Circular Motion Webquest Project Physics 12
... • The idea behind The Widow Maker must be uniform circular motion, since it is moving in a circle at constant speed. • As in moves in a circle it is always changing direction, which means although it is at a constant speed, the velocity is changing since velocity is a vector. • This means it is also ...
... • The idea behind The Widow Maker must be uniform circular motion, since it is moving in a circle at constant speed. • As in moves in a circle it is always changing direction, which means although it is at a constant speed, the velocity is changing since velocity is a vector. • This means it is also ...
UNIT 4 Lab
... Discuss your answers with an instructor. It is common to draw force diagrams to indicate the forces acting on an object. When we draw force diagrams, we will represent the object by a large point. The forces will be drawn as arrows pointing in the direction of the force, with the tail of the arrow ...
... Discuss your answers with an instructor. It is common to draw force diagrams to indicate the forces acting on an object. When we draw force diagrams, we will represent the object by a large point. The forces will be drawn as arrows pointing in the direction of the force, with the tail of the arrow ...
Learning material
... So much for speeds. To do dynamics we also need a description of the acceleration of a body moving uniformly in a circle. Consider first the change in speed between two neighbouring points on the circle in figure 1. Because we’re considering uniform motion round the circle, the speed is constant so ...
... So much for speeds. To do dynamics we also need a description of the acceleration of a body moving uniformly in a circle. Consider first the change in speed between two neighbouring points on the circle in figure 1. Because we’re considering uniform motion round the circle, the speed is constant so ...
Static-chapter3
... rB rA O To derive the moment of the couple, consider two vectors , rA and rB from O to points A and B lying on the line of action of F and - F. The moment of the couple about O is: M = rA x (F) + rB x (-F) = (rA - rB) x F By triangle law of vector addition, rB + r = rA or r = rA - rB So: M = r x F T ...
... rB rA O To derive the moment of the couple, consider two vectors , rA and rB from O to points A and B lying on the line of action of F and - F. The moment of the couple about O is: M = rA x (F) + rB x (-F) = (rA - rB) x F By triangle law of vector addition, rB + r = rA or r = rA - rB So: M = r x F T ...
Document
... rB rA O To derive the moment of the couple, consider two vectors , rA and rB from O to points A and B lying on the line of action of F and - F. The moment of the couple about O is: M = rA x (F) + rB x (-F) = (rA - rB) x F By triangle law of vector addition, rB + r = rA or r = rA - rB So: M = r x F T ...
... rB rA O To derive the moment of the couple, consider two vectors , rA and rB from O to points A and B lying on the line of action of F and - F. The moment of the couple about O is: M = rA x (F) + rB x (-F) = (rA - rB) x F By triangle law of vector addition, rB + r = rA or r = rA - rB So: M = r x F T ...
Ch 6: Work and Energy 6.1 Work and Kinetic Energy `Member the
... 6-2 The Dot Product What we’ve learned so far is that work can be calculated by multiplying force, or the “component of force in the direction of motion” by the distance an object moves. This works (excuse the pun) for work done by a constant force, or piecewise-smooth linear forces. We’ve also lear ...
... 6-2 The Dot Product What we’ve learned so far is that work can be calculated by multiplying force, or the “component of force in the direction of motion” by the distance an object moves. This works (excuse the pun) for work done by a constant force, or piecewise-smooth linear forces. We’ve also lear ...
5. - Cloudfront.net
... Gravity - pull to the center of the earth Gravitational acceleration(g) = 9.8m /sec2 or 10 m/ sec2 =32 ft/ sec 2 Free Fall – motion going down due to gravity Weight –downward force due to gravity, Newtons weight = mass,kg X gravitational acceleration(g) Air Friction , Newton– force that opposes the ...
... Gravity - pull to the center of the earth Gravitational acceleration(g) = 9.8m /sec2 or 10 m/ sec2 =32 ft/ sec 2 Free Fall – motion going down due to gravity Weight –downward force due to gravity, Newtons weight = mass,kg X gravitational acceleration(g) Air Friction , Newton– force that opposes the ...
Prep-Physics Practice Final Exam Free body diagram 1. Dale skis
... 50. A point at the end of a spinning helicopter blade has a centripetal acceleration of 30 m/s2. If the velocity of the blade at this point is 10 m/s, how long is the helicopter blade? 51. A toy car is tied to a post with string, causing it to drive in a tight circle. This is shown in the picture be ...
... 50. A point at the end of a spinning helicopter blade has a centripetal acceleration of 30 m/s2. If the velocity of the blade at this point is 10 m/s, how long is the helicopter blade? 51. A toy car is tied to a post with string, causing it to drive in a tight circle. This is shown in the picture be ...
03pp notes
... Newton’s Second Law of Motion When acceleration is less than g—non-free fall. The force exerted by the surrounding air increases with the increasing falling speed. The force of air resistance may continue to increase until it equals the weight. At this point, net force is zero and no further accele ...
... Newton’s Second Law of Motion When acceleration is less than g—non-free fall. The force exerted by the surrounding air increases with the increasing falling speed. The force of air resistance may continue to increase until it equals the weight. At this point, net force is zero and no further accele ...