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ALGORITHMS CONDITIONAL BRANCH CONTROL STRUCTURE 1 Definition of a Block But first, let us define a block as group of related instructions – A block can contain one or as many instructions as we want BLOCK 1 -------------------Get X Get Y Let Z = X + Y Give Z BLOCK 2 ---------------------Let X = A + B * C /D 2 Test Blocks By adding a test at the beginning of a block, we let the results of the test determine which block of instructions will be executed TEST True Block ---------------------Do these Instructions if Test is True False Block ----------------------Do these Instructions if the Test is False 3 What is a Test? The test used in a conditional branching control structure contains a variable or expression that evaluates to either True or False 4 Logical Operators in a Test Expression = Equal To < Less Than > Greater Than <= Less Than or Equal To >= Greater Than or Equal To <> Not Equal To (Greater Than or Less Than) 5 Examples of Tests TEST (3 + 2) = (7 – 2) 5 <> (8 – 3) ((7*2)-3) < 12 ((9/3)*2)<=6 (25-(3*5))>10 23>= (12*2) LOGICAL VALUE True False True True False False 6 Logical Tests In practice, tests contain variables and expressions, not numbers Suppose that X, Y and Z are 3, 5, 8 respectively Test Logical Value (X + Y) = (Z – 1) False X=3 True (X > Y) False 7 Test Block (syntax and interpretation) Syntax if (Test) Block1 if (Test) Block1 else Block2 Interpretation If Test is evaluated to true Block1 is executed, else Block2 is executed. The else is optionnal. Note that the indentation is important. It determines the beginning and the end of each block. 8 Algorithm 2.1 Write an algorithm to compute the absolute value of a number. – Name: ABSOLUTE – Givens: Number • Change: None – Results: Value – Intermediates: None – Definition: Value := ABSOLUTE (Number) – ----------------------– Method • Get Number • If (Number >= 0) Let Value = Number • If (Number < 0) Let Value = (-1) * Number • Give Value 9 Else It is redundant to do the test twice as in IF (X > 0) Do this IF (X <= 0) Do that The test should be written as If (X > 0) Do this Else (or Otherwise) Do that 10 Algorithm 2.1 (b) Write an algorithm to compute the absolute value of a number using only one test – Name: ABSOLUTE – Givens: Number • Change:None – Results: Value – Intermediates: None – Definition: Value := ABSOLUTE (Number) – ----------------------– Method • Get Number If (Number >= 0) Let Value = Number Else Let Value = (-1) * Number • Give Value 11 Algorithm 2.2 Write an algorithm which finds the largest of three given numbers General Concept – Keep track of “Biggest so Far” • • • • Look at the first two numbers Store the larger of the two numbers in “Biggest so Far” Compare “Biggest so Far” with the third number If the third number is larger, then store it in “Biggest so Far” 12 Algorithm 2.2 Write an algorithm which finds the largest of three given numbers Name: BIG3 Givens: N1, N2, N3 Change:None Results:Largest Intermediates: None Definition: Largest := BIG3(N1,N2,N3) Method -----------------Get N1 Get N2 Get N3 If (N1 > N2) Let Largest = N1 Else Let Largest = N2 If (N3 > Largest) Let Largest = N3 Give Largest 13 Trace 2.1 Trace Algorithm 2.2 with the values 8, 12, 7 (1) Get N1 (2) Get N2 (3) Get N3 (4) If (N1 > N2) (5) Let Largest = N1 (6) Else (7) Let Largest = N2 LN N1 N2 N3 1 8 2 12 3 7 4 7 8 10 Output 12 Largest Test (8>12) 12 (7>12) (8) If (N3 > Largest) (9) Let Largest = N3 (10) Give Largest 14 Algorithm 2.3 Write an algorithm which, when given an ordered list X1, X2, & X3, modifies the list so that the values are in ascending order General Concept • Look at the first two numbers, X1 and X2. If X1 is larger than X2, swap them (remember the swap algorithm? Algorithm 1.7) • Look at X2 and X3. If X2 is larger than X3, swap them – This will put the largest number in the X3 position – X2 may have changed, so we have to look at X1 again • Look again at X1 and X2. If X1 is larger than X2, swap them – Now the list is in non-decreasing order 15 Algorithm 2.3 Write an algorithm which, given an ordered list X1, X2 & X3, modifies it so that the values are in ascending – Method order – Name: SORT3 – Givens: X1,X2,X3 • Change: X1,X2,X3 – Results: None – Intermediates: Temp – Definition: SORT3(X1,X2,X3) – ---------------• Get X1, X2, X3 • If (X1 > X2) Let Temp = X1 Let X1 = X2 Let X2 = Temp • If (X2 > X3) Let Temp = X2 Let X2 = X3 Let X3 = Temp • If (X1 > X2) Let Temp = X1 Let X1 = X2 Let X2 = Temp • Give X1, X2, X3 16 Trace 2.2 Trace algorithm 2.3 with list X having values 3, 8 and 2 respectively (1) Get X (2) If (X1 > X2) (3) Let Temp = X1 (4) Let X1 = X2 (5) Let X2 = Temp (6) If (X2 > X3) (7) Let Temp = X2 (8) Let X2 = X3 (9) Let X3 = Temp (10) If (X1 > X2) (11) Let Temp = X1 (12) Let X1 = X2 (13) Let X2 = Temp (14) Give X LN 1 X TEMP TEST (3,8,2) 2 (3 > 8) 6 (8 > 2) 7 8 8 (3,2,2) 9 (3,2,8) 10 (3 > 2) 11 3 12 (2,2,8) 13 (2,3,8) 14 Output (2,3,8) 17 Multiple Tests Sometimes we need to perform multiple related tests – For example, in assigning grades, a student can receive A+, A, A-….E, F We can add an ELSE IF clause for multiple test results IF (Test 1) Execute block for Test 1 Else IF (Test 2) Execute block for Test 2 Else Execute block for Else 18 Algorithm 2.4 Write an algorithm which calculates the amount of money to charge for a ticket. The amount varies with the age of the individual. The charge for a person less than 16 is $7. The charge for a person over age 65 is $5 The charge is $10 for everyone else Name: FARE Givens: Age Change: None Results: Price Intermediates: None Definition: Price := FARE(Age) Method --------------------Get Age If (Age < 16) Let Price = $7 Else If (Age > 65) Let Price = $5 Else Let Price = $10 Give Price 19 Trace 2.3 Trace algorithm 2.4 with the given age 35 (1) Get Age (2) If (Age < 16) (3) Let Price = (4) Else If (Age > (5) Let Price = (6) Else (7) Let Price = (8) Give Price LN Age 1 35 Price Test $7 65) $5 2 (35<16) 4 (35>65) $10 7 $10 8 Output $10 20 Algorithm 2.5 Given an employee’s eligible medical expenses for a calendar year, write an algorithm which computes the amount of reimbursement from group medical insurance. The insurance does not cover the first $100 of medical expenses. It pays 90% of the remaining amount in the first $2000 of expenses and 100% of any additional expenses. يتكفل. األولى من النفقات الطبية100 ال يغطي التأمين مبلغ.