
Math 601 Solutions to Homework 10
... So, λ1 λ2 = −6 and λ1 + λ2 = 1. By inspection we see that the eigenvalues are λ1 = 3 and λ2 = −2. (This method only works for 2 × 2 matrices.) Now, we find the eigenvectors associated with each eigenvalue. For λ1 = 3, we have: ...
... So, λ1 λ2 = −6 and λ1 + λ2 = 1. By inspection we see that the eigenvalues are λ1 = 3 and λ2 = −2. (This method only works for 2 × 2 matrices.) Now, we find the eigenvectors associated with each eigenvalue. For λ1 = 3, we have: ...
9.1
... Vectors in Two Dimensions In applications of mathematics, certain quantities are determined completely by their magnitude—for example, length, mass, area, temperature, and energy. We speak of a length of 5 m or a mass of 3 kg; only one number is needed to describe each of these quantities. Such a q ...
... Vectors in Two Dimensions In applications of mathematics, certain quantities are determined completely by their magnitude—for example, length, mass, area, temperature, and energy. We speak of a length of 5 m or a mass of 3 kg; only one number is needed to describe each of these quantities. Such a q ...