lab #4 - Physics Department, Princeton University
... launching the cart on a path more nearly parallel to the backdrop. If you haven’t already done so, multiply your x- and y-data by your scale factor to convert them to cm (or m). To find the factor k of the wheels and the coefficient r of rolling friction according to the formulae of part A, you ne ...
... launching the cart on a path more nearly parallel to the backdrop. If you haven’t already done so, multiply your x- and y-data by your scale factor to convert them to cm (or m). To find the factor k of the wheels and the coefficient r of rolling friction according to the formulae of part A, you ne ...
Ch. 4,5,6 ------------------- Forces, Circular Motion, Energy
... 17. (2) T F When a mass is moved to a higher altitude, its gravitational PE increases. 18. (2) T F Friction is an example of a non-conservative force. 19. (2) T F Friction acting on a mass always does negative work. 20. (2) T F When you drive a car down a hill, gravity does no work on the car. 21. ( ...
... 17. (2) T F When a mass is moved to a higher altitude, its gravitational PE increases. 18. (2) T F Friction is an example of a non-conservative force. 19. (2) T F Friction acting on a mass always does negative work. 20. (2) T F When you drive a car down a hill, gravity does no work on the car. 21. ( ...
AP Physics 1 Student Sample Question 1
... center and directed downward For labeled arrows representing the friction and normal forces or a single arrow representing the resultant of the friction and normal forces (i.e., the force exerted on the wheel by the surface), with no extraneous forces The friction force should start at the wheel-ram ...
... center and directed downward For labeled arrows representing the friction and normal forces or a single arrow representing the resultant of the friction and normal forces (i.e., the force exerted on the wheel by the surface), with no extraneous forces The friction force should start at the wheel-ram ...
B. Multiple Choice Questions
... 4. Block A is heavier than Block B. The force F is the same in both configurations. The surface is frictionless. The acceleration of Block A A.) is larger than Block B. A B.) is smaller than Block B. F C.) is the same as Block B. D.) can not be determined. E.) none of the above. F ...
... 4. Block A is heavier than Block B. The force F is the same in both configurations. The surface is frictionless. The acceleration of Block A A.) is larger than Block B. A B.) is smaller than Block B. F C.) is the same as Block B. D.) can not be determined. E.) none of the above. F ...
Prep-Physics Practice Final Exam Free body diagram 1. Dale skis
... acting on the box, and the coefficient of kinetic friction is 0.25. What is the force of friction acting on the box as it slides across a wooden floor? 12. A box of mass 15 kg slides across the ground with a frictional force of 80 N what is µk between the box and the ground? 13. A box of mass 15 kg ...
... acting on the box, and the coefficient of kinetic friction is 0.25. What is the force of friction acting on the box as it slides across a wooden floor? 12. A box of mass 15 kg slides across the ground with a frictional force of 80 N what is µk between the box and the ground? 13. A box of mass 15 kg ...
L3b--09-20--Friction and Drag
... As you know, whenever two solid objects are in contact there is a “pushing force” (normal force) between the objects that acts perpendicular to the plane of contact between the objects. In many circumstances, there is also a force that acts parallel to the plane of contact between two objects. This ...
... As you know, whenever two solid objects are in contact there is a “pushing force” (normal force) between the objects that acts perpendicular to the plane of contact between the objects. In many circumstances, there is also a force that acts parallel to the plane of contact between two objects. This ...
Reading materials
... Step 2 - What is the force of friction acting on the box if you push horizontally on the box with a force of 10 N, as in Figure 5.3a? Nothing has changed vertically, so we still have FN = mg = 40 N . To determine whether or not the box moves, let’s use equation 5.2 to determine the maximum possible ...
... Step 2 - What is the force of friction acting on the box if you push horizontally on the box with a force of 10 N, as in Figure 5.3a? Nothing has changed vertically, so we still have FN = mg = 40 N . To determine whether or not the box moves, let’s use equation 5.2 to determine the maximum possible ...
Steps to Solving Newtons Laws Problems.
... 4) A box initially at rest on a level floor is being acted on by a variable horizontal ...
... 4) A box initially at rest on a level floor is being acted on by a variable horizontal ...
how pre-service physics teachers interpret static and kinetic friction
... concepts about the friction force, the difference between static and kinetic friction, and factors that needs to be investigated in the worksheet. But, they experienced some confusion about their results of the surface area of the same object which is in contact with the surface. They did not much m ...
