ExamView - geometry review for final chapters 5 and 6 .tst
... 51. yes; Because point P is equidistant from L and M , point P is on the perpendicular bisector of LM by the Converse of the Perpendicular Bisector Theorem. Also, LN ≅ MN , so PN is a bisector of LM . Because P can only be on one of the bisectors, PN is the perpendicular bisector of LM . 52. The fir ...
... 51. yes; Because point P is equidistant from L and M , point P is on the perpendicular bisector of LM by the Converse of the Perpendicular Bisector Theorem. Also, LN ≅ MN , so PN is a bisector of LM . Because P can only be on one of the bisectors, PN is the perpendicular bisector of LM . 52. The fir ...
Solutions to USC’s 21st High School Math Contest
... x, then x − 0.25x = 5k, so x = 20k/3. 18. (e) 0 = (x − 1)(x2 + x + 1) = x3 − 1. Thus, x3 = 1, and (1 + 1)3 = 8. 19. (d) The last digit of 11n − 1 is 0, so 5 always divides 11n − 1. Also, checking the remainders when the powers of 11 are divided by 3 and 7 we get that 3 divides 11n − 1 exactly when n ...
... x, then x − 0.25x = 5k, so x = 20k/3. 18. (e) 0 = (x − 1)(x2 + x + 1) = x3 − 1. Thus, x3 = 1, and (1 + 1)3 = 8. 19. (d) The last digit of 11n − 1 is 0, so 5 always divides 11n − 1. Also, checking the remainders when the powers of 11 are divided by 3 and 7 we get that 3 divides 11n − 1 exactly when n ...
TryAngle? - TI Education
... down in the second column, second row as 111. Next ask the students to tell all their sets that have a 2" side. Write these sets on board as 3-digit numbers, then go back and order them in ascending order. When you get to the 3" sides, tell students that we can not re-use triangles with 2" sides. Su ...
... down in the second column, second row as 111. Next ask the students to tell all their sets that have a 2" side. Write these sets on board as 3-digit numbers, then go back and order them in ascending order. When you get to the 3" sides, tell students that we can not re-use triangles with 2" sides. Su ...
Quadrature of the parabola with the square pyramidal number
... Split the segments AB and BC into six equal parts and lead, from split points on AB parallels to BC, and from points on BC lines joining with A. The parabola passes through the points of intersection of the grid, as drawn, because, for one of its properties, it cuts the vertical lines of the grid in ...
... Split the segments AB and BC into six equal parts and lead, from split points on AB parallels to BC, and from points on BC lines joining with A. The parabola passes through the points of intersection of the grid, as drawn, because, for one of its properties, it cuts the vertical lines of the grid in ...
Generic Lesson Plan Format
... Print Resources: Websites that contain different activities for helping students learn how to classify triangles according to their sides and angles (eDhelper.com), middle school textbooks for teaching about polygons and geometry (NCTM Process Standards textbook), websites containing helpful informa ...
... Print Resources: Websites that contain different activities for helping students learn how to classify triangles according to their sides and angles (eDhelper.com), middle school textbooks for teaching about polygons and geometry (NCTM Process Standards textbook), websites containing helpful informa ...
