Download Practice Test 2

COMPASS Algebra
Practice Test 2
• This practice test is 10 items long.
• Record your responses on a sheet of
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• The correct answers are on the slide
after the last question.
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1.
Which of these is the product
of (x + 2y) and (2x – 3y) ?
A.
 B.
 C.
 D.
 E.
2x2 – 7xy + 6y2
2x2 + xy – 6y2
2x2 + 7xy + 6y2
2x2 – xy – 6y2
2x2 + 7xy – 6y2
2. For all a  o
 A. 4a b
2
B.
 C.
4
b
ab
4a
 D.
b
4
 E.
1
4a 2 b
4a
and b  0,
?
1
ab
3.
This is a graph of which equation?
 A.
2
y   x6
3
B.
3
y  x6
2
 C.
2
y  x6
3
8
6
4
2
 D.
 E.
3
y   x6
2
5
-2
3
y   x6
2
4. What is the solution to the
equation 3(x + 2) – 2(2x + 2) = -2 ?
 A. -12
 B. 10
 C. -4
 D. 4
 E. 12
5. In the Cartesian plane what is the distance
between the points (4, 2 13 ) and (2, 13 ) ?
 A.
6  13
 B.
9 13
 C.
75
 D.
49
 E.
7
6. Simplify: 25
 A.
1
15
 B.
1
75
 C. -375
 D.
1
125
 E. -125
3
2
7. What is the distance from point A to
point B?
A.
2
8
B
 B. 34
 C. 2 2
A
-2
 D.
34
 E.
75
8. For all x ≠ 0 and y ≠ 0,
A.
x5
y4
 B.
y8
x 10
 C.
 D.
 E.
x2 y2
x 10
y8
1
x2 y2
4
3
x y
x 6 y 5
9.
For all x, y, and z,
A. x5y4z2
 B. x6y4z2
 C. x9y4z2
 D. x5y4z3
 E. 2x3y2z
3
2
2
(x y z)
10. If y  2 x
then y  ?
A. 45
B. 64
 C. 30
 D. 9
 E. 15
2
 5 x  12 and
,
x  3
Answers
Algebra Practice Test 2
1.
2.
3.
4.
5.
B
A
D
D
E
6. D
7. D
8. B
9. B
10.A
1.
Which of these is the product
of (x + 2y) and (2x – 3y) ?
A. 2x2 – 7xy + 6y2
 B. 2x2 + xy – 6y2
 C. 2x2 + 7xy + 6y2
 D. 2x2 – xy – 6y2
 E. 2x2 + 7xy – 6y2
( x  2 y )( 2 x  3 y )
2x  3 xy  4 xy  6 y
2
2 x  xy  6 y
2
2
2
2. For all a  o
 A. 4a b
2
B.
 C.
 D.
 E.
4
b
ab
4a
b
4
1
4a 2 b
4a
and b  0,
?
1
ab
Multiply by the reciprocal of the divisor
4a ab
4a
1


 4a 

1
1 1
ab
ab
2
4a b
2
 4a b
1
Recall y = mx +b
3.
This line has a negative, downward slope.
This eliminates B and C.
This is a graph of which equation?
 A.
2
y   x6
3
B.
3
y  x6
2
 C.
2
y  x6
3
The y-intercept is +6
This eliminates E.
8
6
4
2
 D.
 E.
3
y   x6
2
3
y   x6
2
5
-2
The slope is down 3 over 2.
This eliminates A.
4. What is the solution to the
equation 3(x + 2) – 2(2x + 2) = -2 ?
 A. -12
 B. 10
 C. -4
 D. 4
 E. 12
3( x  2)  2(2 x  2)  2
3x  6  4x  4  2
 x  2  2
2 2
 x  4
x4
5. In the Cartesian plane what is the distance
between the points (4, 2 13 ) and (2, 13 ) ?
 A.
6  13
Recall the distance formula.
d  ( x2  x1 )  ( y2  y1 )
2
2
 B.
9 13
2
2
d  ((2)  (4))  ( 13  2 13)
 C.
75
 D.
49
 E.
7
d  (6)  ( 13)  36  13
2
d  49  7
2
6. Simplify: 25
 A.
1
15
 B.
1
75
 C. -375
 D.
1
125
 E. -125
3
2
Negative Exponent
Take the reciprocal.
Rewrite rational exponent
with radical notation
3
2
25 
1
25
3

2
1

125
1
1
 3
3
5
25
 
2
Simplify
7. What is the distance from point A to
point B? Use the Pythagorean Theorem
A.
8
 B. 34
 C. 2 2
 D.
34
 E.
75
a b  c
2
2
2
3 5  c
2
9  25  c
2
34  c
34  c
2
2
2
2
B
3
A
-2
5
8. For all x ≠ 0 and y ≠ 0,
A.
 B.
 C.
 D.
 E.
x5
y4
y8
x 10
x2 y2
x 10
y8
1
x2 y2
4
3
x y
x 6 y 5
Let each negative exponent cross the
division bar and it becomes positive.
8
5 3
y
x 4 y 3
y y
 6 4  10
6 5
x
x y
x x
9.
For all x, y, and z,
o A.
o B.
o C.
o D.
o E.
x5y4z2
x6y4z2
x9y4z2
x5y4z3
2x3y2z
3
2
2
(x y z)
(x3y2z)2
(x3y2z)(x3y2z)
When multiplying like bases,
add the exponents.
x3 + 3 y2 + 2 z1 + 1
x6 y 4 z 2
10. If y  2 x  5x  12 and x  3,
then y  ?
2
y  2 x  5 x  12
A. 45
2
y  2(3)  5(3)  12
B. 64
y  2(9)  5(3)  12
y  18  15  12
 C. 30
y  45
2
 D. 9
 E. 15