
Bonus page #2
... Where Etot = ES + EN is the electric field of the sphere as a whole. So why in the heck do we do this?? The reason is that the electric field of the sphere as a whole is incredibly easy to calculate – we use Gauss’ law here now that we have spherical symmetry. But now we have this extra term on the ...
... Where Etot = ES + EN is the electric field of the sphere as a whole. So why in the heck do we do this?? The reason is that the electric field of the sphere as a whole is incredibly easy to calculate – we use Gauss’ law here now that we have spherical symmetry. But now we have this extra term on the ...
answer
... A particle with unknown mass and charge is projected into the apparatus shown below. The particle moves with constant speed v as it passes undeflected through a pair of parallel plates, as shown above. The plates are separated by a distance d, and a constant potential difference V is maintained betw ...
... A particle with unknown mass and charge is projected into the apparatus shown below. The particle moves with constant speed v as it passes undeflected through a pair of parallel plates, as shown above. The plates are separated by a distance d, and a constant potential difference V is maintained betw ...
Homework No. 07 (2014 Fall) PHYS 320: Electricity and Magnetism I
... Use these to find the force on a point charge due to a point dipole. (c) Confirm that above two forces are equal in magnitude and opposite in direction, as per Newton’s third law. 2. (40 points.) (Based on Griffiths 3rd/4th ed., Problem 4.8.) We showed in class that the electric field of a point dip ...
... Use these to find the force on a point charge due to a point dipole. (c) Confirm that above two forces are equal in magnitude and opposite in direction, as per Newton’s third law. 2. (40 points.) (Based on Griffiths 3rd/4th ed., Problem 4.8.) We showed in class that the electric field of a point dip ...
Questions having one mark each: Write the S.I unit of i. electric field
... constant of the intervening medium? c. Draw an equipotential surface for a system, consisting of two charges Q, -Q separated by a distance ‘r’ apart. d. Show graphically the variation of charge ‘q’ with time’t’ when a condenser is charged. e. What orientation of an electric dipole in a uniform elect ...
... constant of the intervening medium? c. Draw an equipotential surface for a system, consisting of two charges Q, -Q separated by a distance ‘r’ apart. d. Show graphically the variation of charge ‘q’ with time’t’ when a condenser is charged. e. What orientation of an electric dipole in a uniform elect ...
Lab E2
... the magnitude of the charge are micro-Coulombs. You will need to use a ruler to measure the distance to point P from the charge. Show your measurement and calculation (including units for all numbers) on your printout, below the field line pattern. We are using real metric units for all numbers here ...
... the magnitude of the charge are micro-Coulombs. You will need to use a ruler to measure the distance to point P from the charge. Show your measurement and calculation (including units for all numbers) on your printout, below the field line pattern. We are using real metric units for all numbers here ...
Essentials of Electricity 1 - VCC Library
... Electric force is determined by the magnitude of each charge (q1 and q2) and the distance (r) between them. Greater charges mean stronger electric force and greater distances mean weaker electric force. Electric force, measured in newtons (N), can be calculated with Coulomb’s Law: FE = ...
... Electric force is determined by the magnitude of each charge (q1 and q2) and the distance (r) between them. Greater charges mean stronger electric force and greater distances mean weaker electric force. Electric force, measured in newtons (N), can be calculated with Coulomb’s Law: FE = ...
27.15. (a) Identify: Apply Eq.(27.2) to relate the magnetic force to the
... ohmic heating due to the resistance of the wire would be severe; such a current isn’t feasible. (b) The magnetic force must be upward. The directions of I, B and F are shown in Figure 27.33, where we have assumed that B is south to north. To produce an upward magnetic force, the current must be to t ...
... ohmic heating due to the resistance of the wire would be severe; such a current isn’t feasible. (b) The magnetic force must be upward. The directions of I, B and F are shown in Figure 27.33, where we have assumed that B is south to north. To produce an upward magnetic force, the current must be to t ...
Homework #8 203-1-1721 Physics... Part A
... 5. A cosmic ray proton (mp = 1.67 x 10-27 kg) strikes the Earth near the equator with a vertical velocity of 2.8 x 107 m/s. Assume that the horizontal component of the Earth's magnetic field at the equator is 30 µT. Calculate the ratio of the magnetic force on the proton to the gravitational force o ...
... 5. A cosmic ray proton (mp = 1.67 x 10-27 kg) strikes the Earth near the equator with a vertical velocity of 2.8 x 107 m/s. Assume that the horizontal component of the Earth's magnetic field at the equator is 30 µT. Calculate the ratio of the magnetic force on the proton to the gravitational force o ...
Midterm Exam No. 01 (Spring 2014)
... where n is the number of turns per unit length, I is the current, and n̂ points along the axis determined by the cross product of direction of radius vector and direction of current. (a) If you double the radius of the solenoid, how much does the magnetic field inside the solenoid change? (b) The fo ...
