Applications of Trees
... { while(t != null) { if(s == label(t)) return t; if(s < label(t) t = leftSubTree(t); else t = rightSubTree(t); ...
... { while(t != null) { if(s == label(t)) return t; if(s < label(t) t = leftSubTree(t); else t = rightSubTree(t); ...
if - Read
... The code is broken into two cases If the right subtree of node x is nonempty, then the successor of x is just the left-most node in the right subtree, which found by calling Tree-Minimum(right) If the right subtree of x is empty and x has a successor y, then y is the lowest ancestor of x whose left ...
... The code is broken into two cases If the right subtree of node x is nonempty, then the successor of x is just the left-most node in the right subtree, which found by calling Tree-Minimum(right) If the right subtree of x is empty and x has a successor y, then y is the lowest ancestor of x whose left ...
INF 431 PC – 2 Balanced Binary trees
... • One way to implement a priority queue is by using a binary heap: binary heap is a binary tree with two additional properties: – The tree is complete, i.e. every level of the tree is full, except perhaps the bottom level, and it is filled left-to-right. – For every node in the tree, the value of th ...
... • One way to implement a priority queue is by using a binary heap: binary heap is a binary tree with two additional properties: – The tree is complete, i.e. every level of the tree is full, except perhaps the bottom level, and it is filled left-to-right. – For every node in the tree, the value of th ...
Lecture 14
... hierarchical data (eg: organizational structure) • Trees allows us to find things efficiently – Navigation is O(log n) for a “balanced” tree with n nodes ...
... hierarchical data (eg: organizational structure) • Trees allows us to find things efficiently – Navigation is O(log n) for a “balanced” tree with n nodes ...
lecture 9
... • Lemma: A red-black tree with n internal nodes has height at most 2 lg(n +1) • Definition: Black-height, bh(x), is the number of black nodes on any path from x to a leaf (not counting x itself). • Proof: We first prove a claim: The sub-tree rooted at any node x contains at least 2bh(x) –1 internal ...
... • Lemma: A red-black tree with n internal nodes has height at most 2 lg(n +1) • Definition: Black-height, bh(x), is the number of black nodes on any path from x to a leaf (not counting x itself). • Proof: We first prove a claim: The sub-tree rooted at any node x contains at least 2bh(x) –1 internal ...
Lecture 23
... are efficient because half the tree is eliminated at each comparison (cf binary search with arrays). In searching for an item in a binary search tree only involves going left or right for each node as we descend the tree. This is similar to choosing first or second half during a binary search for an ...
... are efficient because half the tree is eliminated at each comparison (cf binary search with arrays). In searching for an item in a binary search tree only involves going left or right for each node as we descend the tree. This is similar to choosing first or second half during a binary search for an ...
105-1 Data Structures Quiz2 系級: 學號: 姓名: 1. The following
... (1) Please find the vertex sequence derived by DFS and BFS respectively. Note that we assume that node A is the root. You should draw the graph. (10%) (2) Please apply Kruskal’s algorithm to drive the minimum cost spanning tree. Note that you must show your actions step by step. (5%) ...
... (1) Please find the vertex sequence derived by DFS and BFS respectively. Note that we assume that node A is the root. You should draw the graph. (10%) (2) Please apply Kruskal’s algorithm to drive the minimum cost spanning tree. Note that you must show your actions step by step. (5%) ...
Binary Search Tree
... • 2 binary search trees contains the same 6 keys. – (a) A binary search tree with height 3. – (b) A binary search tree with height 5. – Which one is better? ...
... • 2 binary search trees contains the same 6 keys. – (a) A binary search tree with height 3. – (b) A binary search tree with height 5. – Which one is better? ...
