HCPSS Curriculum Framework Common Core 8 Unit 2: Expressions
... 2. Two or more expressions may be equivalent, even when their symbolic forms differ. A relatively small number of symbolic transformations can be applied to expressions to yield equivalent expressions. 3. Variables have many different meanings, depending on context and purpose. 4. Using variables pe ...
... 2. Two or more expressions may be equivalent, even when their symbolic forms differ. A relatively small number of symbolic transformations can be applied to expressions to yield equivalent expressions. 3. Variables have many different meanings, depending on context and purpose. 4. Using variables pe ...
Section 8.1 Solving Quadratic Equations A linear equation has the
... A linear equation has the form ax b c , with a 0 . These equations are called first-degree polynomial equations. In this section we learn how to solve second-degree polynomial equations. These equations are called quadratic equations. Quadratic Equation in One Variable A quadratic equation in ...
... A linear equation has the form ax b c , with a 0 . These equations are called first-degree polynomial equations. In this section we learn how to solve second-degree polynomial equations. These equations are called quadratic equations. Quadratic Equation in One Variable A quadratic equation in ...
Solving Linear Systems: Graphing Method
... Solving Linear Systems of Equations - Graphing Method • While the graphing method is helpful in gaining a visual understanding of solving systems of equations, it is not very practical for solving systems whose solutions are not integers. For example, the solution (3/7, - 2/9) is not likely to be f ...
... Solving Linear Systems of Equations - Graphing Method • While the graphing method is helpful in gaining a visual understanding of solving systems of equations, it is not very practical for solving systems whose solutions are not integers. For example, the solution (3/7, - 2/9) is not likely to be f ...
5.2: Solving Quadratic Equations by Factoring
... • Let A and B be real numbers or algebraic expressions. If AB=0, then A=0 or B=0. • This means that If the product of 2 factors is zero, then at least one of the 2 factors had to be zero itself! ...
... • Let A and B be real numbers or algebraic expressions. If AB=0, then A=0 or B=0. • This means that If the product of 2 factors is zero, then at least one of the 2 factors had to be zero itself! ...
Solution to Practice Questions
... m. Then p is odd, and p cannot be one of the pj ’s. Indeed, if p = pj for some j, then p would divide 4p1 p2 · · · pn . Since it also divides m, it would have to divide 4p1 p2 · · · pn − m = 1, a contradiction. It follows that p is not congruent to 3 modulo 4, so the only possibility is that it is c ...
... m. Then p is odd, and p cannot be one of the pj ’s. Indeed, if p = pj for some j, then p would divide 4p1 p2 · · · pn . Since it also divides m, it would have to divide 4p1 p2 · · · pn − m = 1, a contradiction. It follows that p is not congruent to 3 modulo 4, so the only possibility is that it is c ...
Write or Identify a Linear Equation
... 2. The equation y = mx + b is called the slope-intercept form of a linear equation, where m is the slope of the line and b is the y-intercept. Therefore, the slope of the equation y = -5x + 4 is -5. 3. Plug the slope and point into the point-slope formula. y - y1 = m(x - x1) y - (-2) = 1/3(x - (-1)) ...
... 2. The equation y = mx + b is called the slope-intercept form of a linear equation, where m is the slope of the line and b is the y-intercept. Therefore, the slope of the equation y = -5x + 4 is -5. 3. Plug the slope and point into the point-slope formula. y - y1 = m(x - x1) y - (-2) = 1/3(x - (-1)) ...
