Section 8-2 Center of Mass
... a. Net torque produces rotation b. Occurs around an axis of rotation – usually a hinge. i. Imaginary line passing through a hinge 2. Torque depends on force and lever arm a. Ease of rotation depends on: i. How much force is applied ii. Where the force is applied 1. Farther from the axis of rotation ...
... a. Net torque produces rotation b. Occurs around an axis of rotation – usually a hinge. i. Imaginary line passing through a hinge 2. Torque depends on force and lever arm a. Ease of rotation depends on: i. How much force is applied ii. Where the force is applied 1. Farther from the axis of rotation ...
2012 - 2013 Study Guide
... 2. Why does an astronaut weigh less on the moon than on Earth? a. The astronaut has less mass on the moon. b. The astronaut is farther from Earth’s center when he or she is on the moon. c. The gravitational field strength is less on the moon’s surface than on Earth’s surface. d. The astronaut is con ...
... 2. Why does an astronaut weigh less on the moon than on Earth? a. The astronaut has less mass on the moon. b. The astronaut is farther from Earth’s center when he or she is on the moon. c. The gravitational field strength is less on the moon’s surface than on Earth’s surface. d. The astronaut is con ...
Chapter 1
... but varies directly with position D) requires a force which is not constant, but varies inversely with position ...
... but varies directly with position D) requires a force which is not constant, but varies inversely with position ...
Second practice midetrm key (Word document)
... Evaluate at t= .4756 Dy/dt = -2.846 m/s If a ball was released from rest and fell 41cm before striking the lab table, how long would that fall take? T = sqrt (2 * h /g) = sqrt (2 *.41 /9.8) = 0.289 s If the initial velocity were 3.15 m/s, what would be the theoretical range be if the ball was shot a ...
... Evaluate at t= .4756 Dy/dt = -2.846 m/s If a ball was released from rest and fell 41cm before striking the lab table, how long would that fall take? T = sqrt (2 * h /g) = sqrt (2 *.41 /9.8) = 0.289 s If the initial velocity were 3.15 m/s, what would be the theoretical range be if the ball was shot a ...
Forces - Canyon ISD
... From the units of mass and acceleration you can see that the units for force are kg m/s2 = N (Newton). 1 Newton is a little less than ¼ lb. Newton’s Third Law—action-reaction [F12=-F21] Newton’s 3rd law states that whenever an object exerts a force on a second object, the second object exerts an e ...
... From the units of mass and acceleration you can see that the units for force are kg m/s2 = N (Newton). 1 Newton is a little less than ¼ lb. Newton’s Third Law—action-reaction [F12=-F21] Newton’s 3rd law states that whenever an object exerts a force on a second object, the second object exerts an e ...
ch4-review
... Fg is greater on the feather Fg is greater on the stone Fg is zero on both due to the vacuum Fg is equal on both always Fg is zero on both always ...
... Fg is greater on the feather Fg is greater on the stone Fg is zero on both due to the vacuum Fg is equal on both always Fg is zero on both always ...
Kinematics - Vicphysics
... You need to be able to use a wide range of graphs. When given a graph in the exam, look for the following on the graph before even reading the question: type of graph (F – d, F – v, Energy – distance, F – t etc.). the units on the axis. the limit reading on each axis. Look at the scale on bo ...
... You need to be able to use a wide range of graphs. When given a graph in the exam, look for the following on the graph before even reading the question: type of graph (F – d, F – v, Energy – distance, F – t etc.). the units on the axis. the limit reading on each axis. Look at the scale on bo ...
File
... • B5.3 A car is travelling around a flat curve of radius 0.25km. The coefficient of static friction between the tires and the road is 0.4. At what speed will the car begin to skid? Ans: 31.30m/s • B5.4 A racing car travels around a curve of radius 1000m. If the frictional force is zero and the spee ...
... • B5.3 A car is travelling around a flat curve of radius 0.25km. The coefficient of static friction between the tires and the road is 0.4. At what speed will the car begin to skid? Ans: 31.30m/s • B5.4 A racing car travels around a curve of radius 1000m. If the frictional force is zero and the spee ...
unit 2 universal gravitation and circular motion
... Satellites are objects that are projected into space They are at a constant height above the planet and are in uniform circular motion The force of gravity keeps the satellite in orbit around the earth (or any other planet) ...
... Satellites are objects that are projected into space They are at a constant height above the planet and are in uniform circular motion The force of gravity keeps the satellite in orbit around the earth (or any other planet) ...
Free fall
In Newtonian physics, free fall is any motion of a body where its weight is the only force acting upon it. In the context of general relativity, where gravitation is reduced to a space-time curvature, a body in free fall has no force acting on it and it moves along a geodesic. The present article only concerns itself with free fall in the Newtonian domain.An object in the technical sense of free fall may not necessarily be falling down in the usual sense of the term. An object moving upwards would not normally be considered to be falling, but if it is subject to the force of gravity only, it is said to be in free fall. The moon is thus in free fall.In a uniform gravitational field, in the absence of any other forces, gravitation acts on each part of the body equally and this is weightlessness, a condition that also occurs when the gravitational field is zero (such as when far away from any gravitating body). A body in free fall experiences ""0 g"".The term ""free fall"" is often used more loosely than in the strict sense defined above. Thus, falling through an atmosphere without a deployed parachute, or lifting device, is also often referred to as free fall. The aerodynamic drag forces in such situations prevent them from producing full weightlessness, and thus a skydiver's ""free fall"" after reaching terminal velocity produces the sensation of the body's weight being supported on a cushion of air.