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Transcript
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Amplifier Transfer
Function
Note that the ideal amplifier transfer function:
oc
vout
(t ) = Avo vi (t )
is an equation of a line (with slope = Avo and y -intercept = 0).
vout
Avo < 0
Avo > 0
vin
This ideal transfer function implies that the output voltage can
be very large, provided that the gain Avo and the input voltage
vin are large.
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However, we find in a “real” amplifier that there are limits on
how large the output voltage can become. The transfer function
of an amplifier is more accurately expressed as:
L



vout (t )  Avo vin (t )


L
vin (t )  Lin
Lin  vin (t )  Lin
vin (t )  Lin
This expression is shown graphically as:
vout
L+
L-in =
LAvo
L+in
Avo
L-
=
L+
Avo
vin
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* This expression (and graph) shows that electronic amplifiers
have a maximum and minimum output voltage (L+ and L-).
* If the input voltage is either too large or too small (too
negative), then the amplifier output voltage will be equal to
either L+ or L- .
* If vout = L+ or vout =L- , we say the amplifier is in saturation (or
compression).
Amplifier saturation occurs when the input voltage is greater
than:
L
vin > + B L+in
Avo
or when the input voltage is less than:
vin 
L
Avo
Lin
Often, we find that these voltage limits are symmetric, i.e.:
L  L
and
Lin  Lin
For example, the output limits of an amplifier might be L+ = 15 V
and L- = -15 V.
However, we find that these limits are also often asymmetric
(e.g., L+ = +15 V and L- = +5 V).
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Q: Why do we care if an
amplifier saturates? Does it
cause any problems, or
otherwise result in
performance degradation??
A: Absolutely! If an amplifier
saturates—even momentarily—
the unavoidable result will be a
distorted output signal.
For example, consider a case where the input to an amplifier is a
triangle wave:
vin (t)
Lin
t
Lin
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Since Lin  vin (t )  Lin for all time t, the output signal will be
within the limits L+ and L- for all time t, and thus the amplifier
output will be vout (t) = Avo vin (t):
vout (t)
L
t
L
Consider now the case where the input signal is much larger,
such that vin (t )  Lin and vin (t )  Lin for some time t (e.g., the
input triangle wave exceeds the voltage limits Lin and Lin some
of the time):
vin (t)
Lin
t
Lin
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This is precisely the situation
about which I earlier
expressed caution. We now
must experience the palpable
agony of signal distortion!
vout (t)
L
t
L
Note that this output signal is not a triangle wave!
For time t where vin (t )  Lin and vin (t )  Lin , the value Avo vin (t ) is
greater than L+ and less than L-, respectively. Thus, the output
voltage is limited to vout (t )  L and vout (t )  L for these times.
As a result, we find that output vout (t ) does not equal Avo vin (t ) —
the output signal is distorted!
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In reality, the saturation voltages L , L , Lin , and Lin are not so
precisely defined. The transition from the linear amplifier
region to the saturation region is gradual, and cannot be
unambiguously defined at a precise point.
vout
L+
L 
in
L
Avo
L 
in
L
vin
Avo
Avo
Lvout(t)
L
t
L