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PHYS - 321 ELEMENTARY ELECTRONiCS
PHYS - 321 ELEMENTARY ELECTRONiCS

... Voltage drop on ith resistor is proportional to ratio of Ri to Rtot! Vi = {Ri/Rtot} V ΔV1 ={R1/(R1+R2)} V ΔV2 ={R2/(R1+R2)} V ...
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... Ohm's Law states that the voltage across a conductor is proportional to the current in the conductor: V=IR, where V is the voltage in volts, I is the current in am peres, and R is the proportionality constant which is known as the resistance of the conductor whose unit is in ohms. The power dissipat ...


... With the current moving counter clockwise because of the direction of the voltage sources. Now in order to calculate the potential difference between B and A, all we have to do is calculate the voltage between these points: VBA = ε1 − I(R1 + R2 ) = 1 − I = 0.515 V ...
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... ( I ) Current is what flows on a wire or conductor like water flowing down a river. Current flows from negative to positive on the surface of a conductor. Current is measured in (A) amperes or amps. ( E ) Voltage is the difference in electrical potential between two points in a circuit. It's the pus ...
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... 3. A string of fifty 15 ohm Christmas tree lights are connected in series. One burns out, they all burn out. Calculate the total resistance. 4. Calculate the total resistance for two 180 ohm resistors connected in parallel. 5. A 10 ohm, 20 ohm, and 100 ohm resistors are connected in parallel. Calcul ...
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... 2. A single-phase transformer used for lighting circuit on board ship has 1000 turns on the primary and 200 turns on the secondary. The no load current is 3A at 0.2 power factor lag when the secondary current is 280A at a power factor of 0.8 lagging. Assume the voltage drop in the winding to be negl ...
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... where J=Nqu (A/m2) is the volume current density or simply current density. It can be justified analytically that for most conducting materials the average drift velocity is directly proportional to the applied external electric field strength, or u=−µeE, where µe is the mobility of electrons in a c ...
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... electric field due to some geometry of charge. If a “Gaussian Surface” is picked carefully such that the E-field has uniform intensity at all points, E comes out of the integral. Implies that if qencl = 0, the E-field must also be zero. Never, unless to prove no Bmonopoles. Not to be confused with a ...
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Ohm's law

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