Week 7 - Acid-base, redox
... With titration, one combines two reactants to reach a stoichiometric proportion or endpoint. The endpoint is often visualized by adding an indicator. At the endpoint, one can analyze an analyte (moles, grams, percentage, or concentration). Titration Works for any reaction type. The calculations for ...
... With titration, one combines two reactants to reach a stoichiometric proportion or endpoint. The endpoint is often visualized by adding an indicator. At the endpoint, one can analyze an analyte (moles, grams, percentage, or concentration). Titration Works for any reaction type. The calculations for ...
AP Chemistry
... In the SO2 molecule, both of the bonds between sulfur and oxygen have the same length. Explain this observation, supporting your explanation by drawing in the box below a Lewis electron-dot diagram (or diagrams) for the SO2 molecule ...
... In the SO2 molecule, both of the bonds between sulfur and oxygen have the same length. Explain this observation, supporting your explanation by drawing in the box below a Lewis electron-dot diagram (or diagrams) for the SO2 molecule ...
Word - Chemistry and More
... b) the reaction between aluminum and chlorine to form a compound. c) the reaction between solutions of ammonium hydroxide and copper(II) nitrate. d) the addition of solid iron to a nitric acid solution to form iron(III) nitrate and hydrogen gas. e) the splitting of water into its elements. ...
... b) the reaction between aluminum and chlorine to form a compound. c) the reaction between solutions of ammonium hydroxide and copper(II) nitrate. d) the addition of solid iron to a nitric acid solution to form iron(III) nitrate and hydrogen gas. e) the splitting of water into its elements. ...
Name
... 27. What is the solubility of sodium nitrate at 30oC? 28. A saturated solution of potassium nitrate is formed from 100 g of water. If the saturated solution is cooled from 80oC to 50oC, how many grams of precipitate are formed? ...
... 27. What is the solubility of sodium nitrate at 30oC? 28. A saturated solution of potassium nitrate is formed from 100 g of water. If the saturated solution is cooled from 80oC to 50oC, how many grams of precipitate are formed? ...
A) I is TRUE, II is FALSE B) I is FALSE, II is TRUE C) I and II
... is endothermic, with a release of energy is exothermic, with an absorption of energy is endothermic, with an absorption of energy can be either exothermic or endothermic ...
... is endothermic, with a release of energy is exothermic, with an absorption of energy is endothermic, with an absorption of energy can be either exothermic or endothermic ...
Part I - American Chemical Society
... The USNCO Subcommittee is conducting a survey in an effort to determine the impact of the Olympiad program on students. The first phase of this effort is represented by several questions added to the end of this year's exam, which should be answered on the same Scantron sheet students use for the ex ...
... The USNCO Subcommittee is conducting a survey in an effort to determine the impact of the Olympiad program on students. The first phase of this effort is represented by several questions added to the end of this year's exam, which should be answered on the same Scantron sheet students use for the ex ...
CHEMISTRY 102 Spring 2012 Hour Exam III Page 20 1. For the
... After equilibrium is reached, which of the following statements (a-d) regarding these experiments is true? a) In experiment 1, the rate of the forward reaction at equilibrium will be greater than the rate of the reverse reaction at equilibrium. b) Equilibrium cannot be reached in experiment 2 becaus ...
... After equilibrium is reached, which of the following statements (a-d) regarding these experiments is true? a) In experiment 1, the rate of the forward reaction at equilibrium will be greater than the rate of the reverse reaction at equilibrium. b) Equilibrium cannot be reached in experiment 2 becaus ...
chapter 4 review_package
... 9. Given the following balanced equations, solve the stoichiometric problems (PLO-D5) a. Ammonia combines with oxygen gas in the following reaction: 4 NH3 + 5O2 → 6H2O + 4NO i. How many moles of NH3 are needed to combine with 3.57 moles of O2 gas? ...
... 9. Given the following balanced equations, solve the stoichiometric problems (PLO-D5) a. Ammonia combines with oxygen gas in the following reaction: 4 NH3 + 5O2 → 6H2O + 4NO i. How many moles of NH3 are needed to combine with 3.57 moles of O2 gas? ...
Chemical Equilibrium
... Changing the volume of a reactant container changes the concentration of gaseous reactants and therefore their partial pressures Equilibrium position will therefore move The value of Kc or Kp does NOT change Changing pressure by adding more of an inert gas has no effect of the equilibrium position - ...
... Changing the volume of a reactant container changes the concentration of gaseous reactants and therefore their partial pressures Equilibrium position will therefore move The value of Kc or Kp does NOT change Changing pressure by adding more of an inert gas has no effect of the equilibrium position - ...
