RiverbeckConfPaper160516
... BiCMOS. Whilst both integrated circuit were implemented in the same technology LNA1 is a separate device to improve electrical isolation. Between the devices is a pair of 100 Ω differential microstrip lines. The overall gain is programmable from 15 dB – 45 dB, see Figure 5. On the main integrated ci ...
... BiCMOS. Whilst both integrated circuit were implemented in the same technology LNA1 is a separate device to improve electrical isolation. Between the devices is a pair of 100 Ω differential microstrip lines. The overall gain is programmable from 15 dB – 45 dB, see Figure 5. On the main integrated ci ...
Exp04rev
... AC Magnitude and Phase Objectives: Today's experiment provides practical experience with the meaning of magnitude and phase in a linear circuits and the use of phasor algebra to predict the response of a linear system to a sinusoidal input. Using the digital oscilloscopes, we can better understand t ...
... AC Magnitude and Phase Objectives: Today's experiment provides practical experience with the meaning of magnitude and phase in a linear circuits and the use of phasor algebra to predict the response of a linear system to a sinusoidal input. Using the digital oscilloscopes, we can better understand t ...
lab8
... ii. Apply a very small amplitude sine wave to the input, with a DC bias equal to what you recorded from the previous part. Make sure that the DC output level is roughly 6V. This can be hard because the gain is so high, so be careful. It will be easier to set your DC bias right using an AC signal tha ...
... ii. Apply a very small amplitude sine wave to the input, with a DC bias equal to what you recorded from the previous part. Make sure that the DC output level is roughly 6V. This can be hard because the gain is so high, so be careful. It will be easier to set your DC bias right using an AC signal tha ...
CircuitI_exp071411496961
... Figure 2 shows some characteristics of the waveforms: the voltage of one peak (Vp) and the peak-topeak voltage (Vp-p), which is twice of Vp for symmetric waveforms. The period (T) is also shown which is related to the frequency as f=1/T. ...
... Figure 2 shows some characteristics of the waveforms: the voltage of one peak (Vp) and the peak-topeak voltage (Vp-p), which is twice of Vp for symmetric waveforms. The period (T) is also shown which is related to the frequency as f=1/T. ...
09fa mid2
... You want to use the amplifier in unity gain feedback. 1A) If the compensation capacitor CC is zero, what is the frequency of the first and second poles? What is the unity gain frequency? What is the phase margin? ...
... You want to use the amplifier in unity gain feedback. 1A) If the compensation capacitor CC is zero, what is the frequency of the first and second poles? What is the unity gain frequency? What is the phase margin? ...
sheet3
... 9. An amplifier with feedback has voltage gain of 40. To produce a specified output, the input voltage required without feedback is 0.1v. When feedback has been provided the input must be increased to 2.4v to produce the same output. Calculate the value of feedback ratio. 10. The ac equivalent circ ...
... 9. An amplifier with feedback has voltage gain of 40. To produce a specified output, the input voltage required without feedback is 0.1v. When feedback has been provided the input must be increased to 2.4v to produce the same output. Calculate the value of feedback ratio. 10. The ac equivalent circ ...
hw3
... a. Write an expression for ID as a function of output bias point. How much does ID change as the output voltage varies from 9V to 1V? b. What is the change in the input and overdrive voltage as the output varies from 9V to 1V? c. Write an expression for gm and ro as a function of output bias point. ...
... a. Write an expression for ID as a function of output bias point. How much does ID change as the output voltage varies from 9V to 1V? b. What is the change in the input and overdrive voltage as the output varies from 9V to 1V? c. Write an expression for gm and ro as a function of output bias point. ...
resonance experiment
... across the inductor are equal, so the circuit looks like a resistor. No energy is dissipated at resonance. We looked at a typical resonant LCR circuit as shown in the diagram below. The values of the capacitor, inductor and resistor were 4700Picofarads, 1MH and either 33ohms or 330ohms depending on ...
... across the inductor are equal, so the circuit looks like a resistor. No energy is dissipated at resonance. We looked at a typical resonant LCR circuit as shown in the diagram below. The values of the capacitor, inductor and resistor were 4700Picofarads, 1MH and either 33ohms or 330ohms depending on ...
EEEE 381 Lab 6 Frequency Response - RIT
... the frequency of the small-signal input (shown as 1 kHz in Figure 2). The frequency of vsig should be varied from 1 kHz to a frequency that is sufficiently high to ensure that the magnitude of the voltage gain drops to unity (0 dB) — i.e., until the output signal amplitude is equal to the input sign ...
... the frequency of the small-signal input (shown as 1 kHz in Figure 2). The frequency of vsig should be varied from 1 kHz to a frequency that is sufficiently high to ensure that the magnitude of the voltage gain drops to unity (0 dB) — i.e., until the output signal amplitude is equal to the input sign ...
Stability and Frequency Compensation
... The phase begins to change at one-tenth of the pole (zero) frequency, changes by -45 degrees (+45 degrees) at the pole (zero), and approaches a -90-degree (+90-degree) change at 10 times the pole (zero) frequency. ...
... The phase begins to change at one-tenth of the pole (zero) frequency, changes by -45 degrees (+45 degrees) at the pole (zero), and approaches a -90-degree (+90-degree) change at 10 times the pole (zero) frequency. ...
Physics 517/617 HOMEWORK V Due Nov 24
... e) Remembering that the base-emitter junction of a transistor acts like a diode, use the results of part d) to describe how a high frequency AM signal gets demodulated (turned into high and audio frequencies) in the radio you will be building in lab. f) Again, considering the AM radio you are to bui ...
... e) Remembering that the base-emitter junction of a transistor acts like a diode, use the results of part d) to describe how a high frequency AM signal gets demodulated (turned into high and audio frequencies) in the radio you will be building in lab. f) Again, considering the AM radio you are to bui ...
Bode plot
In electrical engineering and control theory, a Bode plot /ˈboʊdi/ is a graph of the frequency response of a system. It is usually a combination of a Bode magnitude plot, expressing the magnitude of the frequency response, and a Bode phase plot, expressing the phase shift. Both quantities are plotted against a horizontal axis proportional to the logarithm of frequency.