... where n is the number of turns per unit length, I is the current, and n̂ points along the axis determined by the cross product of direction of radius vector and direction of current. (a) If you double the radius of the solenoid, how much does the magnetic field inside the solenoid change? (b) The fo ...
Tuesday, October 23 rd
... Magnetic forces can only change the direction (of the Velocity) of charged particles. They cannot change the magnitude (of their velocity). Example: J.J. Thomson’s experiment (1897) for q/m 1. Determine v by measuring E/B: 2. Determine q/m by measuring R with E turned off. ...
... Magnetic forces can only change the direction (of the Velocity) of charged particles. They cannot change the magnitude (of their velocity). Example: J.J. Thomson’s experiment (1897) for q/m 1. Determine v by measuring E/B: 2. Determine q/m by measuring R with E turned off. ...
Electromagnetism - David Brotherton CCCMC
... given surface (such as a conducting coil). The SI unit of magnetic flux is the weber (in derived units: volt-seconds). The CGS unit is the Maxwell. EMF – Electromagnetic Field - In the past, electrically charged objects were thought to produce two different, unrelated types of field associated with ...
... given surface (such as a conducting coil). The SI unit of magnetic flux is the weber (in derived units: volt-seconds). The CGS unit is the Maxwell. EMF – Electromagnetic Field - In the past, electrically charged objects were thought to produce two different, unrelated types of field associated with ...
Electric Potential Energy
... The negative work done by the system is the positive work done on the system We can calculate the work from: W = DU = qDV ...
... The negative work done by the system is the positive work done on the system We can calculate the work from: W = DU = qDV ...
Lecture 3 ppt version
... The figure show the path of negatively charged particle 1 through a rectangular region of uniform electric field; the particle is deflected towards the top of the page. Is the field directed ...
... The figure show the path of negatively charged particle 1 through a rectangular region of uniform electric field; the particle is deflected towards the top of the page. Is the field directed ...
Electromagnetic Waves
... capacitor, we assume that the volume between the two plates can be replaced with a conductor of radius R carrying current id ! Thus from chapter 27 we know that the magnetic field at a distance from the center of the capacitor is given by ...
... capacitor, we assume that the volume between the two plates can be replaced with a conductor of radius R carrying current id ! Thus from chapter 27 we know that the magnetic field at a distance from the center of the capacitor is given by ...
General Physics II
... The electric force is the same in magnitude because both the proton and electron have the same magnitude of charge. Since they have different signs, though, the forces are in opposite directions. For the same force, the electron experiences a larger acceleration because it is much lighter than the ...
... The electric force is the same in magnitude because both the proton and electron have the same magnitude of charge. Since they have different signs, though, the forces are in opposite directions. For the same force, the electron experiences a larger acceleration because it is much lighter than the ...
Document
... An polarized material containing a lot of microscopic dipoles lined up where the polarization P is obtained from dipole moment per unit volume. The field produced by this polarization can be obtained by calculating the bound charges as follows ...
... An polarized material containing a lot of microscopic dipoles lined up where the polarization P is obtained from dipole moment per unit volume. The field produced by this polarization can be obtained by calculating the bound charges as follows ...
Field (physics)
In physics, a field is a physical quantity that has a value for each point in space and time. For example, on a weather map, the surface wind velocity is described by assigning a vector to each point on a map. Each vector represents the speed and direction of the movement of air at that point. As another example, an electric field can be thought of as a ""condition in space"" emanating from an electric charge and extending throughout the whole of space. When a test electric charge is placed in this electric field, the particle accelerates due to a force. Physicists have found the notion of a field to be of such practical utility for the analysis of forces that they have come to think of a force as due to a field.In the modern framework of the quantum theory of fields, even without referring to a test particle, a field occupies space, contains energy, and its presence eliminates a true vacuum. This lead physicists to consider electromagnetic fields to be a physical entity, making the field concept a supporting paradigm of the edifice of modern physics. ""The fact that the electromagnetic field can possess momentum and energy makes it very real... a particle makes a field, and a field acts on another particle, and the field has such familiar properties as energy content and momentum, just as particles can have"". In practice, the strength of most fields has been found to diminish with distance to the point of being undetectable. For instance the strength of many relevant classical fields, such as the gravitational field in Newton's theory of gravity or the electrostatic field in classical electromagnetism, is inversely proportional to the square of the distance from the source (i.e. they follow the Gauss's law). One consequence is that the Earth's gravitational field quickly becomes undetectable on cosmic scales.A field can be classified as a scalar field, a vector field, a spinor field or a tensor field according to whether the represented physical quantity is a scalar, a vector, a spinor or a tensor, respectively. A field has a unique tensorial character in every point where it is defined: i.e. a field cannot be a scalar field somewhere and a vector field somewhere else. For example, the Newtonian gravitational field is a vector field: specifying its value at a point in spacetime requires three numbers, the components of the gravitational field vector at that point. Moreover, within each category (scalar, vector, tensor), a field can be either a classical field or a quantum field, depending on whether it is characterized by numbers or quantum operators respectively. In fact in this theory an equivalent representation of field is a field particle, namely a boson.