Math 2250-10 Quiz 2 SOLUTIONS January 17, 2014
... dy =K2 y C 8 =K2 y K 4 dx dy =K2 dx yK4 (unless y0 = 4, in which case the solution is y t h 4 ) dy = K2 dx yK4 ln y K 4 =K2 x C C1 exponentiate: C ...
... dy =K2 y C 8 =K2 y K 4 dx dy =K2 dx yK4 (unless y0 = 4, in which case the solution is y t h 4 ) dy = K2 dx yK4 ln y K 4 =K2 x C C1 exponentiate: C ...
Solution - Illustrative Mathematics
... numbers that are equal and multiplying them both by 2 will result in two equal numbers. So this system has infinitely many solutions, as the equations both correspond to the same line and lines have infinitely many points. (Bonus) In parts (a), (c), and (d), there are infinitely many equations that ...
... numbers that are equal and multiplying them both by 2 will result in two equal numbers. So this system has infinitely many solutions, as the equations both correspond to the same line and lines have infinitely many points. (Bonus) In parts (a), (c), and (d), there are infinitely many equations that ...
Chapter 2 Lesson 3
... one or both of the equations by a constant so that one of the variables has the same coefficient in both equations. If the sign in front of the coefficient is the same in both equations, subtract one equation from the other. If the sign in front of the coefficient is different in both equations, ...
... one or both of the equations by a constant so that one of the variables has the same coefficient in both equations. If the sign in front of the coefficient is the same in both equations, subtract one equation from the other. If the sign in front of the coefficient is different in both equations, ...
