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Stochastic Calculus for Finance II
Chapter 1
財金所 潘政宏
1.1 Probability Space
The set of all sample points is called sample
space, say Ω .
Def1.1.1:Let F be a collection of subsets of
nonempty set Ω. We say that F is a
-algebra if
(1) the empty set  ∈ F.
c
(2) A ∈ F, then A ∈ F.

(3) A1,A2,A3,… ∈ F, then n 1 An ∈ F.
1.1 Probability Space
(Ω, F) is called a measurable space.
Def1.1.2:Given (Ω, F) , a probability measure is a
real-valued function P: F →[0,1] and
(1) ∀A ∈ F, P(A) ∈[0,1].
(2) A1,A2,A3,… is a sequence of disjoint sets
in F, then P  A    P A 

 i 1

i

i 1
i
(3) P(Ω)=1
(Ω, F ,P) is called a probability space.
1.2 Random variables
Def1.2.1: Let (Ω, F ,P) be a probability space.
X : Ω →R is a random variable if
-1
B F
X
∀B ∈ B,
(Ω, F)
(R, B)
X
X-1 (B)
∈F
B
∈B
1.6 Change of Measure
Thm1.6.1:
Let (Ω, F, P) be a probability space and let Z be an almost surely
nonnegative random variable with EZ=1. For A ∈ F define
Then is a probability measure. Furthermore, if X is a nonnegative
random variable, then
If Z is almost surely strictly positive, we also have
for every nonnegative random variable Y.
1.6 Change of Measure
d P( )
P( A)   d P( )  
dP( )   Z ( )dP( )
A
A dP( )
A
EX   X ( )d P( )   X ( )


d P( )
dP( )   X () Z ()dP()  E[ XZ ]

dP( )
dP( )
1
Y
EY   Y ( )dP( )   Y ( )
d P( )   Y ( )
d P( )  E[ ]



Z ( )
Z
d P( )
1.6 Change of Measure
Def1.6.3:
Let Ω be a nonempty set and F a σ-algebra of
subsets of Ω. Two probability measures P and
on (Ω, F) are said to be equivalent if they agree
which sets in F have probability zero.
i.e.
1.6 Change of Measure
Example:
Ω={1,2,3,4}
F= ({1},{2},{3},{4})
1
1
1
P({1})  , P({2})  , P({3})  , P({4})  0
2
3
6
1
1
1
P({1})  , P({2})  , P({3})  , P({4})  0
4
2
2
1
1
1
P({1})  , P({2})  , P({3})  0, P({4}) 
4
2
2
1.6 Change of Measure
Thm1.6.7 (Radon-Nikodým):
Let P and be equivalent probability measures defined on
(Ω, F). Then there exists an almost surely positive random
variable Z such that EZ=1 and
1.6 Change of Measure
EX:X~N(0,1) with respect to P.
Y=X+θ~N(θ,1) with respect to P.
Find such that Y~N(0,1) with respect to
y
Sol:Let

1
2
.
2
2
dP
Z 

dP
e

1
e
2
dy
( y  )
2
e
2
 y 
2
2
dy
then Z>0 and
EZ   e

 y 
2
2

dP   e

 y 
2
2
1
e
2

( y  )2
2
dy  


1
e
2

y2
2
dy  1
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