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Transcript
Name: _______________________________ Period ______
Section 7.1 – Polynomial Degree and Finite Differences
Big Idea: You have studied several kinds of nonlinear sequences and functions, which do not have a
common difference or a constant slope. In this lesson you will discover that even nonlinear
sequences sometimes have a special pattern in their differences. These patterns are often
described by polynomials.

A Polynomial in one variable is any expression that can be written in the form:
an x n  an 1 x n 1  ...  a1 x1  a0
Where x is a variable, the exponents are nonnegative integers, the coefficients are real
numbers, and an  0 . The degree of a polynomial is the power of the term that has the
greatest exponent.
Examples of Polynomials:
A.
y4
B.
y
C.
y  4( x  3)2  2
D.
y  x3  2
E.
F.
 5 x  4
3
y  3x3  6 x 2  x 7  x  1
4
y  3x50
What is the
degree?
Examples that are NOT
polynomials
y  4(3) x
y  3 x 1  2
y  4log 2 ( x)
1
y   x 1
x
y  3x
2
5
y 3 x2 7
If the degrees of the terms of a polynomial decrease from left to right, the polynomial is in
standard form. Which polynomials above are in standard form? _________________
Example 1:
y  x3  9 x 2  26 x  24
Degree = __________ Coefficients = ___________ Constant Term = _____________
Is the polynomial in standard form?
Example 2:
y  4 x 2  9 x5  26  24 x3
Degree = __________ Coefficients = ___________ Constant Term = _____________
Is the polynomial in standard form?
Example 3:
Circle the equation(s) that represent polynomials. If they are not polynomials say why they are not.
y
y  4 x 2  2 x6  26
y  4x  x
2
1
2
3
x 1
y  x 4  x3  x 2
y  25(4) x
y  3 x 4
Finite Differences: In modeling linear functions, you have already discovered that for x-values that
are evenly spaced, the differences between the corresponding y-values must be the same. With 2ndand 3rd-degree polynomial functions, the differences between the corresponding y-values are not the
same. However, finding the differences between those differences produces an interesting pattern.
1st Degree
y  3x  4
X
Y
2
D1
2nd Degree
3rd Degree
y  2 x2  5x  7
y  0.1x3  x 2  3x  5
x
y
x
y
10
3.7
1.88
-5
-57.5
3
13
3.8
2.88
0
-5
4
16
3.9
3.92
5
-2.5
5
19
4.0
5.00
10
25
6
22
4.1
6.12
15
152.5
7
25
4.2
7.28
20
455
D1
D2
D1
D2
D3
Note that in each case the x-values are spaced equally. You find the first set of differences,
D1 , by
subtracting each y-value from the one after it. You find the second set of differences,
the differences of consecutive
D1
values in the same way.
For the 2nd-degree polynomial function, the
polynomial function, the
D3
D2 , by finding
D2
values are constant, and for the 3rd-degree
values are constant. What do you think will happen with a 4 th or 5th
degree polynomial function?
Analyzing differences to find a polynomial’s degree is called the Finite Differences Method.
Use this method to analyze and solve the problem in Example 4.
Example 4 (see page 379 in your textbook):
Find the polynomial function that models the relationship between the number of sides and the
number of diagonals of a convex polygon. Use the function to find the number of diagonals of a
dodecagon (a 12-sided polygon).
Number of sides
x
3
Number of diagonals
y
0
4
2
5
5
6
9
7
14
8
20
D1
D2
D3
You can stop finding differences when the values of a set of differences are constant.
Model your data using the correct polynomial function: (1) Linear
(2) Quadratic
y  ax 2  bx  c
or
(3) Cubic:
y  ax  b
y  ax3  bx 2  cx  d
Choose points from your table, and substitute the coordinates into your equation to create a
system of three equations in three variables.
Solve the system of equations using substitution method.
Then, substitute the values of the coefficients back into the equation.
Substitute 12 for x to find the number of diagonals in a dodecagon.
You try one: Find the polynomial equation that matches this data.
x
y
4
4
5
4
6
16
7
32
8
52
9
76
D1
D2
D3
You can stop finding differences when the values of a set of differences are constant.
Model your data using the correct polynomial function: (1) Linear
(2) Quadratic
y  ax 2  bx  c
or
(3) Cubic:
y  ax  b
y  ax3  bx 2  cx  d
Choose points from your table, and substitute the coordinates into your equation to create a
system of three equations in three variables.
Solve the system of equations using substitution method.
Then, substitute the values of the coefficients back into the equation.