Arithmetic
... • Suppose n is even, n = 2m • To compute a∙b • Write a = a1∙2m + a0, b = b1∙2m + b0, where a1, a0, b1, b0 are m-bit numbers (numbers < 2m) – the first and last m bits of a and b a∙b = a1b1∙22m + (a1b0+a0b1)∙2m + a0b0 = a1b1∙(22m+2m) + (a1-a0)(b0-b1)∙2m + a0b0∙(2m+1) Only 3 m-bit multiplications!!! ...
... • Suppose n is even, n = 2m • To compute a∙b • Write a = a1∙2m + a0, b = b1∙2m + b0, where a1, a0, b1, b0 are m-bit numbers (numbers < 2m) – the first and last m bits of a and b a∙b = a1b1∙22m + (a1b0+a0b1)∙2m + a0b0 = a1b1∙(22m+2m) + (a1-a0)(b0-b1)∙2m + a0b0∙(2m+1) Only 3 m-bit multiplications!!! ...
Math 4707 The Catalan Nunbers 1 Introduction
... the railroad tracks, and then subtract from the total number of blockwalks. Let B be a blockwalk which crosses the railroad track, and let Bi denote the letter (N or E) in the ith step of the walk. Any blockwalk which crosses the tracks must, at some point, have the number of E’s exceed the number o ...
... the railroad tracks, and then subtract from the total number of blockwalks. Let B be a blockwalk which crosses the railroad track, and let Bi denote the letter (N or E) in the ith step of the walk. Any blockwalk which crosses the tracks must, at some point, have the number of E’s exceed the number o ...
COS 423 Lecture 1 Counting in Binary Amortized and Worst-Case Efficiency
... k. Let Φ = n mod 2k. Each add increases Φ by one, unless cost is k + 1 or more. (We call the add expensive.) In this case n mod 2k = 2k – 1, so Φ decreases by 2k – 1. This can happen at most n/2k times out of n: Φ = n - e2k ≥ 0, where e = #expensive adds. ...
... k. Let Φ = n mod 2k. Each add increases Φ by one, unless cost is k + 1 or more. (We call the add expensive.) In this case n mod 2k = 2k – 1, so Φ decreases by 2k – 1. This can happen at most n/2k times out of n: Φ = n - e2k ≥ 0, where e = #expensive adds. ...
11Numbers
... Why Bits (Binary Digits)? • Computers are built using digital circuits Inputs and outputs can have only two values True (high voltage) or false (low voltage) Represented as 1 and 0 ...
... Why Bits (Binary Digits)? • Computers are built using digital circuits Inputs and outputs can have only two values True (high voltage) or false (low voltage) Represented as 1 and 0 ...
Logarithm
... For decimal numbers with fractional part (小數部), we separate the fractional part from its integral part (整數部). Like 7.687510, the integral part is 7, and the fractional part is 0.6875. Convert the integral part into binary directly (1112), and do the fractional part as follows: ...
... For decimal numbers with fractional part (小數部), we separate the fractional part from its integral part (整數部). Like 7.687510, the integral part is 7, and the fractional part is 0.6875. Convert the integral part into binary directly (1112), and do the fractional part as follows: ...
Integer Exponent Review Notes
... The numbers used in the exploration were written in scientific notation. Write in your own words how to convert numbers from scientific notation to decimal form. Converting from Scientific Notation to Decimal (Standard) Form: To convert from scientific notation with a positive power of 10, move the ...
... The numbers used in the exploration were written in scientific notation. Write in your own words how to convert numbers from scientific notation to decimal form. Converting from Scientific Notation to Decimal (Standard) Form: To convert from scientific notation with a positive power of 10, move the ...
Exam - Lenoir-Rhyne University
... o Completely erase any changes. You can write on this test booklet. (But the test booklet will not be graded.) ...
... o Completely erase any changes. You can write on this test booklet. (But the test booklet will not be graded.) ...
Geometry 10-1 Circles and Circumference
... Ex 3: The diameters of ○X, ○Y, and ○Z are 22 mm, 16 mm, and 10 mm respectively. a.) Find EZ. b.) Find XF. ...
... Ex 3: The diameters of ○X, ○Y, and ○Z are 22 mm, 16 mm, and 10 mm respectively. a.) Find EZ. b.) Find XF. ...
Approximations of π
Approximations for the mathematical constant pi (π) in the history of mathematics reached an accuracy within 0.04% of the true value before the beginning of the Common Era (Archimedes). In Chinese mathematics, this was improved to approximations correct to what corresponds to about seven decimal digits by the 5th century.Further progress was made only from the 15th century (Jamshīd al-Kāshī), and early modern mathematicians reached an accuracy of 35 digits by the 18th century (Ludolph van Ceulen), and 126 digits by the 19th century (Jurij Vega), surpassing the accuracy required for any conceivable application outside of pure mathematics.The record of manual approximation of π is held by William Shanks, who calculated 527 digits correctly in the years preceding 1873. Since the mid 20th century, approximation of π has been the task of electronic digital computers; the current record (as of May 2015) is at 13.3 trillion digits, calculated in October 2014.