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Geometry 300 Parallelogram Packet Name________________________ Date__________________ 1. In Parallelogram ABCD, A = 9y – 12, B = –26x + 16, C = 60. Find the value of x and y. B A C D 2. In Parallelogram EFGH, the ratio of E to F is 1:11. Find the measure of G and H. 3. Quadrilateral IJKL has coordinates I(–2, 6) , J(2, 11) , K(3, 8) and L(–1, 3). Show using slopes that IJKL is a parallelogram. Geometry 300 Name________________________ Parallelogram Packet Date__________________ 4. Draw parallelogram STAR with diagonals SA and TR . Find the value of x and y if mTSA = 2x, mSTR = 18, mSRT = 62, mRSA = 3y + 5, and mSAT = 50. 5. Given: Parallelogram WSTV WS = x + 5 WV = x + 9 VT = 2x + 1 Find the perimeter of WSTV 6. W S Given: Parallelogram ABCD m A = x m D = 3x - 4 Find: mD and mC V T D A C B 7. In parallelogram PWJL. PW= 5x – 3, LJ = 3x + 3. Find x and the measures of sides PW and LJ. Geometry 300 Parallelogram Packet Name________________________ Date__________________ 8. Use the parallelogram at the right to solve each problem. E b) If mBAC = 45°, find mACD c) If mBEA = 135°, find mAED C d) If mABC = 50°, find mBCD e) If AB = 5x – 3 and CD = 2x + 9, find AB f) If mDAB = 2x – 10 and mADC = 3x, find mDAB g) If mBAD = 3x – 12 and mBCD = x + 40, find mBAD h) If CE = 2x + 7 and EA = 3x – 4, Find CA i) If BD = 4y – 22 and ED = y + 5, Find BE A B a) If mBCD = 125°, find mBAD D Geometry 300 Parallelogram Packet Name________________________ Date__________________ 9. Solve for x and y in the parallelogram below. 3x 2 y 114° 4x 6 y 66° 10. Solve for the value(s) of x in the parallelogram below and then determine the possible side lengths. 2 x 2 3x 20 x 2 2 x 32 11. Solve for the value(s) of x in the parallelogram below and then determine the possible diagonal lengths. 5x 4 x2 2 Geometry 300 Name________________________ Parallelogram Packet Date__________________ 12. In Parallelogram ABCD, mA = 4 x 11y 10 , mB = 3 y 2 x , mC = 2 y 15 x 5 and mD = 2 x 3 y . Find the values of x and y and mA and mB. B A C D 13. Quadrilateral ABCD has the following vertices A(-5,-9) , B(6, -11) , C(7, -7) and D(-4, -5) Prove using the distance formula that this is a parallelogram. In other words, show that the opposite sides of the quadrilateral are equal and therefore must be a parallelogram.