notes about solving friction problems
... a unitless number that tells us how rough the two surfaces are. The coefficient of friction is different for different surfaces; it can never be below zero and is usually less than 1. The coefficient of friction for rubber tires on pavement is about 0.8; for skates on ice it is about 0.1. Our Toolbo ...
... a unitless number that tells us how rough the two surfaces are. The coefficient of friction is different for different surfaces; it can never be below zero and is usually less than 1. The coefficient of friction for rubber tires on pavement is about 0.8; for skates on ice it is about 0.1. Our Toolbo ...
Preview Sample 1
... Free-body diagrams including third-law forces (statics). Have the students draw yet more free-body diagrams; in each, identify all forces on the primary object, label each, and identify what object is exerting the force. Then draw, in separate diagrams, the forces exerted by the primary object on al ...
... Free-body diagrams including third-law forces (statics). Have the students draw yet more free-body diagrams; in each, identify all forces on the primary object, label each, and identify what object is exerting the force. Then draw, in separate diagrams, the forces exerted by the primary object on al ...
Powerpoint revew chap4 no solutions
... This work is protected by United States copyright laws and is provided solely for the use of instructors in teaching their courses and assessing student learning. Dissemination or sale of any part of this work (including on the World Wide Web) will destroy the integrity of the work and is not permit ...
... This work is protected by United States copyright laws and is provided solely for the use of instructors in teaching their courses and assessing student learning. Dissemination or sale of any part of this work (including on the World Wide Web) will destroy the integrity of the work and is not permit ...
Forces - Weebly
... different size collide, the forces on each are the SAME (but in opposite directions). However, the same force on a smaller car means a bigger acceleration! ...
... different size collide, the forces on each are the SAME (but in opposite directions). However, the same force on a smaller car means a bigger acceleration! ...
Summary of Chapters 1-3 Equations of motion for a uniformly accelerating object
... the gravity force pulling the mass down the ramp? As you slowly put the mass on the ramp, the ramp compresses & stretches along the ramp as gravity tries to slide the mass down the ramp. When you let go, the ramp has stretched enough to push on the mass with EXACTLY the right amount of force up the ...
... the gravity force pulling the mass down the ramp? As you slowly put the mass on the ramp, the ramp compresses & stretches along the ramp as gravity tries to slide the mass down the ramp. When you let go, the ramp has stretched enough to push on the mass with EXACTLY the right amount of force up the ...
Circular Motion
... Problem: For a car traveling at speed v around a curve of radius r, what is the banking angle for which no friction is required? What is the angle for a 50km/hr (14m/s) off ramp with radius 50m? To the free-body diagram! Note that we’ve picked an unusual coordinate system. Not down the inclined pl ...
... Problem: For a car traveling at speed v around a curve of radius r, what is the banking angle for which no friction is required? What is the angle for a 50km/hr (14m/s) off ramp with radius 50m? To the free-body diagram! Note that we’ve picked an unusual coordinate system. Not down the inclined pl ...
net force
... In order for sink a ship in the harbor, a cannon ball of 25kg must be accelerated at 44m/s2. How much force is required to hit the ship? ...
... In order for sink a ship in the harbor, a cannon ball of 25kg must be accelerated at 44m/s2. How much force is required to hit the ship? ...
unit 6: gravity and projectile motion
... (d) Although you only made a casual qualitative observation of the objects you dropped, it turns out that in the absence of air resistance or other sources of friction all objects accelerate at the rate of g = 9.8 m/s2 close to the surface of the earth. There are small variations from place to place ...
... (d) Although you only made a casual qualitative observation of the objects you dropped, it turns out that in the absence of air resistance or other sources of friction all objects accelerate at the rate of g = 9.8 m/s2 close to the surface of the earth. There are small variations from place to place ...
Exam 1
... 1) (5pts)If gravitation in the atom is 1039 times weaker than the electrostatic force, why is it that gravity dominates over the large scale of the universe? a) the electrostatic force is a short range force b) gravitation acts over a larger distance than electrostatics c) electrostatics doesn’t act ...
... 1) (5pts)If gravitation in the atom is 1039 times weaker than the electrostatic force, why is it that gravity dominates over the large scale of the universe? a) the electrostatic force is a short range force b) gravitation acts over a larger distance than electrostatics c) electrostatics doesn’t act ...
Kinetic Energy and Work
... Note 1:The expressions for work we have developed apply when F is constant. Note 2:We have made the implicit assumption that the moving object is point-like. Note 3: W > 0 if 0 < φ < 90°, W < 0 if 90° < φ < 180°. Net Work: If we have several forces acting on a body (say three as in the picture) ther ...
... Note 1:The expressions for work we have developed apply when F is constant. Note 2:We have made the implicit assumption that the moving object is point-like. Note 3: W > 0 if 0 < φ < 90°, W < 0 if 90° < φ < 180°. Net Work: If we have several forces acting on a body (say three as in the picture) ther ...
Luna Park Physics
... and the barrier, both of which are ‘springy’. The force here is not constant, it will increase rapidly with the amount of compression of both the bumper and barrier. However, if we can estimate the amount of compression, and know the mass and speed of the Dodgem we can find a figure for the average ...
... and the barrier, both of which are ‘springy’. The force here is not constant, it will increase rapidly with the amount of compression of both the bumper and barrier. However, if we can estimate the amount of compression, and know the mass and speed of the Dodgem we can find a figure for the average ...
