Divisibility Math Tricks to Learn the Facts (Divisibility)
... Take the last digit in a number. Double and subtract the last digit from the rest of the digits. Example: 357 (Double 7 to get 14. Subtract 14 from 35 to get 21 which is divisible by 7; therefore, 357 is divisible by 7. ...
... Take the last digit in a number. Double and subtract the last digit from the rest of the digits. Example: 357 (Double 7 to get 14. Subtract 14 from 35 to get 21 which is divisible by 7; therefore, 357 is divisible by 7. ...
Wilson Theorems for Double-, Hyper-, Sub-and Super
... elements listed in natural order. Then s! = r1 r2 . . . rs−N n1 n2 . . . nN ≡ (−1)N r1 r2 . . . rs , where N denotes the number of nonquadratic residues j < 2p . As p ≡ 3 (mod 4), one has r1 r2 . . . rs ≡ 1; see [22, p. 75]. Hence s! ≡ (−1)N . Thus by Remark 2, (p − 1)!! ≡ 1 if and only if either 2 ...
... elements listed in natural order. Then s! = r1 r2 . . . rs−N n1 n2 . . . nN ≡ (−1)N r1 r2 . . . rs , where N denotes the number of nonquadratic residues j < 2p . As p ≡ 3 (mod 4), one has r1 r2 . . . rs ≡ 1; see [22, p. 75]. Hence s! ≡ (−1)N . Thus by Remark 2, (p − 1)!! ≡ 1 if and only if either 2 ...
A Tale of Two Sieves - American Mathematical Society
... if n = ab where a and b are very close to n , as in the case of n = 8051 , it is easy to find the two squares. But in its worst cases, the difference-of-squares method can be far worse than trial division. It is worse in another way too. With trial division, most numbers fall into the easy case; nam ...
... if n = ab where a and b are very close to n , as in the case of n = 8051 , it is easy to find the two squares. But in its worst cases, the difference-of-squares method can be far worse than trial division. It is worse in another way too. With trial division, most numbers fall into the easy case; nam ...