Slide 1
... A block S (the sliding block) with mass M =3.3 kg is free to move along a horizontal frictionless surface. It is connected by a cord that wraps over a frictionless pulley, to a second block H (the hanging block) with mass m = 2.1 kg. The cord and pulley are considered to be “massless”. The hanging b ...
... A block S (the sliding block) with mass M =3.3 kg is free to move along a horizontal frictionless surface. It is connected by a cord that wraps over a frictionless pulley, to a second block H (the hanging block) with mass m = 2.1 kg. The cord and pulley are considered to be “massless”. The hanging b ...
Topic 2 Mechanics Part 3 and 4 projectile, friction,10
... 3. A goofball is hit with an initial velocity of 35ms-1 at an angle less than 450 above the horizontal. The horizontal component of the velocity : a) greater than b) equal to or c) less than the vertical component Answer – a) Explain the answer above: Range (x) = horizontal displacement from point o ...
... 3. A goofball is hit with an initial velocity of 35ms-1 at an angle less than 450 above the horizontal. The horizontal component of the velocity : a) greater than b) equal to or c) less than the vertical component Answer – a) Explain the answer above: Range (x) = horizontal displacement from point o ...
Document
... A gun carrier M moves on a frictionless incline, its speed reduces from v to 0 after shooting a canon-ball m in the horizontal direction. Is the total momentum of system (M and m) conserved in this process, and why? Find out the speed of canon-ball. ...
... A gun carrier M moves on a frictionless incline, its speed reduces from v to 0 after shooting a canon-ball m in the horizontal direction. Is the total momentum of system (M and m) conserved in this process, and why? Find out the speed of canon-ball. ...
Angular Momentum FA#7--Angular Momentum
... (10) Imagine that our sun ran out of nuclear fuel and collapsed. What would its radius have to be in order for its period of rotation to be the same as “pulsars” with a rotational period of 1.33 seconds/rotation? The sun’s current period of rotation is 25 days. (I = 2/5mR2 for spheres). Msun = 2.0 x ...
... (10) Imagine that our sun ran out of nuclear fuel and collapsed. What would its radius have to be in order for its period of rotation to be the same as “pulsars” with a rotational period of 1.33 seconds/rotation? The sun’s current period of rotation is 25 days. (I = 2/5mR2 for spheres). Msun = 2.0 x ...
AIM: Force and Motion Ideas An object`s position can be described
... Some types of force, typically those caused by everyday pushes and pulls (such as when people push or pull on other objects), only exist when the objects involved are in direct contact with each other. When contact is broken these forces no longer exist. Some types of force, such as gravity and m ...
... Some types of force, typically those caused by everyday pushes and pulls (such as when people push or pull on other objects), only exist when the objects involved are in direct contact with each other. When contact is broken these forces no longer exist. Some types of force, such as gravity and m ...
10 Circular Motion
... Centripetal force, Fc, is measured in newtons when m is expressed in kilograms, v in meters/second, and r in meters. ...
... Centripetal force, Fc, is measured in newtons when m is expressed in kilograms, v in meters/second, and r in meters. ...
Force
... problem. Glen suggests that the normal force is 50 N; Olive suggests that the normal force in the diagram is 75 N; and Warren suggests that the normal force is 100 N. While all three answers may seem reasonable, only one is correct. Indicate which two answers are wrong and explain why they are wrong ...
... problem. Glen suggests that the normal force is 50 N; Olive suggests that the normal force in the diagram is 75 N; and Warren suggests that the normal force is 100 N. While all three answers may seem reasonable, only one is correct. Indicate which two answers are wrong and explain why they are wrong ...
04-16 Applying Newton`s 2nd Law
... Make a quantitative force diagram for the grocery bag. without ripping is 250 N. Do the groceries stay in the bag or does the bag rip? Explain using evidence and reasoning from your force diagram and calculations. ...
... Make a quantitative force diagram for the grocery bag. without ripping is 250 N. Do the groceries stay in the bag or does the bag rip? Explain using evidence and reasoning from your force diagram and calculations. ...
Newton`s Laws - Seattle Central College
... 2. If an object is sliding relative to the table, the resulting friction is kinetic, if it is not moving relative to another object, the resulting friction is static (or there is no friction). Use subscripts s for static and k for kinetic. 3. Make sure that all your observations, kinematics, FBDs an ...
... 2. If an object is sliding relative to the table, the resulting friction is kinetic, if it is not moving relative to another object, the resulting friction is static (or there is no friction). Use subscripts s for static and k for kinetic. 3. Make sure that all your observations, kinematics, FBDs an ...
POP4e: Ch. 1 Problems
... object is in equilibrium if the forces are equal in magnitude and opposite in direction. (b) The object is in equilibrium if the net torque on the object is zero. (c) The object is in equilibrium if the forces act at the same point on the object. (d) The object is in equilibrium if the net force and ...
... object is in equilibrium if the forces are equal in magnitude and opposite in direction. (b) The object is in equilibrium if the net torque on the object is zero. (c) The object is in equilibrium if the forces act at the same point on the object. (d) The object is in equilibrium if the net force and ...
Recitation
... Reflect: Note that the weight of 20 N was never used in the calculations because both gravitational potential and kinetic energy are proportional to mass, m. Thus any object, that attains 25.0 m/s at a height of 15.0 m, must have an initial velocity of 30.3 m/s. As the rock moves upward gravity does ...
... Reflect: Note that the weight of 20 N was never used in the calculations because both gravitational potential and kinetic energy are proportional to mass, m. Thus any object, that attains 25.0 m/s at a height of 15.0 m, must have an initial velocity of 30.3 m/s. As the rock moves upward gravity does ...
Physics 2170
... Back in Physics 1110 we started by discussing velocities and accelerations and called this kinematics. Then we moved to Newton’s laws of motion which tells us that it is force that causes acceleration. This is called dynamics. Finally, we used conservation of momentum and conservation of energy to a ...
... Back in Physics 1110 we started by discussing velocities and accelerations and called this kinematics. Then we moved to Newton’s laws of motion which tells us that it is force that causes acceleration. This is called dynamics. Finally, we used conservation of momentum and conservation of energy to a ...
angular momentum.
... that a centrifugal force pulls outward on an object. • Example: – If the string breaks, the object doesn’t move radially outward. – It continues along its tangent straight-line path—because no force acts on it. (Newton’s first law) ...
... that a centrifugal force pulls outward on an object. • Example: – If the string breaks, the object doesn’t move radially outward. – It continues along its tangent straight-line path—because no force acts on it. (Newton’s first law) ...