... concepts about the friction force, the difference between static and kinetic friction, and factors that needs to be investigated in the worksheet. But, they experienced some confusion about their results of the surface area of the same object which is in contact with the surface. They did not much m ...
Homework 5 - Physics | Oregon State University
... At this point, the problem reduces to geometry: Given the directions of vectors ~g , ~a and ~g − ~a and the magnitude g = 9.8 m/s2 , find the magnitude a. We can solve this question using the sine theorem, but it is just as easy to solve in Carthesian coordinates. Let the x axis run uphull along the ...
... At this point, the problem reduces to geometry: Given the directions of vectors ~g , ~a and ~g − ~a and the magnitude g = 9.8 m/s2 , find the magnitude a. We can solve this question using the sine theorem, but it is just as easy to solve in Carthesian coordinates. Let the x axis run uphull along the ...
I. Force, Mass, and Acceleration
... º Think of a car stuck in the mud or on ice – what do you usually do to help them? – Gravel gets put down so friction is increased. º Rolling friction – friction between a rolling object and the surface its rolling on. º Microwelds break and reform as wheel rolls. º Usually less than sliding or stat ...
... º Think of a car stuck in the mud or on ice – what do you usually do to help them? – Gravel gets put down so friction is increased. º Rolling friction – friction between a rolling object and the surface its rolling on. º Microwelds break and reform as wheel rolls. º Usually less than sliding or stat ...
HW4 - due 6 pm Day 8 (Wed. Aug. 6)
... A contestant in a winter games event pushes a 53.0 kg block of ice across a frozen lake with a rope over his shoulder as shown in Figure 4.29(b). The coefficient of static friction is 0.1 and the coefficient of kinetic friction is 0.03. ...
... A contestant in a winter games event pushes a 53.0 kg block of ice across a frozen lake with a rope over his shoulder as shown in Figure 4.29(b). The coefficient of static friction is 0.1 and the coefficient of kinetic friction is 0.03. ...
Work-Energy Theorem and Conservation of Energy
... Particular physical motion can also be described by the work-energy theorem, which reads (KEf + PEf) - (KEi + PEi) = W. The KE and PE represent kinetic and potential energies, and the subscript f and i are final and initial. In the right hand side of the equation, W is the work done by frictional or ...
... Particular physical motion can also be described by the work-energy theorem, which reads (KEf + PEf) - (KEi + PEi) = W. The KE and PE represent kinetic and potential energies, and the subscript f and i are final and initial. In the right hand side of the equation, W is the work done by frictional or ...
Force
... friction must be equal to the push, pull, component of gravity or other force that attempts to move the object. (If there is no force attempting to cause motion, then there can be no friction). Static friction is the strongest type of friction since the surfaces have a stronger adherence when statio ...
... friction must be equal to the push, pull, component of gravity or other force that attempts to move the object. (If there is no force attempting to cause motion, then there can be no friction). Static friction is the strongest type of friction since the surfaces have a stronger adherence when statio ...
law 1
... Inertia Example: Quarters on a toy car. When the toy car bumps into the wall the car stops but the quarter keep moving in the same direction. A force was applied to the car to stop it but no force was applied to the quarters. ...
... Inertia Example: Quarters on a toy car. When the toy car bumps into the wall the car stops but the quarter keep moving in the same direction. A force was applied to the car to stop it but no force was applied to the quarters. ...
8.1 Characteristics of Dry Friction
... found using Fs = s N, where s is called the coefficient of static friction. The value of s depends on the two materials in contact. Once the block begins to move, the frictional force typically drops and is given by Fk = k N. The value of k (coefficient of kinetic friction) is less than s . St ...
... found using Fs = s N, where s is called the coefficient of static friction. The value of s depends on the two materials in contact. Once the block begins to move, the frictional force typically drops and is given by Fk = k N. The value of k (coefficient of kinetic friction) is less than s . St ...
Chapter 11: Force and Newton*s Laws
... 2. When forces are ___balanced____ forces, they cancel each other out and do not change an object’s motion; when forces are _____unbalanced______forces, the motion of an object changes. B. Newton’s ____first law_____ of motion - an object will remain at rest or move with constant speed unless a net ...
... 2. When forces are ___balanced____ forces, they cancel each other out and do not change an object’s motion; when forces are _____unbalanced______forces, the motion of an object changes. B. Newton’s ____first law_____ of motion - an object will remain at rest or move with constant speed unless a net ...
Newton`s First Law of Motion
... Identify at least five pairs of action-reaction forces in the following diagram. ...
... Identify at least five pairs of action-reaction forces in the following diagram. ...
