
Lecture 5 (linked lists, vectors)
... returns the element at rank r without removing it object replaceAtRank(integer r, object o): replace the element at rank with o and return the old element insertAtRank(integer r, object o): insert a new element o to have rank r object removeAtRank(integer r): removes and returns the element at ...
... returns the element at rank r without removing it object replaceAtRank(integer r, object o): replace the element at rank with o and return the old element insertAtRank(integer r, object o): insert a new element o to have rank r object removeAtRank(integer r): removes and returns the element at ...
Lecture 3 Linear Data Structures
... • Array: a sequence of indexed components with the following properties: – array size is fixed at the time of array’s construction • int[] numbers = new int [10]; – array elements are placed contiguously in memory • address of any element can be calculated directly as its offset from the beginn ...
... • Array: a sequence of indexed components with the following properties: – array size is fixed at the time of array’s construction • int[] numbers = new int [10]; – array elements are placed contiguously in memory • address of any element can be calculated directly as its offset from the beginn ...
Exercise
... • h: Height of the tree • insertion and removal operations take O(log(n)) steps • Heap’s regular layout makes it possible to store heap nodes efficiently in an array Exercise The software that controls the events in a user interface keeps the events in a data structure. Whenever an event such as a m ...
... • h: Height of the tree • insertion and removal operations take O(log(n)) steps • Heap’s regular layout makes it possible to store heap nodes efficiently in an array Exercise The software that controls the events in a user interface keeps the events in a data structure. Whenever an event such as a m ...
Program Design Strategies Abstract Data Types (ADTs) Queues
... Operations insert and getMax can be slow if the tree is “skinny” • Both take linear time on a skinny tree and O(log n) time on a fat tree ...
... Operations insert and getMax can be slow if the tree is “skinny” • Both take linear time on a skinny tree and O(log n) time on a fat tree ...
Lecture 3 Linear Data Structures
... • Array: a sequence of indexed components with the following properties: – array size is fixed at the time of array’s construction • int[] numbers = new int [10]; – array elements are placed contiguously in memory • address of any element can be calculated directly as its offset from the beginn ...
... • Array: a sequence of indexed components with the following properties: – array size is fixed at the time of array’s construction • int[] numbers = new int [10]; – array elements are placed contiguously in memory • address of any element can be calculated directly as its offset from the beginn ...
TECH REPORT
... take O(log log n) time and Store operations take O(log log n) amortized expected time. The algorithm uses linear space. Because any data structure can be implemented with an array, we can use the techniques described in this paper to make any data structure fully persistent at a cost of an extra fac ...
... take O(log log n) time and Store operations take O(log log n) amortized expected time. The algorithm uses linear space. Because any data structure can be implemented with an array, we can use the techniques described in this paper to make any data structure fully persistent at a cost of an extra fac ...
**** 1 - Postech
... An abstract data type storing arbitrary objects. An ordered list in which all insertions and deletions are made at one end, called top ...
... An abstract data type storing arbitrary objects. An ordered list in which all insertions and deletions are made at one end, called top ...
ppt (new version
... Ensuring good average performance The chance that two keys will fall to the same slot is 1/m - just like if the hash function was truly random! ...
... Ensuring good average performance The chance that two keys will fall to the same slot is 1/m - just like if the hash function was truly random! ...
Chapter 4
... Abstract data structures Commonly implemented using arrays Can be implemented using other structures ...
... Abstract data structures Commonly implemented using arrays Can be implemented using other structures ...
ELEMENTARY DATA STRUCTURES
... Read characters until end of file If the character is an open anything, push it in the stack If it’s a close anything,then if stack is empty, report an error, otherwise, pop the stack 5. If popped symbol is not the corresponding opening symbol, then report an error 6. At end of file, if stack is not ...
... Read characters until end of file If the character is an open anything, push it in the stack If it’s a close anything,then if stack is empty, report an error, otherwise, pop the stack 5. If popped symbol is not the corresponding opening symbol, then report an error 6. At end of file, if stack is not ...
Stacks and Queues Dynamic memory allocation
... we can create a single object dynamically by myPtr = new myDataType; or a dynamically created array by myPtr = new myDataType[100]; ...
... we can create a single object dynamically by myPtr = new myDataType; or a dynamically created array by myPtr = new myDataType[100]; ...
CSci 161
... b) add a random value between 0 and 1000 to each array element, using an instance of the Random class and its nextInt(int n) method c) sort the array, using Arrays.sort() d) display the array, using Arrays.toString() to create something that is displayable CSci 161 ...
... b) add a random value between 0 and 1000 to each array element, using an instance of the Random class and its nextInt(int n) method c) sort the array, using Arrays.sort() d) display the array, using Arrays.toString() to create something that is displayable CSci 161 ...
Fundamental Data Structures
... In reality the average insertion rate of elements should not exceed the average removal rate since the queue would grow ad infinitum and blast the available memory. Usually a fixed number of queue elements will suffice to balance possible insertion bursts or removal delays. Here is a possible realiz ...
... In reality the average insertion rate of elements should not exceed the average removal rate since the queue would grow ad infinitum and blast the available memory. Usually a fixed number of queue elements will suffice to balance possible insertion bursts or removal delays. Here is a possible realiz ...
COMP20010: Algorithms and Imperative Programming
... In order to extend the previous data structure to the case of general trees; In order to register a potentially large number of children of a node, we need to use a container (a list or a vector) to store the children, instead of using instance variables; null ...
... In order to extend the previous data structure to the case of general trees; In order to register a potentially large number of children of a node, we need to use a container (a list or a vector) to store the children, instead of using instance variables; null ...
Week 3 - Ken Cosh
... Stacks are linear data structures, that can only be accessed at one end for storing and retrieving data. New data is added to the top of a stack, and data is also retrieved from the top of the stack. Similar to a stack of trays in a canteen. It is a LIFO structure (Last In First Out). ...
... Stacks are linear data structures, that can only be accessed at one end for storing and retrieving data. New data is added to the top of a stack, and data is also retrieved from the top of the stack. Similar to a stack of trays in a canteen. It is a LIFO structure (Last In First Out). ...
LISTS
... forward or backward in the list and to insert before or after the current node. Note however that memory requirements are now increased in order to do this and the algorithms must cope with two references for each node. Once again, some processes can be accomplished more quickly but worst case is st ...
... forward or backward in the list and to insert before or after the current node. Note however that memory requirements are now increased in order to do this and the algorithms must cope with two references for each node. Once again, some processes can be accomplished more quickly but worst case is st ...