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... ∠QCD = ∠QBD ..(ii) [Angles in the same segment] But, ∠ABP = ∠QBD ..(iii) [Vertically opposite angles] By (i), (ii) and (ii) we get ∠ACP = ∠QCD Proved. If circles are drawn taking two sides of a triangle as diameters, prove that the point of intersection of these circles lie on the third side. Given ...
... ∠QCD = ∠QBD ..(ii) [Angles in the same segment] But, ∠ABP = ∠QBD ..(iii) [Vertically opposite angles] By (i), (ii) and (ii) we get ∠ACP = ∠QCD Proved. If circles are drawn taking two sides of a triangle as diameters, prove that the point of intersection of these circles lie on the third side. Given ...
( ) Chapter 5
... angles is 32° and the third angle which is adjacent tot he exterior angle has a measure of 180° − 32° = 148°. These are known because of the conjectures made in Explorations 1 and 2. 5.1 Monitoring Progress (pp. 232–235) 1. Sample answer: Obtuse isosceles triangle: ...
... angles is 32° and the third angle which is adjacent tot he exterior angle has a measure of 180° − 32° = 148°. These are known because of the conjectures made in Explorations 1 and 2. 5.1 Monitoring Progress (pp. 232–235) 1. Sample answer: Obtuse isosceles triangle: ...
