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3.0 - Electricity, Components and Circuits
3.0 - Electricity, Components and Circuits

A. Agnes, E. Bonizzoni, P. Malcovati, F. Maloberti: "A 9.4
A. Agnes, E. Bonizzoni, P. Malcovati, F. Maloberti: "A 9.4

... The time required to discharge 0.8pF by 0.4V with a 1.2µA constant current is 0.267µs. Since T2 must be less than half of the clock period, the maximum usable clock is 1.87MHz. However, to have a margin to possible errors, this design uses fCK=1.4MHz. The power consumed to charge and discharge C1 de ...
74LS151 - 8-to-1 multiplexer
74LS151 - 8-to-1 multiplexer

FSEZ1016A Primary-Side-Regulation PWM Integrated Power MOSFET FSEZ10 16A
FSEZ1016A Primary-Side-Regulation PWM Integrated Power MOSFET FSEZ10 16A

... During the inductor current discharge time, the sum of output voltage and diode forward-voltage drop is reflected to the auxiliary winding side as (VO+VF)× NA/NS. Since the diode forward-voltage drop decreases as current decreases, the auxiliary winding voltage reflects the output voltage best at th ...
6.0L Fuel Injection Control Module (FICM) How To’s
6.0L Fuel Injection Control Module (FICM) How To’s

... The stock injector pulse was specified as 400 µs – 5.8 ms at 20 A. I wanted a little extra current to help overcome injector stiction or other electro-mechanical issues that might arise in the injectors. I tried to trace back the electronics from the current sense resistors on the FICM logic board, ...
ES636 True RMS-to-DC Converters  Features
ES636 True RMS-to-DC Converters Features

... The current I4 drives the internal current mirror through a low-pass filter formed by R1 and the external capacitor, CAV. As long as the time constant of this filter is greater than the longest period of the input signal, I4 is averaged. The current mirror returns a current, I3, to the square/divide ...
KS4 Electricty - Resistance, Power and Energy
KS4 Electricty - Resistance, Power and Energy

... Draw adoes line of best fit for Plot your points on the graph. If you get a your straight line it means What graph look like? your graph. that the two quantities current and voltage are proportional. What does proportional mean? If you double the voltage then the current doubles. This fact was put i ...
Lab : Exploring Voltage, Current, and Resistance
Lab : Exploring Voltage, Current, and Resistance

... The first student should assemble the circuit as shown in the schematic on the left.  Then,  using the Digital  Multimeter in the three different modes, measure the voltages, currents, and resistances  as shown in the  schematic at right.  If you do not know how to use the DMM, view the assigned vid ...
AN52 - Linear Technology Magazine Circuit Collection, Volume 1
AN52 - Linear Technology Magazine Circuit Collection, Volume 1

... Q5’s emitter monitors the voltage across 50mΩ resistor R1. When the voltage across R1 exceeds 220mV, Q4 turns on hard, pulling current through R5. When the voltage at the ILIM pin of the LT1110 reaches a diode drop below the VIN pin, the internal switch turns off. Thus, maximum switch current is mai ...
Electronics Lab #2
Electronics Lab #2

... resistances using the Ohmmeter and make sure the values agree with the color code. Connect the resistors in parallel and measure the total resistance and see that this resistance agrees with what you expect from numerical calculation. Calculate the total current supplied by the battery using Ohm's l ...
lecture12
lecture12

... To find xf , the asymptotic final value, we assume that the circuit will be in steady-state as t goes to infinity. So we assume that the capacitor is acting like an open circuit. We then find the value of current or voltage we are looking for using this open-circuit assumption. Here, we use the circ ...
UJT
UJT

Combinations of resistors and non-ideal meters
Combinations of resistors and non-ideal meters

... Recall that to measure the current passing through a given resistor, you place an ammeter in series with it. The resistance of the ammeter should be small so that it does not change significantly the current through the resistor (and hence the voltage drop across the resistor). Create a circuit cons ...
SGM721/2/3/4 970µA,10MHz, Rail-to-Rail I/O CMOS
SGM721/2/3/4 970µA,10MHz, Rail-to-Rail I/O CMOS

