Oscillatory Motion
... The forces acting on the bob are the tension and the weight. T is the force exerted by the string mg is the gravitational force The tangential component of the gravitational force is the restoring force. Recall that the tangential acceleration is ...
... The forces acting on the bob are the tension and the weight. T is the force exerted by the string mg is the gravitational force The tangential component of the gravitational force is the restoring force. Recall that the tangential acceleration is ...
Topic 4
... The greater the mass, the smaller the acceleration for a given force. Mass is inversely related to force. An object with twice the mass will have half the acceleration if the same force is applied. ...
... The greater the mass, the smaller the acceleration for a given force. Mass is inversely related to force. An object with twice the mass will have half the acceleration if the same force is applied. ...
Centripetal Force
... Centripetal force is not another force to add to our list of forces such as weight, normal, etc. It is a characteristic of a force, force component, or combination of forces. For example, a bicycle rounding a flat curve will have a static force of friction maintain its circular motion. A bicycle rou ...
... Centripetal force is not another force to add to our list of forces such as weight, normal, etc. It is a characteristic of a force, force component, or combination of forces. For example, a bicycle rounding a flat curve will have a static force of friction maintain its circular motion. A bicycle rou ...
Final 2
... You may use both sides of two 8.5 x 11 sheets for formulas and reference information. Choose 30 of the 40 questions on the test. Each is worth 3 1/3 points. If you answer more than 30 questions, only the FIRST 30 will be counted. Answer all questions on the Scantron sheet. Be sure your name ...
... You may use both sides of two 8.5 x 11 sheets for formulas and reference information. Choose 30 of the 40 questions on the test. Each is worth 3 1/3 points. If you answer more than 30 questions, only the FIRST 30 will be counted. Answer all questions on the Scantron sheet. Be sure your name ...
CTNewtonLawsb
... CTN-18 A block of mass m on a rough table is pulled by a string as shown. The string exerts a horizontal force of magnitude FT . The coefficient of static friction between block and table is S; the kinetic friction coefficient is K. As with most surfaces, S > ...
... CTN-18 A block of mass m on a rough table is pulled by a string as shown. The string exerts a horizontal force of magnitude FT . The coefficient of static friction between block and table is S; the kinetic friction coefficient is K. As with most surfaces, S > ...
SEPT 19 HPS
... The electric motor of a model train accelerates the train from rest to 0.620 m/s in 21.0 ms. The total mass of the train is 875 g. Find the average power delivered to the train during the acceleration. ...
... The electric motor of a model train accelerates the train from rest to 0.620 m/s in 21.0 ms. The total mass of the train is 875 g. Find the average power delivered to the train during the acceleration. ...
0090 Script - Introduction to Newton`s First Law of Motion
... those two forces are equal in magnitude and opposite in direction so they cancel one another out because their sum is zero. So the sphere will maintain a constant velocity until it experiences a net external force, for example, it could run into some wood blocks. The wood blocks applied a net extern ...
... those two forces are equal in magnitude and opposite in direction so they cancel one another out because their sum is zero. So the sphere will maintain a constant velocity until it experiences a net external force, for example, it could run into some wood blocks. The wood blocks applied a net extern ...
Work and Power Notes
... o When you use a ramp you will travel more distance (the hypotenuse) but you will exert less force. o Two men have identical boxes to move. One man uses the ramp and anther lifts the load straight up. The same amount of work is done by both people. So why use a ramp? ...
... o When you use a ramp you will travel more distance (the hypotenuse) but you will exert less force. o Two men have identical boxes to move. One man uses the ramp and anther lifts the load straight up. The same amount of work is done by both people. So why use a ramp? ...
Newton`s Laws presentation
... due to friction. This force accelerates the car forward. The brakes apply a force to the wheels, which in turn apply a frictional force to the ground, decelerating the car. So the gas pedal and the brakes are both accelerators, since they change the speed of the car. Because velocity is the combinat ...
... due to friction. This force accelerates the car forward. The brakes apply a force to the wheels, which in turn apply a frictional force to the ground, decelerating the car. So the gas pedal and the brakes are both accelerators, since they change the speed of the car. Because velocity is the combinat ...
Forces - Vicphysics
... You will often be asked to draw diagrams illustrating forces. There are several considerations when drawing force diagrams: The arrows that represent the forces should point in the direction of applied force. The length of the arrow represents the strength of the force, so some effort should be ma ...
... You will often be asked to draw diagrams illustrating forces. There are several considerations when drawing force diagrams: The arrows that represent the forces should point in the direction of applied force. The length of the arrow represents the strength of the force, so some effort should be ma ...
ch04
... • Select an object(s) to which the equations of equilibrium are to be applied. • Draw a free-body diagram for each object chosen above. Include only forces acting on the object, not forces the object exerts on its environment. • Choose a set of x, y axes for each object and resolve all forces in the ...
... • Select an object(s) to which the equations of equilibrium are to be applied. • Draw a free-body diagram for each object chosen above. Include only forces acting on the object, not forces the object exerts on its environment. • Choose a set of x, y axes for each object and resolve all forces in the ...
unit: describing motion
... Note to students: Your semester exam will cover everything that we have done so far this year. While this study guide is designed to help you study, be sure to also look over your content quizzes, unit tests, lab activities, Gizmos, ISN and textbook. Extra credit will be given for FULL completion of ...
... Note to students: Your semester exam will cover everything that we have done so far this year. While this study guide is designed to help you study, be sure to also look over your content quizzes, unit tests, lab activities, Gizmos, ISN and textbook. Extra credit will be given for FULL completion of ...
Chapter 2
... Newton’s 1st Law of Motion Isaac Newton (1642 – 1727) Newton took Galileo’s principle of inertia and built it into his First Law of Motion (also known as the Law of Inertia). “Every object continues in its state of rest, or of uniform motion in a straight line, unless it is compelled to change that ...
... Newton’s 1st Law of Motion Isaac Newton (1642 – 1727) Newton took Galileo’s principle of inertia and built it into his First Law of Motion (also known as the Law of Inertia). “Every object continues in its state of rest, or of uniform motion in a straight line, unless it is compelled to change that ...
Circular Motion Notes.notebook
... Centripetal Force Centripetal acceleration is due to a centripetal force. Centripetal force is the net force required to keep an object moving in a circular path. It may be a tension, force of friction, force of gravity or a combination of force components that point along the radial directio ...
... Centripetal Force Centripetal acceleration is due to a centripetal force. Centripetal force is the net force required to keep an object moving in a circular path. It may be a tension, force of friction, force of gravity or a combination of force components that point along the radial directio ...