Trigonometry for Physics
... If the projectile lands at the same elevation as its starting point, it will have the same final vertical SPEED as initial (opposite velocity) 9) The time it takes to get to the top of its path is the same as the time to get from the top back to the ground. 10) The range of the projectile (where it ...
... If the projectile lands at the same elevation as its starting point, it will have the same final vertical SPEED as initial (opposite velocity) 9) The time it takes to get to the top of its path is the same as the time to get from the top back to the ground. 10) The range of the projectile (where it ...
Proving a Rectangle Is a Parallelogram
... Note: Remind the student that a theorem cannot be used in its own proof. If necessary, review the theorems that have been proved prior to the introduction of this theorem so that the student understands which theorems can be used in this proof. Also, proofs may vary from what is shown in this rubric ...
... Note: Remind the student that a theorem cannot be used in its own proof. If necessary, review the theorems that have been proved prior to the introduction of this theorem so that the student understands which theorems can be used in this proof. Also, proofs may vary from what is shown in this rubric ...
Geometry
... sum to 180°; base angles of isosceles triangles are congruent; the segment joining midpoints of two sides of a triangle is parallel to the third side and half the length; the medians of a triangle meet at a point. G-CO.11 Prove theorems about parallelograms. Theorems include: opposite sides are cong ...
... sum to 180°; base angles of isosceles triangles are congruent; the segment joining midpoints of two sides of a triangle is parallel to the third side and half the length; the medians of a triangle meet at a point. G-CO.11 Prove theorems about parallelograms. Theorems include: opposite sides are cong ...
274 Curves on Surfaces, Lecture 5
... Lemma 5.5. Any three choices `(A), `(B), `(C) ∈ R of lengths is realizable by a unique decorated ideal triangle (up to isometry). Proof. We first consider the case where all three lengths are equal to 0. This means that the horocycles are all tangent to each other as well as to the ideal boundary. T ...
... Lemma 5.5. Any three choices `(A), `(B), `(C) ∈ R of lengths is realizable by a unique decorated ideal triangle (up to isometry). Proof. We first consider the case where all three lengths are equal to 0. This means that the horocycles are all tangent to each other as well as to the ideal boundary. T ...
