Comparing Circle Parts
... Solving Equations and Inequalities Solving ________________ and ________________ are both done using inverse operations on both sides. The solutions look different, however, because ________________ have only a single answer while ________________ have a whole range of answers. These solutions can ...
... Solving Equations and Inequalities Solving ________________ and ________________ are both done using inverse operations on both sides. The solutions look different, however, because ________________ have only a single answer while ________________ have a whole range of answers. These solutions can ...
Full text
... We shall briefly discuss the equation (±a ± b)2 E 1 (mod ab) , equivalent to {a - b)2 E 1 (mod aZ?) , which we rewrite as a2 - kab + b2 = 1. In §1 we showed that this equation is solvable iff z2 - (k2 - 4)z/2 = +4 is solvable. The latter equation has an obvious solution, namely {z9 y)= (k, 1) . So w ...
... We shall briefly discuss the equation (±a ± b)2 E 1 (mod ab) , equivalent to {a - b)2 E 1 (mod aZ?) , which we rewrite as a2 - kab + b2 = 1. In §1 we showed that this equation is solvable iff z2 - (k2 - 4)z/2 = +4 is solvable. The latter equation has an obvious solution, namely {z9 y)= (k, 1) . So w ...
Graphs of Inequalities Solving Inequalities Using the Addition principle
... Solving Inequalities Using the Multiplication Principle Multiplication and Division Properties of Inequalities: Multiplying or dividing by the same positive number does not change the solutions. For any real numbers a; b; and c (where c is positive) : If we multiply or divide by a negative number, t ...
... Solving Inequalities Using the Multiplication Principle Multiplication and Division Properties of Inequalities: Multiplying or dividing by the same positive number does not change the solutions. For any real numbers a; b; and c (where c is positive) : If we multiply or divide by a negative number, t ...
A6 Quadratic equations
... The only solution that makes sense is x = 60 miles per hour. If Jenny’s average speed on the way to work was 8 miles per hour her average speed on the way home would be –12 miles per hour, a negative number. We can therefore ignore the second solution. When practical problems lead to quadratic equat ...
... The only solution that makes sense is x = 60 miles per hour. If Jenny’s average speed on the way to work was 8 miles per hour her average speed on the way home would be –12 miles per hour, a negative number. We can therefore ignore the second solution. When practical problems lead to quadratic equat ...