خوارزمية لحساب تعويض التأمين الصحي .2000 للمبالغ األكبر من100% المدفوعة ويعوض2000 من المبلغ المتبقي لغاية90% 21 Algorithm 2.5 Name: MEDICAL Givens: Expense Change: None Results: Refund Intermediates: LL (Constant 100) UL (Constant 2000) Definition: Refund := MEDICAL(Expense) Method --------------------Set LL = 100 Set UL = 2,000 Get Expense If (Expense < LL) Let Refund = 0 Else If (Expense < UL) Let Refund = 90% (Expense-LL) Else Let Refund = 90% (UL-LL) + 100% (Expense - UL) Give Refund 22 Trace 2.4 Trace Algorithm 2.5 for $3,000 worth of expenses ( 1) Set LL = 100 ( 2) Set UL = 2,000 ( 3) Get Expense LN UL LL Exp Refund Test 1,2 100 2K 3 3000 4 (3K<100) 6 (3K<2K) 9 2,710 10 Output 2,710 ( 4) If (Expense < 100) ( 5) Let Refund = 0 ( 6) Else If (Expense < 2,000) ( 7) Let Refund = 90% (Expense-100) ( 8) Else ( 9) Let Refund = 90% (1,900) + 100% (Expense - 2,000) 23 (10) Give Refund Additional Material 24 Flow Charts 25 Flow Charts Logic is implemented with a Diamond Symbol There are two exits, which should be labeled Y/N or T/F The two paths need to join before the end of the flowchart 26 Start ABSOLUTE Algorithm 2.1(a) Name: ABSOLUTE Givens: Number Change: None Results: Value Intermediates: None Definition: Value := ABSOLUTE (Number) Get Number N If (Number >= 0) Y Let Value = Number N If (Number < 0) Y Let Value = (-1) * Number Give Value Finish ABSOLUTE 27 Algorithm 2.1(b) Start ABSOLUTE Get Number Name: ABSOLUTE Givens: Number Change: None Results: Value Intermediates: None Definition: Value := ABSOLUTE (Number) If (Number >= 0) N Y Let Value = Number Let Value = (-1) * Number Give Value Finish ABSOLUTE 28 Start BIG3 Algorithm 2.2 Name: BIG3 Givens: N1, N2, N3 Change:None Results:Largest Intermediates: None Definition: Largest := BIG3(N1,N2,N3) Get N1 Get N2 Get N3 N If (N1 > N2) Y Let Largest = N1 If (N3 > Largest) Let Largest = N2 N Y Let Largest = N3 Give Largest Finish BIG3 29 Start SORT3 Algorithm 2.3 Get X1 Get X2 Get X3 If (X1 > X2) Name: SORT3 Givens: X1,X2,X3 Change: X1,X2,X3 Results: None Intermediates: Temp Definition: SORT3(X1,X2,X3) N Y Let Temp = X1 Let X1 = X2 Let X2 = Temp If (X2 > X3) N Y Let Temp = X2 Let X2 = X3 Let X3 = Temp If (X1 > X2) N Y Let Temp = X1 Let X1 = X2 Let X2 = Temp Give X1 Give X2 Give X3 30 Finish SORT3 Algorithm 2.4 Name: FARE Givens: Age Change: None Results: Price Intermediates: None Definition: Price := FARE(Age) Start FARE Get Age N If (Age < 16) Y Let Price = $7 N If (Age > 65) Y Let Price = 5$ Let Price = $10 Give Price Finish FARE 31 Algorithm 2.5 Name: MEDICAL Givens: Expense Change: None Results: Refund Intermediates: LL (Constant 100) UL (Constant 2,000) Definition: Refund := MEDICAL(Expense) Start MEDICAL Set LL = 100 Set UL = 2,000 Get Expense N If (Expense < LL ) Y N If (Expense < UL ) Y Let Refund = 0 Let Refund = 90%(Expense – LL ) Let Refund = 90%(UL-LL)+ 100%(Expense – UL ) Give Refund Finish MEDICAL 32 Homework 33 For each of the following questions: Develop an algorithm Trace the algorithm with suitable data •Write an algorithm to reverse the digits in a three digit number and then add that number to 500. For example, 468 becomes 864. When added to 500, the result is 1364. •Write an algorithm to get the names and ages of two people. Return the name of the person who is older (in the format “x is older than y”, where x and y are the names of the two people), unless the two people are the same age, in which case, return the message “x is the same age as y”. 34 An automotive sales representative’s commission is calculated as a percentage of the sale: – 8% of the first $5,000.00 of the sale price – 10% on the remainder of the sale price, if the remainder is less than or equal to $80,000.00 or – 12.5% on the remainder, if the remainder is more than $80,000.00 Develop an algorithm that will accept the sale price of the automobile and calculate and display the sales representative’s commission. 35