2.05 AQA F = ma - extra questions
... (a) The toy parachute is thrown with an initial horizontal speed of 9.0 ms–1. Calculate the initial vertical speed. (2 marks) (b) The wall is a horizontal distance of 12 m from the point at which the toy parachute is thrown. You may ignore air resistance in this part of the question. (i) ...
... (a) The toy parachute is thrown with an initial horizontal speed of 9.0 ms–1. Calculate the initial vertical speed. (2 marks) (b) The wall is a horizontal distance of 12 m from the point at which the toy parachute is thrown. You may ignore air resistance in this part of the question. (i) ...
Chapter 2 Motion Along a Straight Line
... speed. • It is important to realize that speeding up is not always associated with an acceleration that is positive. Likewise, slowing down is not always associated with an acceleration that is negative. The relative directions of an object's velocity and acceleration determine whether the object wi ...
... speed. • It is important to realize that speeding up is not always associated with an acceleration that is positive. Likewise, slowing down is not always associated with an acceleration that is negative. The relative directions of an object's velocity and acceleration determine whether the object wi ...
Chapter 2 Motion Along a Straight Line
... speed. • It is important to realize that speeding up is not always associated with an acceleration that is positive. Likewise, slowing down is not always associated with an acceleration that is negative. The relative directions of an object's velocity and acceleration determine whether the object wi ...
... speed. • It is important to realize that speeding up is not always associated with an acceleration that is positive. Likewise, slowing down is not always associated with an acceleration that is negative. The relative directions of an object's velocity and acceleration determine whether the object wi ...
Raising and Lowering
... negative velocity. Draw a motion diagram for the box. Is the net force on the box, up, down or zero? Draw a force diagram for the box. Acceleration is positive, e.g. velocity might change from -10 to -5, an increase of +5. The net force = mass x acceleration which is upwards since acceleration is up ...
... negative velocity. Draw a motion diagram for the box. Is the net force on the box, up, down or zero? Draw a force diagram for the box. Acceleration is positive, e.g. velocity might change from -10 to -5, an increase of +5. The net force = mass x acceleration which is upwards since acceleration is up ...
LinearMomentum - University of Colorado Boulder
... Definition: Total momentum of several masses: m1 with velocity v1 , m2 with velocity v2, etc.. ...
... Definition: Total momentum of several masses: m1 with velocity v1 , m2 with velocity v2, etc.. ...
Exam 1 - RIT
... “RIFLE PROBLEM” At t = 0, a rifle is fired horizontally at a target which is at the same level as the rifle; the target, mounted on a wall, is 30.5 m from the end of the rifle. The bullet strikes the wall at a distance of 7.62 cm below the center of the target. (a) Make a sketch of the rifle, the ta ...
... “RIFLE PROBLEM” At t = 0, a rifle is fired horizontally at a target which is at the same level as the rifle; the target, mounted on a wall, is 30.5 m from the end of the rifle. The bullet strikes the wall at a distance of 7.62 cm below the center of the target. (a) Make a sketch of the rifle, the ta ...
Chapter 4 Force Lecture Notes
... b. Which of Newton’s Laws best applies? 7. Two separate objects are seen moving at the same rate of acceleration. a. What can be concluded about the force causing their acceleration. b. Which of Newton’s Law best applies? ...
... b. Which of Newton’s Laws best applies? 7. Two separate objects are seen moving at the same rate of acceleration. a. What can be concluded about the force causing their acceleration. b. Which of Newton’s Law best applies? ...
Chapter 15
... equilibrium position, the origin, at t = 0 and moves to the right. The amplitude of its motion is 2.00 cm, and the frequency is 1.50 Hz. (a) Show that the position of the particle is given by x = (2.00 cm) sin (3.00 π t). Determine (b) the maximum speed and the earliest time (t > 0) at which the par ...
... equilibrium position, the origin, at t = 0 and moves to the right. The amplitude of its motion is 2.00 cm, and the frequency is 1.50 Hz. (a) Show that the position of the particle is given by x = (2.00 cm) sin (3.00 π t). Determine (b) the maximum speed and the earliest time (t > 0) at which the par ...
Chapter 7 Impulse and Momentum continued
... External forces – Forces exerted on the objects by agents external to the system. Net force changes the velocity (and momentum) of a mass. ...
... External forces – Forces exerted on the objects by agents external to the system. Net force changes the velocity (and momentum) of a mass. ...
4-6 - mrhsluniewskiscience
... and objects at rest tend to stay at rest unless acted upon by an unbalanced force. Newton’s Second Law: Force equals mass times acceleration (F = ma).` Newton’s Third Law: For every action there is an equal and opposite reaction. ...
... and objects at rest tend to stay at rest unless acted upon by an unbalanced force. Newton’s Second Law: Force equals mass times acceleration (F = ma).` Newton’s Third Law: For every action there is an equal and opposite reaction. ...
6.4 Friction 6 Newton`s Second Law of Motion
... Both liquids and gases are called fluids because they flow. • Fluid friction occurs as an object pushes aside the fluid it is moving through. • The friction of liquids is appreciable, even at low speeds. • Air resistance is the friction acting on something moving through air. ...
... Both liquids and gases are called fluids because they flow. • Fluid friction occurs as an object pushes aside the fluid it is moving through. • The friction of liquids is appreciable, even at low speeds. • Air resistance is the friction acting on something moving through air. ...
Chapter 10: Energy, Work and Simple Machines
... opposing force equals the change in kinetic energy. 4.state and apply the relationship that work done against gravity equals the change in gravitational potential energy. 5.Define and calculate power from calculating the amount of work done by an object. ...
... opposing force equals the change in kinetic energy. 4.state and apply the relationship that work done against gravity equals the change in gravitational potential energy. 5.Define and calculate power from calculating the amount of work done by an object. ...
Linear Momentum
... • If your car runs into a brick wall and you come to rest along with the car, there is a significant change in momentum. If you are wearing a seat belt or if the car has an air bag, your change in momentum occurs over a relatively long time ...
... • If your car runs into a brick wall and you come to rest along with the car, there is a significant change in momentum. If you are wearing a seat belt or if the car has an air bag, your change in momentum occurs over a relatively long time ...
POP4e: Ch. 1 Problems
... necessarily true because the angle of the incline is unknown. (e) None of these statements is necessarily true because the mass of one block is not given. Since the rollers on the ramp used by David were frictionless, he did not do any work overcoming nonconservative forces as he slid the block up t ...
... necessarily true because the angle of the incline is unknown. (e) None of these statements is necessarily true because the mass of one block is not given. Since the rollers on the ramp used by David were frictionless, he did not do any work overcoming nonconservative forces as he slid the block up t ...