CHE 106 Chapter 5
... Things to remember: DH is as state function, so we are allowed to apply Hess’s Law and add together appropriate reactions to calculate the DHof ...
... Things to remember: DH is as state function, so we are allowed to apply Hess’s Law and add together appropriate reactions to calculate the DHof ...
Role of Water as a Solvent
... Table 4.1 Solubility Rules For Ionic Compounds in Water Soluble Ionic Compounds 1. All common compounds of Group 1A(1) ions (Li+, Na+, K+, etc.) and ammonium ion (NH4+) are soluble. 2. All common nitrates (NO3-), acetates (CH3COO- or C2H3O2-) and most perchlorates (ClO4-) are soluble. 3. All common ...
... Table 4.1 Solubility Rules For Ionic Compounds in Water Soluble Ionic Compounds 1. All common compounds of Group 1A(1) ions (Li+, Na+, K+, etc.) and ammonium ion (NH4+) are soluble. 2. All common nitrates (NO3-), acetates (CH3COO- or C2H3O2-) and most perchlorates (ClO4-) are soluble. 3. All common ...
Revised Higher 2014 Paper
... One way to identify if a perfume is counterfeit is to use gas chromatography. The Marks gas chromatograms from a brand name perfume and two counterfeit perfumes, A and B, are shown below. The chromatograms were run under identical ...
... One way to identify if a perfume is counterfeit is to use gas chromatography. The Marks gas chromatograms from a brand name perfume and two counterfeit perfumes, A and B, are shown below. The chromatograms were run under identical ...
Second Semester Review Part 1
... the forward reaction is proceeding at a certain rate at some temperature and pressure; when the pressure is increased, we may expect for the forward reaction (A) a greater rate of reaction and a greater yield of SO3 at equilibrium. (B) a greater rate of reaction and the same yield of SO3 at equilibr ...
... the forward reaction is proceeding at a certain rate at some temperature and pressure; when the pressure is increased, we may expect for the forward reaction (A) a greater rate of reaction and a greater yield of SO3 at equilibrium. (B) a greater rate of reaction and the same yield of SO3 at equilibr ...
PowerPoint
... Aqueous Solutions of Acids Problem: What is the molarity of the sulfate and hydronium ions in a solution prepared by dissolving 155g of sulfuric acid into sufficient water to produce 2.30 Liters of acid solution? H2SO4 (l) + 2 H2O(l) ...
... Aqueous Solutions of Acids Problem: What is the molarity of the sulfate and hydronium ions in a solution prepared by dissolving 155g of sulfuric acid into sufficient water to produce 2.30 Liters of acid solution? H2SO4 (l) + 2 H2O(l) ...
2010 - SAASTA
... Producing syngas from coal with steam is Gasification. Producing syngas from natural gas with steam is called reforming. ...
... Producing syngas from coal with steam is Gasification. Producing syngas from natural gas with steam is called reforming. ...
Part II - KFUPM Faculty List
... o nonspontaneous at ‒ 10C. (Ice does not melt at this temperature) o at equilibrium at 0C. (Ice and water are at equilibrium at this temperature) ...
... o nonspontaneous at ‒ 10C. (Ice does not melt at this temperature) o at equilibrium at 0C. (Ice and water are at equilibrium at this temperature) ...
Chemistry 12 – Unit 3 – Chapter 5 – Thermochemistry
... -Thus H can be used as a conversion factor in a balanced equation to obtain amounts of reactant/product or H itself. (mole to mole ratios). 2. H for a reaction is equal in magnitude but opposite in sign to H for the reverse reaction. Problems with molar enthalpies: ...
... -Thus H can be used as a conversion factor in a balanced equation to obtain amounts of reactant/product or H itself. (mole to mole ratios). 2. H for a reaction is equal in magnitude but opposite in sign to H for the reverse reaction. Problems with molar enthalpies: ...
Answer
... Calculate the enthalpy of solution of AgBr(s). As the final solution has a volume of 320 mL, its mass is: mass = density × volume = (0.997 g mL-1) × (320 mL) = 319 g The heat produced causes the temperature of this mass of solution and the calorimeter to rise by 2.4 °C: q = ( × × ∆T) + ( ...
... Calculate the enthalpy of solution of AgBr(s). As the final solution has a volume of 320 mL, its mass is: mass = density × volume = (0.997 g mL-1) × (320 mL) = 319 g The heat produced causes the temperature of this mass of solution and the calorimeter to rise by 2.4 °C: q = ( × × ∆T) + ( ...
CHAPTER 6: Earth science
... 1. The following photograph shows the result of adding a colourless solution of silver nitrate to a colourless solution of sodium chloride in a test tube. (a) A white precipitate forms. Define the term ‘precipitate’. An insoluble solid forms when two solutions are mixed. ...
