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C Name: ___________________ Period: _____________ 1. How is the scientific definition of work different from the everyday definition? Everyday – something to earn money Scientific – Force applied to moving an object 2. Describe a situation where a force is applied but no work is done. Pushing on a wall that doesn’t move. No motion = no work 3. A force of 10,000 N is applied to a stationary wall. How much work is performed? W=F*d W = 10,000 N * 0 m W=0J 4. A 950 N skydiver jumps from an altitude of 3000 m. What is the total work performed on the skydiver? W=F*d W = 950 N * 3000 m W = 2,850,000 J 5. You are walking from your math class to your science class. You are carrying books that weigh 20 N (↑). You walk 45 m (→) down the hall, climb 15 m up (↑) the stairs, and then walk another 30 m (→) to your science class. What is the total work performed on your books? * Remember that the movement needs to be in the same direction as the force applied. W=F*d W = 20 N * 15 m W = 300 J 6. How much work is done by a crane that lowers 1000 N of material a distance of 150 m? W=F*d W = 1000 N * 150 m W = 150,000 J 7. A bulldozer performs 80,000 J of work pushing dirt a distance of 16 m. What is the force of the dirt? F=W/d F = 80,000 J / 16 m F = 5000 N 8. A woman lifts a 35 kg child a distance of 1.5 m (↑) and carries her forward for 6.5 m (→). a. How much work does the woman do in lifting the child? Wt = m * g Wt = 35 kg * 9.8 m/s/s = 343 N W=Fxd W = 343 N x 1.5 m W = 514.5 J b. How much work does the child do? Child applies no force that causes movement 0J 9. An ant does 1 J of work in dragging a 0.0020 N grain of sugar. How far does the ant drag the sugar? d=W/F d = 1 J / .002 N d = 500 m 10. How much work is done when a 1 kg mass is raised a vertical distance of 1 m? F=m*g F = 1 kg * 9.8 m/s/s = 9.8 N W=Fxd W = 9.8 N x 1 m W = 9.8 J 11. Mrs. Smith pushed a 10 kg desk across a floor for a distance of 5 m (→). She exerted a horizontal force of 20 N (→). How much work did she do? W=F*d W = 20 N * 5 m W = 100 J 12. A weight lifter lifts a 150 kg barbell above his head from the floor to a height of 2 m. He holds the barbell there for 5 seconds. How much work does he do during that 5 second interval? W=F*d d=0 0J