Phys202_Final_Exam_Spr2007.doc
... IGNORE the sign of your answer and select the correct magnitude from the list. You may not leave prior the then end of the class after all papers are collected. You may only have pencils and a one memory non-programmable calculator with you. Let the index of refraction of glass be 1.5 and water be 1 ...
... IGNORE the sign of your answer and select the correct magnitude from the list. You may not leave prior the then end of the class after all papers are collected. You may only have pencils and a one memory non-programmable calculator with you. Let the index of refraction of glass be 1.5 and water be 1 ...
Electric Fields
... distance without touching (unlike other forces) Very difficult for early scientists to accept Michael Faraday proposed the Electric Field to explain ...
... distance without touching (unlike other forces) Very difficult for early scientists to accept Michael Faraday proposed the Electric Field to explain ...
Midterm Exam 1
... with sun at one focus. The straight line joining the planet and the sun sweeps out equal areas of space in equal amounts of time. What does this tell us about speeds of planets in different parts of their orbits? ...
... with sun at one focus. The straight line joining the planet and the sun sweeps out equal areas of space in equal amounts of time. What does this tell us about speeds of planets in different parts of their orbits? ...
Rotational Motion
... The kinetic energy in a fluid is the same as for any other mass: K = ½ mv2. The change in potential energy is: U = mgh. The work done on a fluid is due to pressure. • Pressure acting on a volume: W = PAx = PV. ...
... The kinetic energy in a fluid is the same as for any other mass: K = ½ mv2. The change in potential energy is: U = mgh. The work done on a fluid is due to pressure. • Pressure acting on a volume: W = PAx = PV. ...
p250t2f03
... (D) trick question, since the force and acceleration must be zero for motion with constant speed is zero. ___ 3. If the orbital distance of the moon from the earth were larger, then (A) the force of attraction between the earth and the moon would be smaller. (B) the centripetal acceleration of the m ...
... (D) trick question, since the force and acceleration must be zero for motion with constant speed is zero. ___ 3. If the orbital distance of the moon from the earth were larger, then (A) the force of attraction between the earth and the moon would be smaller. (B) the centripetal acceleration of the m ...
Magnetic Force Homework
... 7. The magnetic field above has magnitude 3.0 T. For each of the following particles placed in the field, find (a) the force exerted by the magnetic field on the particle, and (b) the acceleration of the particle. Be sure to give magnitude and direction in each case. a) an e- at rest ...
... 7. The magnetic field above has magnitude 3.0 T. For each of the following particles placed in the field, find (a) the force exerted by the magnetic field on the particle, and (b) the acceleration of the particle. Be sure to give magnitude and direction in each case. a) an e- at rest ...
HW 8 Magnetic Force Homework
... 7. The magnetic field above has magnitude 3.0 T. For each of the following particles placed in the field, find (a) the force exerted by the magnetic field on the particle, and (b) the acceleration of the particle. Be sure to give magnitude and direction in each case. a) an e- at rest ...
... 7. The magnetic field above has magnitude 3.0 T. For each of the following particles placed in the field, find (a) the force exerted by the magnetic field on the particle, and (b) the acceleration of the particle. Be sure to give magnitude and direction in each case. a) an e- at rest ...
Force
... An unbalanced force is a force that changes the motion. The book slides and then stops because of In space there is no a resistant force called resistance to cause friction. Friction is friction, so a bowling force that opposes ball would stay in motion. motion ...unless another object got in the wa ...
... An unbalanced force is a force that changes the motion. The book slides and then stops because of In space there is no a resistant force called resistance to cause friction. Friction is friction, so a bowling force that opposes ball would stay in motion. motion ...unless another object got in the wa ...
CH. 6 Sec. 2
... Name ______________________________ Class ___________________ Date __________________ ...
... Name ______________________________ Class ___________________ Date __________________ ...
work
... PEs = ½ kx2 PEs = ½ · 800N/m · (.25m)2 PEs = 100. N·m PEs = 100 J Upon its release, the object reaches maximum velocity as it passes through the relaxed position. What is that velocity? PEs1 + KEs1 = PEs2 + KEs2 100.J + 0J = 0J + 100J KE2 = 100J = ½ mv22 ; m = 15kg v2 = 3.7m/s ...
... PEs = ½ kx2 PEs = ½ · 800N/m · (.25m)2 PEs = 100. N·m PEs = 100 J Upon its release, the object reaches maximum velocity as it passes through the relaxed position. What is that velocity? PEs1 + KEs1 = PEs2 + KEs2 100.J + 0J = 0J + 100J KE2 = 100J = ½ mv22 ; m = 15kg v2 = 3.7m/s ...
PowerPoint
... There’s a lot missing • Everything on a computer is discrete – Positions and velocities are discrete – Time is discrete • Accurate modeling of friction, collisions, constrained motion • Simulating so it is “good enough” ...
... There’s a lot missing • Everything on a computer is discrete – Positions and velocities are discrete – Time is discrete • Accurate modeling of friction, collisions, constrained motion • Simulating so it is “good enough” ...