... 1. The following photograph shows the result of adding a colourless solution of silver nitrate to a colourless solution of sodium chloride in a test tube. (a) A white precipitate forms. Define the term ‘precipitate’. An insoluble solid forms when two solutions are mixed. ...
+ H 2 O
... H2SO4 + 2KOH K2SO4 + 2H2O #mole KOH = (M) KOH X (V) KOH #mole KOH = 0.05 L X1M = 0.05 mol KOH 1 mol H2SO4 #mole H2SO4 = # mole KOH X ...
... H2SO4 + 2KOH K2SO4 + 2H2O #mole KOH = (M) KOH X (V) KOH #mole KOH = 0.05 L X1M = 0.05 mol KOH 1 mol H2SO4 #mole H2SO4 = # mole KOH X ...
Chem 2A Final Review
... Limiting Reagents Theoretical and Percent Yield 64. The answer that is closest to the number of grams of oxygen in 6.022 1023 molecules of O2 is: ...
... Limiting Reagents Theoretical and Percent Yield 64. The answer that is closest to the number of grams of oxygen in 6.022 1023 molecules of O2 is: ...
BONUS: Which line in the above graph represents G for the reaction
... which change will cause an increase in the pressure of CO2(g) when equilibrium is re-established? (A) ...
... which change will cause an increase in the pressure of CO2(g) when equilibrium is re-established? (A) ...
Chemistry SOL Review Test
... 103) Using the following equations for complex ions, draw an arrow to show how each system would change under the following conditions. (In which direction will the equilibrium shift?) [Zn(H2O)4]2+ + H2O ↔ [Zn(H2O)3(OH)]+ + H3O+ a. Removing water _________ b. Adding H3O+ _________ ...
... 103) Using the following equations for complex ions, draw an arrow to show how each system would change under the following conditions. (In which direction will the equilibrium shift?) [Zn(H2O)4]2+ + H2O ↔ [Zn(H2O)3(OH)]+ + H3O+ a. Removing water _________ b. Adding H3O+ _________ ...
CfE HIGHER CHEMISTRY Chemistry in Society
... 4. When the fizzing has stopped, make up to the calibration mark with water and shake well. 5. Titrate 20cm3 portions of this solution with standard sodium hydroxide solution, concentration 0.1 moll-1, using methyl orange as an indicator. 6. Repeat until 2 concordant results (within 0.1 cm3) are obt ...
... 4. When the fizzing has stopped, make up to the calibration mark with water and shake well. 5. Titrate 20cm3 portions of this solution with standard sodium hydroxide solution, concentration 0.1 moll-1, using methyl orange as an indicator. 6. Repeat until 2 concordant results (within 0.1 cm3) are obt ...
Final Review
... hydrochloric acid to produce hydrogen and magnesium chloride? a. Mg + 2 HCl ----> H2 + MgCl2 b. Mg + HCl ----> H + MgCl c. 2 Mg + 6 HCl ----> 3 H2 + 2 MgCl3 d. Mg + 2 HCl ----> 2 H + MgCl2 e. Mg + 3 HCl ----> 3 H + MgCl3 71. Which of the following equations is not balanced? a. 2 Na + 2 H2O ----> 2 N ...
... hydrochloric acid to produce hydrogen and magnesium chloride? a. Mg + 2 HCl ----> H2 + MgCl2 b. Mg + HCl ----> H + MgCl c. 2 Mg + 6 HCl ----> 3 H2 + 2 MgCl3 d. Mg + 2 HCl ----> 2 H + MgCl2 e. Mg + 3 HCl ----> 3 H + MgCl3 71. Which of the following equations is not balanced? a. 2 Na + 2 H2O ----> 2 N ...
Thermometric titration
A thermometric titration is one of a number of instrumental titration techniques where endpoints can be located accurately and precisely without a subjective interpretation on the part of the analyst as to their location. Enthalpy change is arguably the most fundamental and universal property of chemical reactions, so the observation of temperature change is a natural choice in monitoring their progress. It is not a new technique, with possibly the first recognizable thermometric titration method reported early in the 20th century (Bell and Cowell, 1913). In spite of its attractive features, and in spite of the considerable research that has been conducted in the field and a large body of applications that have been developed; it has been until now an under-utilized technique in the critical area of industrial process and quality control. Automated potentiometric titration systems have pre-dominated in this area since the 1970s. With the advent of cheap computers able to handle the powerful thermometric titration software, development has now reached the stage where easy to use automated thermometric titration systems can in many cases offer a superior alternative to potentiometric titrimetry.The applications of thermometric titrimetry discussed on this page are by no means exhaustive. The reader is referred to the bibliography for further reading on the subject.