Electric Circuit Theory, Experiment 1:The Linear Resistor and OHM`s
Electric Circuit Theory, Experiment 1:The Linear Resistor and OHM`s

CONNECTOR AMPLIFIER FOR PROPORTIONAL VALVES (0
CONNECTOR AMPLIFIER FOR PROPORTIONAL VALVES (0

... The 0-10 V Connector Amplifier simplifies control of proportional solenoids by supplying a current proportional to an input control (0-10 V or 0-20 mA). It accepts power supply voltages from 9 to 28 VDC. This linear solenoid driver utilizes high frequency switching output (PWM) to provide a DC curre ...
Electric Circuits: Ohm`s Law (Grade 11)
Electric Circuits: Ohm`s Law (Grade 11)

OP285
OP285

... current load condition. When driving the input of an A/D converter, especially successive-approximation converters, the amplifier must maintain a constant output voltage under dynamically changing load current conditions. In these types of converters, the comparison point is usually diode clamped, b ...
Current transducer LF 1010-S = 1000 A I
Current transducer LF 1010-S = 1000 A I

... Definition of typical, minimum and maximum values Minimum and maximum values for specified limiting and safety conditions have to be understood as such as well as values shown in “typical” graphs. On the other hand, measured values are part of a statistical distribution that can be specified by an i ...
Physical Explanation
Physical Explanation

... reverse voltage, i.e., n = f(VR). The quality, Q, of the Varicap is an important factor and can be calculated ...
SP6699
SP6699

... reset and the switch is turned off. It is clear that the voltage level at non-inversion input of A2 sets the peak current level to keep the output in regulation. This voltage level is the output signal of error amplifier A1, and is the amplified signal of the voltage difference between feedback volt ...
EEE331-Exp-6
EEE331-Exp-6

RESET MAX8530/MAX8531 Dual Low-Dropout Linear Regulators with
RESET MAX8530/MAX8531 Dual Low-Dropout Linear Regulators with

... loads. The MAX8530/MAX8531 do not suffer these problems and consume only 150µA of quiescent current whether in dropout, light-load, or heavy-load applications (see the Typical Operating Characteristics). Whereas a PNP-based regulator has dropout voltage that is independent of the load, a P-channel M ...
ZXCL SERIES Micropower SC70-5 & SOT23-5 low dropout regulators
ZXCL SERIES Micropower SC70-5 & SOT23-5 low dropout regulators

... Note2:Output voltage will start to rise when VIN exceeds a value or approximately 1.3V. For normal operation, VIN(min) > VOUT(nom) + 0.5V. Note3:Dropout voltage is defined as the difference between VIN and VO, when VO has dropped 100mV below its nominal value. Nominal value of VO is defined at VIN=V ...
emergency set
emergency set

... 220 volt, 50 Hz supply. A non-inductive resistor under the same conditions takes 12 amperes. If the two are connected is series and placed across the same supply, find the current taken. If now the frequency is reduced to 40 Hz, the voltage being maintained constant, find the current taken. 3. A cur ...
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Current mirror

A current mirror is a circuit designed to copy a current through one active device by controlling the current in another active device of a circuit, keeping the output current constant regardless of loading. The current being 'copied' can be, and sometimes is, a varying signal current. Conceptually, an ideal current mirror is simply an ideal inverting current amplifier that reverses the current direction as well or it is a current-controlled current source (CCCS). The current mirror is used to provide bias currents and active loads to circuits. It can also be used to model a more realistic current source (since ideal current sources don't exist).The circuit topology covered here is one that appears in many monolithic ICs. It is a Widlar mirror without an emitter degeneration resistor in the follower (output) transistor. This topology can only be done in an IC as the matching has to be extremely close and cannot be achieved with discretes.Another topology is the Wilson mirror. The Wilson mirror solves the Early effect voltage problem in his design.
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