CCGPS Culminating Task
... congruent; when a transversal crosses parallel lines, alternate interior angles are congruent and corresponding angles are congruent; points on a perpendicular bisector of a line segment are exactly those equidistant from the segment’s endpoints. MCC9-12.G.CO.10 Prove theorems about triangles. Theor ...
... congruent; when a transversal crosses parallel lines, alternate interior angles are congruent and corresponding angles are congruent; points on a perpendicular bisector of a line segment are exactly those equidistant from the segment’s endpoints. MCC9-12.G.CO.10 Prove theorems about triangles. Theor ...
included angle
... • Adjacent triangles share a COMMON SIDE, so you can apply the REFLEXIVE Property to get a pair of congruent sides. • Look for SEGMENT BISECTORS.. They lead to MIDPOINTS…. Which lead to congruent segments. ...
... • Adjacent triangles share a COMMON SIDE, so you can apply the REFLEXIVE Property to get a pair of congruent sides. • Look for SEGMENT BISECTORS.. They lead to MIDPOINTS…. Which lead to congruent segments. ...
unit 4: geometry study guide
... It is an acute angle. It is a right angle. It is an obtuse angle. It is a straight angle. ...
... It is an acute angle. It is a right angle. It is an obtuse angle. It is a straight angle. ...
unit 5: geometry study guide
... It is an acute angle. It is a right angle. It is an obtuse angle. It is a straight angle. ...
... It is an acute angle. It is a right angle. It is an obtuse angle. It is a straight angle. ...
Algebra 3 – Final Exam Review Name
... Suppose on a map, 2.5 inches represents 520 miles. If the distance between Philadelphia and Nashville on the map measures 4.125 inches, find the actual distance between the two cities in miles. (Write a proportion and then solve.) ...
... Suppose on a map, 2.5 inches represents 520 miles. If the distance between Philadelphia and Nashville on the map measures 4.125 inches, find the actual distance between the two cities in miles. (Write a proportion and then solve.) ...
9 Harmonic Points
... u + v < 2R, the two angles u and v cannot be supplementary. Hence we get u = v, as to be shown. ”(2) ↔ (2 )”: Follows at once from the assumption that A, B, X, Y are harmonic points. We see with a similar argument that (1) ↔ (2 ). Hence all four statements (1),(1’),(2) and (2’) are equivalent. ”(1 ...
... u + v < 2R, the two angles u and v cannot be supplementary. Hence we get u = v, as to be shown. ”(2) ↔ (2 )”: Follows at once from the assumption that A, B, X, Y are harmonic points. We see with a similar argument that (1) ↔ (2 ). Hence all four statements (1),(1’),(2) and (2’) are equivalent. ”(1 ...
