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8.3 – Geometric Sequences A sequence is geometric if consecutive numbers always have the same common ratio (r). Ex: 2, 4, 8, 16, 32, … Ex: 2 4 8 16 , , , , ... 3 9 27 81 has a common ratio of 2 4 8 16 32 2 4 8 16 has a common ratio of -2/3 Geometric sequences are always of the form an = a1 rn-1 r = the common ratio The sequence will be a1, a1r, a1r2, a1r3, …, a1rn-1 Ex: Find a formula for the following geometric sequence, then find a9: 5, 15, 45, … an = a1rn-1 = 5(3)n-1 a9 = 5(3)8 = 32805 Ex: If the 4th term of a geometric sequence is 125 and the 10th term is 125/64, find the 14th term. Think about the relationship between the 10th and 4th terms! a10 a4 r 6 125 a14 1024 125 125r 6 64 1 r6 64 125 1 a14 64 2 4 1 r 2 a14 a10 r 4 The sum of a finite geometric sequence is: a1 1 rn Sn a1 1 r st = 1 term being summed n = # terms being summed r = common ratio 8 Ex: Find the sum: k 3(0.6) k 1 n = 8, a1 = 3(0.6) = 1.8, r = 0.6 1 0.68 Sn 1.8 1.8(2.458) 4.424 1 0.6 The sum of an infinite geometric sequence is: a1 S 1 r If |r| ≥ 1 , the series does not have a sum. Ex: Find the sum: k 1 4(0.6) k 1 Use the infinite sum formula! To find a1, evaluate for k = 1 a1 = 4(0.6)1-1 = 4(0.6)0 = 4 4 4 10 Sn 1 0.6 0.4 Find the sum of the series. 1 16 2 n1 10 0% 0% 0% 0% 0% 19 .9 8 5. .0 3 4. 15 .9 8 3. 31 .9 7 2. 16 31.97 15.98 .03 19.98 16 1. n 0% 11 74 5. 0% 0% 0% 0% 70 96 4. 21 41 3. 66 70 2. 1174 1249 6670 2141 7096 12 49 1. The population in Dodge City decreases by 6% yearly. If the population was 1600 in 1875, what was the population in 1880? Find the sum of the series. 4 2 n 0 5 12 0% 0% 0% 0% 0% 9. 31 5. 9. 45 4. 7. 45 3. 7. 56 2. 10 7.56 7.45 9.45 9.31 10 1. n Find the sum of the infinite series. 9 4 , 3, 2, , ... 2 3 0% 0% 1/ 2 0% 13 0% 9 0% 1/ 2 5. 1 4. -9 3. 5/ 6 2. 65/6 -9 3/2 9 27/2 10 1.