Problem 12 : Odd Numbers in Pascal`s Triangle
... α3 + 22n−1 + 2n−1 . Applying the initial condition a1 = 0 and solving for α = −1, we get the particular solution of an = 22n−1 + 2n−1 − 3n . Recall that our solution to equation 1 is to any row n. Our recurrence relation, however, looks at rows at 2n . Replacing n with 2n in equation 1 will now give ...
... α3 + 22n−1 + 2n−1 . Applying the initial condition a1 = 0 and solving for α = −1, we get the particular solution of an = 22n−1 + 2n−1 − 3n . Recall that our solution to equation 1 is to any row n. Our recurrence relation, however, looks at rows at 2n . Replacing n with 2n in equation 1 will now give ...
7.1 Systems of Linear Equations in Two Variables
... Section 7.1 Notes Page 5 EXAMPLE: A party mix is made by adding nuts that sell for $2.50 per kg to a cereal mixture that sells for $1 per kg. How much of each should be added to get 30 kg of a mix that will sell for $1.70 per kg. For this problem we need to find our two equations and then use eithe ...
... Section 7.1 Notes Page 5 EXAMPLE: A party mix is made by adding nuts that sell for $2.50 per kg to a cereal mixture that sells for $1 per kg. How much of each should be added to get 30 kg of a mix that will sell for $1.70 per kg. For this problem we need to find our two equations and then use eithe ...
4 The Schrodinger`s Equation
... We then endowed ψ with dynamics by adding in, at first a diagonal Hamiltonian Eq. (30) Ĥ and then with some more interesting dynamics by adding a NOT operator Eq. (33) H̃ . We find that both Hamiltonians generate different kinds of motion for the qubit. The lesson here is that the dynamics of system ...
... We then endowed ψ with dynamics by adding in, at first a diagonal Hamiltonian Eq. (30) Ĥ and then with some more interesting dynamics by adding a NOT operator Eq. (33) H̃ . We find that both Hamiltonians generate different kinds of motion for the qubit. The lesson here is that the dynamics of system ...
