Accelerated Motion
... Along with acceleration, there are several other terms that describe accelerated motion over time. reference point - point from which all distances and displacements are measured – the origin of the frame of reference coordinates location or position – how far the object is from the reference point ...
... Along with acceleration, there are several other terms that describe accelerated motion over time. reference point - point from which all distances and displacements are measured – the origin of the frame of reference coordinates location or position – how far the object is from the reference point ...
Forces
... Mass is a scalar quantity. It has a magnitude (such as 60 kg), but no direction. Weight is a vector. It has magnitude AND direction. For objects on Earth, it always points straight down toward the center of the Earth. Also, known as the Force of gravity. ...
... Mass is a scalar quantity. It has a magnitude (such as 60 kg), but no direction. Weight is a vector. It has magnitude AND direction. For objects on Earth, it always points straight down toward the center of the Earth. Also, known as the Force of gravity. ...
Angular Momentum (AIS)
... same anywhere on the body, it does not matter which point of rotation we choose for our summation of torques • Best to choose a point that is easiest to solve (The location of one of our unknown forces) ...
... same anywhere on the body, it does not matter which point of rotation we choose for our summation of torques • Best to choose a point that is easiest to solve (The location of one of our unknown forces) ...
1 - RPI
... positive direction to avoid problems with – signs. (What is the direction of acceleration?) 16. Draw a free-body diagram of the pilot. (Hint: The pilot is upside down. What does that imply about the normal force?) 17. Figure out whether the forces you identified are positive or negative in your coor ...
... positive direction to avoid problems with – signs. (What is the direction of acceleration?) 16. Draw a free-body diagram of the pilot. (Hint: The pilot is upside down. What does that imply about the normal force?) 17. Figure out whether the forces you identified are positive or negative in your coor ...
Momemtum/Impulse/ Conservation of Momentum
... Air bags are used in automobiles because they are able to minimize the affect of the force on an object involved in a collision. Air bags accomplish this by extending the time required to stop the momentum of the driver and passenger (bigger t, less F). Without airbags the driver and passenger tend ...
... Air bags are used in automobiles because they are able to minimize the affect of the force on an object involved in a collision. Air bags accomplish this by extending the time required to stop the momentum of the driver and passenger (bigger t, less F). Without airbags the driver and passenger tend ...
Lecture 34
... • They are the same size and shape and (as drawn) have the same orientation. Therefore, they present the same cross-sectional area and experience the same total incident flux of light. • BUT…the black ship absorbs all the momentum from the light, while the silver ship reflects it. Therefore, the sil ...
... • They are the same size and shape and (as drawn) have the same orientation. Therefore, they present the same cross-sectional area and experience the same total incident flux of light. • BUT…the black ship absorbs all the momentum from the light, while the silver ship reflects it. Therefore, the sil ...
PEKA 5
... 1. Arrange the apparatus as shown in the diagram. Compensate for friction. 2. Measure the mass of the trolley using the triple beam balance provided. Record the value. 2. Switch on the ticker timer. Use a 50g slotted weight for a constant force. 3. Release the slotted weight to fall freely to the gr ...
... 1. Arrange the apparatus as shown in the diagram. Compensate for friction. 2. Measure the mass of the trolley using the triple beam balance provided. Record the value. 2. Switch on the ticker timer. Use a 50g slotted weight for a constant force. 3. Release the slotted weight to fall freely to the gr ...
Document
... where the vector g = 9.8 m/s2 in the downward direction, and F = m g. ELECTRIC FIELD is obtained in a similar way: F = k q1 q2/r2 = q1 (k q2/r2) = q1 (E) where the vector E is the electric field caused by q2. The direction of the E field is determined by the direction of the F, or as you noticed in ...
... where the vector g = 9.8 m/s2 in the downward direction, and F = m g. ELECTRIC FIELD is obtained in a similar way: F = k q1 q2/r2 = q1 (k q2/r2) = q1 (E) where the vector E is the electric field caused by q2. The direction of the E field is determined by the direction of the F, or as you noticed in ...
magnetism and electromagnetism
... A force is exerted on a charged particle by a magnetic field only when the particle moves across the field lines. The force vector, F, is related to the cross product of the velocity vector, v, and the magnetic field vector, B, as given by: F = qv × B The cross product is the component of velocity t ...
... A force is exerted on a charged particle by a magnetic field only when the particle moves across the field lines. The force vector, F, is related to the cross product of the velocity vector, v, and the magnetic field vector, B, as given by: F = qv × B The cross product is the component of velocity t ...
Physics 2
... 39. What happens when the ground is hit? 40. What is the equation for weight in terms of gravity? 41. What does the effect of a. Squashing b. Squeezing have on an object? 42. A force applied to an elastic object will result in the objecy doing what? 43. Once a string goes past its limit of proportio ...
... 39. What happens when the ground is hit? 40. What is the equation for weight in terms of gravity? 41. What does the effect of a. Squashing b. Squeezing have on an object? 42. A force applied to an elastic object will result in the objecy doing what? 43. Once a string goes past its limit of proportio ...