A2 Unit G485: Fields, particles and frontiers of physics
... (ii) V = Q/C = 40 × 10−6/(14 × 10−6) = 2.9 V (iii) Q = 10 × 10−6 × 2.9 = 2.9 × 10−5 C Examiner comments: (b) These calculations could do with some explanations. (i) When they are connected, all the positive charge remains on the top two plates and all the negative charge is on the bottom plates. The ...
... (ii) V = Q/C = 40 × 10−6/(14 × 10−6) = 2.9 V (iii) Q = 10 × 10−6 × 2.9 = 2.9 × 10−5 C Examiner comments: (b) These calculations could do with some explanations. (i) When they are connected, all the positive charge remains on the top two plates and all the negative charge is on the bottom plates. The ...
