vol 2 No 2.8 2005
... earthquake. This is due to dipole oscillations with the beginning of micro- fracturing process. Features of the emissions are: it has nonvanishing components for VLF region ( 30 KHz 3 KHz ), ELF region ( 3 KHz - 3 Hz) ,ULF region ( < 3 Hz ). Experimental evidence of EME before the fracture and at th ...
... earthquake. This is due to dipole oscillations with the beginning of micro- fracturing process. Features of the emissions are: it has nonvanishing components for VLF region ( 30 KHz 3 KHz ), ELF region ( 3 KHz - 3 Hz) ,ULF region ( < 3 Hz ). Experimental evidence of EME before the fracture and at th ...
Theory of Spin-Orbit-Coupled Cold Atomic Systems
... • Synthetic spin-structures may be practically useful for quantum interferometry • Abelian spin-orbit BECs have already been observed. Theory predicts macroscopically-entangled states in non-Abelian SO-BECs (staying tuned for new experiments...) • Synthetic SOC + synthetic magnetic field = new vorte ...
... • Synthetic spin-structures may be practically useful for quantum interferometry • Abelian spin-orbit BECs have already been observed. Theory predicts macroscopically-entangled states in non-Abelian SO-BECs (staying tuned for new experiments...) • Synthetic SOC + synthetic magnetic field = new vorte ...
ch30
... Consider a length l near the middle of a long solenoid of cross-sectional area A carrying current i; the volume associated with this length is Al. The energy UB stored by the length l of the solenoid must lie entirely within this volume because the magnetic field outside such a solenoid is approxima ...
... Consider a length l near the middle of a long solenoid of cross-sectional area A carrying current i; the volume associated with this length is Al. The energy UB stored by the length l of the solenoid must lie entirely within this volume because the magnetic field outside such a solenoid is approxima ...
Homework No. 04 (Fall 2013) PHYS 320: Electricity and Magnetism I
... where r is now the radial vector transverse to the axis of the cylinder. Plot the electric field as a function of r. 3. Consider a uniformly charged solid slab of infinite extent and thickness 2R with charge per unit area σ. Using Gauss’s law show that the electric field inside and outside the slab ...
... where r is now the radial vector transverse to the axis of the cylinder. Plot the electric field as a function of r. 3. Consider a uniformly charged solid slab of infinite extent and thickness 2R with charge per unit area σ. Using Gauss’s law show that the electric field inside and outside the slab ...
Electric Potential
... given by ∆V = ∆U/qo = -Eod. The answer we got does not depend on the path traveled between A and B. Equipotential surfaces Note that if we were to move the charge along the y-axis, no work would be required. In that case we would be moving the charge along an equipotential surface – defined as a sur ...
... given by ∆V = ∆U/qo = -Eod. The answer we got does not depend on the path traveled between A and B. Equipotential surfaces Note that if we were to move the charge along the y-axis, no work would be required. In that case we would be moving the charge along an equipotential surface – defined as a sur ...
Part III
... The Hall Effect When a current-carrying wire is placed in a magnetic field, there is a sideways force (due to v B) on the electrons in the wire. This tends to push them to one side & results in a potential difference from one side of the wire to the other; this is called the Hall Effect. The emf ...
... The Hall Effect When a current-carrying wire is placed in a magnetic field, there is a sideways force (due to v B) on the electrons in the wire. This tends to push them to one side & results in a potential difference from one side of the wire to the other; this is called the Hall Effect. The emf ...
Potential and Field
... creating a potential difference by movement of charges l In the escalator model, positive charges are lifted from the negative terminal of the battery to the positive terminal ◆ chemical reactions inside the battery provide the energy necessary to do this work ◆ by separating the charge, the esc ...
... creating a potential difference by movement of charges l In the escalator model, positive charges are lifted from the negative terminal of the battery to the positive terminal ◆ chemical reactions inside the battery provide the energy necessary to do this work ◆ by separating the charge, the esc ...
Chapter Fourteen The Electric Field and the Electric Potential
... work, we have to overcome the repulsive force between the two charges. The same is true if both charges are negative. • If the charges are of unlike sign, they will attract each other and, consequently, to move q0 at constant velocity, we will have to hold it back. We will then do negative work and ...
... work, we have to overcome the repulsive force between the two charges. The same is true if both charges are negative. • If the charges are of unlike sign, they will attract each other and, consequently, to move q0 at constant velocity, we will have to hold it back. We will then do negative work and ...
May 2009
... potential V (xe ). Let u0 (xe ) and 0 be the (normalized) ground state eigenfunction and energy; let u1 (xe ) and 1 be the eigenfunction and energy of the first excited bound state. The projectile — a “pion” — has mass M , position variable xp , and incidente energy E = ~2 k 2 /2M . The projectile ...
... potential V (xe ). Let u0 (xe ) and 0 be the (normalized) ground state eigenfunction and energy; let u1 (xe ) and 1 be the eigenfunction and energy of the first excited bound state. The projectile — a “pion” — has mass M , position variable xp , and incidente energy E = ~2 k 2 /2M . The projectile ...
magnetic field
... 2. down v (thumb) points right, F(palm) points up, B(fingers) point in. 3. left 4. right 5. into page 6. out of page ...
... 2. down v (thumb) points right, F(palm) points up, B(fingers) point in. 3. left 4. right 5. into page 6. out of page ...