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KEY - AP Physics– Electrostatics – FR 1 #1 (1975
KEY - AP Physics– Electrostatics – FR 1 #1 (1975

... b. W = qV (where V at infinity is zero) = 0.09 J c. F = kqQ/r2 = 0.3 N d. Between the two charges, the fields from each charge point in opposite directions, making the resultant field the difference between the magnitudes of the individual fields. E = kQ/r2 gives EI = 1.2 × 106 N/C to the right and ...
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... previously:  Electric currents generate magnetic fields. If a current is flowing in a straight wire, you can determine the direction of the field with the (curly) right-hand rule: ...
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Electric Fields - Iroquois Central School District

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... magnetic and electrical properties. Layes of composites were deposited by two the help of two crucible evaporation by electron beams. Investigation of thermoelectric power (TEP) were carried out in the temperature region of 90300K in magnetic fields up to 5 kOe. At Co content below percolation thres ...
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Exam IV_v0001_final - University of Colorado Boulder

... 20. An electron and a proton, both with the same initial velocity vo , enter a region with a uniform magnetic field B into the page, as shown. Each one undergoes semi-circular motion in the field and d exits the field some distance d from the entry point. (The diagram shows the path for just one of ...
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... magnets drop toward the rings, does the magnet on the left have an acceleration that is (a) more than, (b) less than, or (c) the same as that of the magnet on the right? ...
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