Exam and Revision Advice
... Net force on m1 equals T, but T is unknown, so use Net force on the system of two masses: Net force on (m1 and m2) = m2g, but Net F = Ma, so m2g = (m1 + m2) x a. Substituting, 0.10 x 10 = (0.1 + 0.4) x a, solve for a. Conseq Q’n: use value of accel’n. Two methods: i) Use equations of motion to find ...
... Net force on m1 equals T, but T is unknown, so use Net force on the system of two masses: Net force on (m1 and m2) = m2g, but Net F = Ma, so m2g = (m1 + m2) x a. Substituting, 0.10 x 10 = (0.1 + 0.4) x a, solve for a. Conseq Q’n: use value of accel’n. Two methods: i) Use equations of motion to find ...
Vectors and Scalars
... An object with a weight of 800 N is suspended by two ropes. The force exerted by one rope is 600 N, directed to the left at an angle of 40° above the horizontal. What force must be exerted by the other rope to keep the object from moving? Draw a scale diagram. ...
... An object with a weight of 800 N is suspended by two ropes. The force exerted by one rope is 600 N, directed to the left at an angle of 40° above the horizontal. What force must be exerted by the other rope to keep the object from moving? Draw a scale diagram. ...
newton`s third law of motion—action and reaction
... If we extend the basic idea of a cannon recoiling from the cannonball it launches, we can understand rocket propulsion. Consider air escaping from an untied, blown-up balloon. If the balloon is released and allowed to move as shown in Figure 7.8, it accelerates as the air comes out. A rocket accele ...
... If we extend the basic idea of a cannon recoiling from the cannonball it launches, we can understand rocket propulsion. Consider air escaping from an untied, blown-up balloon. If the balloon is released and allowed to move as shown in Figure 7.8, it accelerates as the air comes out. A rocket accele ...
Slide lecture for chapter 7
... • so the kinetic energy is owned by the body’s mass and speed, whereas the potential energy is owned by ‘potential energy field’, by virtue of the body’s position • alternative definition: given a force F(x), and a second force that ‘you’ exert that exactly opposes it, so Fyou = – F(x), the change i ...
... • so the kinetic energy is owned by the body’s mass and speed, whereas the potential energy is owned by ‘potential energy field’, by virtue of the body’s position • alternative definition: given a force F(x), and a second force that ‘you’ exert that exactly opposes it, so Fyou = – F(x), the change i ...
Conservation Laws for Systems of Particles
... derivation of equation (16), we have made no assumptions about the motion of the center of mass, G. That is, equation (16) is valid even when G is accelerated. We have implicitly assumed that the reference frame used to describe r �i in equation 13 is non-rotating with respect to the fixed frame xyz ...
... derivation of equation (16), we have made no assumptions about the motion of the center of mass, G. That is, equation (16) is valid even when G is accelerated. We have implicitly assumed that the reference frame used to describe r �i in equation 13 is non-rotating with respect to the fixed frame xyz ...
Oscillations (PPT) - Uplift North Hills Prep
... ET = (1/2)kxMAX2 = (1/2) 5.0 2.02 = 10. J. (e) Find the speed of the mass when its displacement is 1.0 m. SOLUTION: ET = (1/2)mv 2 + (1/2)kx 2. Then 10. = (1/2)(4)v 2 + (1/2)(5)12 v = 1.9 ms-1. ...
... ET = (1/2)kxMAX2 = (1/2) 5.0 2.02 = 10. J. (e) Find the speed of the mass when its displacement is 1.0 m. SOLUTION: ET = (1/2)mv 2 + (1/2)kx 2. Then 10. = (1/2)(4)v 2 + (1/2)(5)12 v = 1.9 ms-1. ...
Document
... To get something moving, you do work on it, the result being kinetic energy. To get objects spinning also takes work, but what is the rotational equivalent of kinetic energy? Problem: in a rotating object, each bit of mass has the same angular speed , but different linear speed v. ...
... To get something moving, you do work on it, the result being kinetic energy. To get objects spinning also takes work, but what is the rotational equivalent of kinetic energy? Problem: in a rotating object, each bit of mass has the same angular speed , but different linear speed v. ...
File - SPH3U- 11 University Prep Physics
... 21. A stationary box of mass 4.2 kg is given a push of 8.2 N [S] along a surface where the frictional force acting is 5.8 N [N]. The push lasts for 3.6 s and then the box is allowed to slide on its own until it comes to rest. (a) Draw free-body diagrams to show the box being pushed and sliding on it ...
... 21. A stationary box of mass 4.2 kg is given a push of 8.2 N [S] along a surface where the frictional force acting is 5.8 N [N]. The push lasts for 3.6 s and then the box is allowed to slide on its own until it comes to rest. (a) Draw free-body diagrams to show the box being pushed and sliding on it ...
MOTION IN TWO DIMENSIONS NOTES
... object that is some height h above the ground. Something has given it horizontal velocity v at this point. Its initial vertical velocity is zero. You will be asked to describe its motion as it falls to the ground. Remember -- describe its horizontal motion (it moves with constant horizontal speed v) ...
... object that is some height h above the ground. Something has given it horizontal velocity v at this point. Its initial vertical velocity is zero. You will be asked to describe its motion as it falls to the ground. Remember -- describe its horizontal motion (it moves with constant horizontal speed v) ...
eBook AQA GCSE Physics Unit P2 Part 1
... in the control system. It is now scheduled to open to the public in 2011. There is an even faster roller coaster under construction in Dubai – its top speed will be 240 km/h. ...
... in the control system. It is now scheduled to open to the public in 2011. There is an even faster roller coaster under construction in Dubai – its top speed will be 240 km/h. ...
File - mr. welling` s school page
... Activity 1 Hold this textbook at arm’s length in front of your shoulders. Move the book from left to right and back again. Repeat these actions with a piece of paper. What differences do you notice between the effort needed to change the direction of the paper and the effort needed to change the dir ...
... Activity 1 Hold this textbook at arm’s length in front of your shoulders. Move the book from left to right and back again. Repeat these actions with a piece of paper. What differences do you notice between the effort needed to change the direction of the paper and the effort needed to change the dir ...