Physics 11 Dynamics - hrsbstaff.ednet.ns.ca
... Note: for all dynamics problem-solving questions, draw appropriate free body diagrams and use the aforementioned problem-solving method. 1. Define the following terms: Inertia - the natural tendency of an object to stay at rest or continue its motion in a straight line at constant speed in the absen ...
... Note: for all dynamics problem-solving questions, draw appropriate free body diagrams and use the aforementioned problem-solving method. 1. Define the following terms: Inertia - the natural tendency of an object to stay at rest or continue its motion in a straight line at constant speed in the absen ...
No Slide Title
... So far, we used: PEgravity=mgh Only valid for h near earth’s surface. More general: PEgravity=-GMEarthm/r PE=0 at infinity distance from the center of the earth See example 7.12 for consistency between these two. Example: escape speed: what should the minimum initial velocity of a rocket be if we wa ...
... So far, we used: PEgravity=mgh Only valid for h near earth’s surface. More general: PEgravity=-GMEarthm/r PE=0 at infinity distance from the center of the earth See example 7.12 for consistency between these two. Example: escape speed: what should the minimum initial velocity of a rocket be if we wa ...
Centripetal Force / Gravity (very good practice)
... 5. The acceleration of gravity on the moon is one-sixth what it is on Earth. The radius of the moon is one-fourth that of the Earth. Determine the moon’s mass. 6. Two objects, with masses m1 and m2, are originally a distance r apart. The magnitude of the force between them is F. If the masses are ch ...
... 5. The acceleration of gravity on the moon is one-sixth what it is on Earth. The radius of the moon is one-fourth that of the Earth. Determine the moon’s mass. 6. Two objects, with masses m1 and m2, are originally a distance r apart. The magnitude of the force between them is F. If the masses are ch ...
FreeVibrations-freestudy-co-uk.pdf
... from the horizontal centre line at any time is x. This is also the displacement of point P. The yoke reaches a maximum displacement equal to R when the pin is at the top and –R when the pin is at the bottom. This is the amplitude of the oscillation. If the wheel rotates at ω radian/sec then after ti ...
... from the horizontal centre line at any time is x. This is also the displacement of point P. The yoke reaches a maximum displacement equal to R when the pin is at the top and –R when the pin is at the bottom. This is the amplitude of the oscillation. If the wheel rotates at ω radian/sec then after ti ...
Solutions to Physics 110 Sample Mid-Term Exam (hand
... A1) a) Yes. In order to know what an object would weigh if it were on earth one must determine the mass of the object. The object’s weight is then W = mg, where g = 9.8 m/s2 the acceleration due to earth’s gravity. Astronauts can determine in space by various means the relative mass of an object, wh ...
... A1) a) Yes. In order to know what an object would weigh if it were on earth one must determine the mass of the object. The object’s weight is then W = mg, where g = 9.8 m/s2 the acceleration due to earth’s gravity. Astronauts can determine in space by various means the relative mass of an object, wh ...
Asim Kiani - BrainMass
... Ricardo notices that the canoe moves 40 cm relative to a submerged log during the exchange and calculates Carmelita’s mass, which she has not told him. What is it ? This is another conservation of momentum problem, but it takes a little unraveling. You see, during the exchange, Ricardo (80 kg) moves ...
... Ricardo notices that the canoe moves 40 cm relative to a submerged log during the exchange and calculates Carmelita’s mass, which she has not told him. What is it ? This is another conservation of momentum problem, but it takes a little unraveling. You see, during the exchange, Ricardo (80 kg) moves ...
Physics I - Rose
... EXECUTE: (a) (17.0 N)(0.250 m)sin37° 2.56 N m . The torque is counterclockwise. (b) The torque is maximum when 90° and the force is perpendicular to the wrench. This maximum torque is (17.0 N)(0.250 m) 4.25 N m . EVALUATE: If the force is directed along the handle then the torque is ...
... EXECUTE: (a) (17.0 N)(0.250 m)sin37° 2.56 N m . The torque is counterclockwise. (b) The torque is maximum when 90° and the force is perpendicular to the wrench. This maximum torque is (17.0 N)(0.250 m) 4.25 N m . EVALUATE: If the force is directed along the handle then the torque is ...
gravity quest key
... It turns out that the theory of relativity gives the same expression for this limiting radius, referred to as the “Schwarzschild radius”. In Newtonian mechanics, however, the description of what happens to objects attracted to this sphere is often highly inaccurate. But in any case, 2GM c2 = 2 (6.67 ...
... It turns out that the theory of relativity gives the same expression for this limiting radius, referred to as the “Schwarzschild radius”. In Newtonian mechanics, however, the description of what happens to objects attracted to this sphere is often highly inaccurate. But in any case, 2GM c2 = 2 (6.67 ...
Centripetal and Gravitational Forces
... • The smaller the velocity of the object, the less centripetal force you will have to apply. • The smaller the length of rope (radius), the more centripetal force you will have to apply to the rope. • Notice that the centripetal force and the centripetal acceleration are always pointing in the same ...
... • The smaller the velocity of the object, the less centripetal force you will have to apply. • The smaller the length of rope (radius), the more centripetal force you will have to apply to the rope. • Notice that the centripetal force and the centripetal acceleration are always pointing in the same ...
Applications of Integration handout
... Here are a few important applications of integration. The applications you may see on an exam in this course include only the Net Change Theorem (which is really just the Fundamental Theorem of Calculus, interpreted in some applied context), plus the ones we review in class, including average value, ...
... Here are a few important applications of integration. The applications you may see on an exam in this course include only the Net Change Theorem (which is really just the Fundamental Theorem of Calculus, interpreted in some applied context), plus the ones we review in class, including average value, ...
