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1 The Normal Curve and the 68-95-99.7 Rule The normal curve (also known as the bell curve) is the most common distribution of data. The normal curve is completely determined by two parameters: mean and standard deviation. The normal curve is symmetric about the mean which is also the median and the mode. Most data is clumped in close to the mean. Figure 1: A very plain normal curve The normal distribution is important since it tells us the amount of data that falls in particular intervals relative to the mean and standard deviation. The notation N ( ; ) states that the data has a normal distribution with mean and a standard deviation . We use the notation mean and standard deviation to indicate that these are de…ning parameters for a statistical distribution rather than statistical values we computed from a sample. For example, N (35; 2:3) indicates a normal distribution with a mean of 35 and a standard deviation of 2.3. Theorem 1 The 68-95-99.7 Rule: In every normal distribution with mean and standard deviation , approximately 68% of the data falls within one standard deviation of the mean. Approximately 95% of the data falls within two standard deviations of the mean. And …nally, approximately 99.7% (almost everything) of the data falls within three standard deviations of the mean. This rule is illustrated in Figure 2 from http://www.answers.com/topic/normaldistribution. 1 In the normal distribution all measurements are computed in terms of distance from the mean relative to standard deviation. Think of standard deviation as a ruler. Professor Russell and Professor Johnson teach di¤erent sections of Elementary Statistics. On test 1, Professor Russell’s class had an average score of 10 points with a standard deviation of 2 points. Assume these test grades follow a normal distribution and explain. Problem 1 What grades comprise the central 68% of the students in Professor Russell’s class? Problem 2 What grades comprise the central 99.7% of the students in Professor Johnson’s class? Remark 2 A useful tool to convert to standardized units is the z-score z= x : Proper use of a z-score permits the comparison of apples to oranges! Problem 3 On test 1, Professor Johnson’s class had an average score of 150 points with a standard deviation of 10 points. Whose score is better: Mary in Russell’s class with a score of 14 or Dawn in Johnson’s class with a score of 160? Problem 4 In Professor Russell’s class, Alan’s test score is z = 1:5. What is Alan’s original test score? Problem 5 In Professor Johnson’s class, what percentage of students scored between 140 and 160 points? 2 Problem 6 In Professor Johnson’s class, what percentage of students scored more than 160 points? Problem 7 If Professor Johnson’s class has 200 students, approximately how many scored between 150 and 170 points? At a particular high school, the average time to run a mile on the track team is 6.7 minutes with a standard deviation of 1.02 minutes. On the archery team the average number of bulls-eyes (out of 20 attempts) is 7.8 with a standard deviation of 3.3. Problem 8 David runs track while Jenny is an archer. If David runs a mile in 5 minutes and Jenny hits 12 bulls-eyes, whose performance is more outstanding? Assume this data follows a normal distribution. Problem 9 Is the sign on the z-score important? Explain. Problem 10 The number of bulls-eyes made by Jack has a z-score of z = 1:15: How many times did Jack hit the bulls-eye? De…nition 3 An observation that is unusually large or small, relative to the other values in a data set, is called an outlier. An observation is considered to be unusually large or small if the absolute value of its z-score is at least 2. Problem 11 Is it unusual to be on the track team and run a 10 minute mile? Problem 12 Is the score 4 unusual on test 1 in Professor Russell’s class? 3 Problem 13 What is the minimum number of bulls-eyes one can hit and have an unusually good performance? The 68-95-99.7 rule is a nice beginning from which to explore the normal curve. It would be greatly limiting if we could only work with z-scores of 1; 2 and 3. Fortunately, technology allows us to work with any z-score in any normal distribution. 2 Exercises 1. The average score in a game of Scrabble is 141 points with a standard deviation of 7 points. i. what scores represent the central 68% of all Scrabble scores? ii. what scores represent the central 95% of all Scrabble scores? iii. what percentage of scores fall between 148 and 155? iv. is 160 an unusual score? v. Tony has a z-score of z = 2:57 representing the last Scrabble game he played. What is Tony’s raw score? 2. When opponents of the Durham Bulls baseball team face pitcher, Ebby Calvin "Nuke" LaLoosh, they average 15 hits per game with a standard deviation of 3 hits and this data follows a normal distribution. i. In a particular game, the Winston-Salem Spirits get 10 hits against Nuke. Find the corresponding z-score. ii. Find the percentage of games where opponents get more than 21 hits. iii. Is unusual for Nuke to throw a no-hitter1 ? Carefully explain your answer and include all supporting computations.. 3. Find all salary outliers for the ’97-’98 Chicago Bulls. standard deviation of these salaries is $8,182,474.38. 1 In Note that the baseball, a pitcher throws a no-hitter if the opposing batters never get a hit. 4 Player Salary 1 Michael Jordan $33,140,000 2 Ron Harper $4,560,000 3 Toni Kukoc $4,560,000 4 Dennis Rodman $4,500,000 5 Luc Longley $3,184,900 6 Scottie Pippen $2,775,000 7 Bill Wennington $1,800,000 8 Scott Burrell $1,430,000 9 Randy Brown $1,260,000 10 Robert Parish $1,150,000 11 Jason Caffey $850,920 12 Steve Kerr $750,000 13 Keith Booth $597,600 14 Jud Buechler $500,000 15 Joe Kleine $272,250 Average $4,088,711 Median $1,430,000 Chicago Bulls Salaries 1997-1998 Season 4. Find all salary outliers for the ’10-’11 Atlanta Hawks. Atlanta Hawks Salaries 2010-2011 Season Clark: Read section 2.1. Do problem 6. 5