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Fibonacci Extended
Fibonacci Extended

... equaled 11. After reading about the Fibonacci numbers, I found that the number 11 is called the golden string. It was neat to find that each different set of numbers shared the relationship of 11 among the sum of all numbers and the 7th term. Those calculations are highlighted in yellow on the Excel ...
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... brackets." Very quickly, zero entered into the sequence with the result that there were mathematical complications once it arrived at the denominator. To avoid this problem, it was decided to try using "the least integer function" instead of the greatest integer function. The notation adopted was: ...
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... The last condition effectively removes the class of all regular polygons. The group structure of such polygons is clear; it is related to the partition of unity in which this partition is prime. Therefore, it does not come as any surprise that a symmetry relation for the star n-polygon < , V is ...
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... When you move terms to the other side of the = sign, negative numbers become positive and positive numbers become negative. How to solve linear equations: 1. Multiply out the brackets 2. All terms containing x to the left-hand side and the rest to the right-hand side 3. Simplify both sides 4. Divide ...
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... The inverse z1 , together with the sum and the product allows to see C as a number field 2 . Two complex numbers z = x + y i, w = a + b i are multiplied as follows: z.w = (x + y i)(a + b i) = xa + xb i +ya i +yb i2 = xa + (xb + ya) i +yb(−1) so z.w = (xa − yb) + (xb + ya) i. A famous formula: |z|2 | ...
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Taylor Polynomials: The Lagrange Error Bound

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... (from Lemma 3). Then p' is an integral multiple of P and the theorem follows. I mentioned this result to Dr. P.M. Lee of York University and he has pointed out to me that Lemma 3 can be derived from H. Siebeck's work on recurring series (L.E. Dickson, History of the Theory of Numbers, p. 394f). A co ...
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Series (mathematics)

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