Topic 2c (foundation) – Homework on Pictograms
... The mileage cost is worked out using the formula Mileage cost = number of miles travelled x rate per mile The rate per mile is £2. The number of miles travelled is 80. (a) ...
... The mileage cost is worked out using the formula Mileage cost = number of miles travelled x rate per mile The rate per mile is £2. The number of miles travelled is 80. (a) ...
LESSON PLAN FOR THE TEACHER
... Each row is symmetrical, beginning with 0, then the diagonals go consecutive integers, even integers, then triangular numbers, etc. (Discuss patterns seen by students) Reflection on Learning: Summarize the possible methods that you can use to determine an explicit formula for a sequence. Read respo ...
... Each row is symmetrical, beginning with 0, then the diagonals go consecutive integers, even integers, then triangular numbers, etc. (Discuss patterns seen by students) Reflection on Learning: Summarize the possible methods that you can use to determine an explicit formula for a sequence. Read respo ...
Fibonacci Identities as Binomial Sums
... himself will be working on writing some other Fibonacci and Lucas identities as binomial sums as well. ...
... himself will be working on writing some other Fibonacci and Lucas identities as binomial sums as well. ...
Elementary Number Theory Definitions and Theorems
... The integer m is called the modulus of the congruence. Proposition 2.2 (Elementary properties of congruences). Let a, b, c, d ∈ Z, m ∈ N. (i) If a ≡ b mod m and c ≡ d mod m, then a + c ≡ b + d mod m. (ii) If a ≡ b mod m and c ≡ d mod m, then ac ≡ bd mod m. (iii) If a ≡ b mod m, then an ≡ bn mod m fo ...
... The integer m is called the modulus of the congruence. Proposition 2.2 (Elementary properties of congruences). Let a, b, c, d ∈ Z, m ∈ N. (i) If a ≡ b mod m and c ≡ d mod m, then a + c ≡ b + d mod m. (ii) If a ≡ b mod m and c ≡ d mod m, then ac ≡ bd mod m. (iii) If a ≡ b mod m, then an ≡ bn mod m fo ...
Argand Diagrams and the Polar Form
... We conclude from this that addition (and hence subtraction) of complex numbers is essentially equivalent to addition (subtraction) of two-dimensional vectors. (See Figure 4.) Because of this, complex numbers (when represented on an Argand diagram) are slidable — as long as you keep their length and ...
... We conclude from this that addition (and hence subtraction) of complex numbers is essentially equivalent to addition (subtraction) of two-dimensional vectors. (See Figure 4.) Because of this, complex numbers (when represented on an Argand diagram) are slidable — as long as you keep their length and ...
34(3)
... approximately twice the size they are to appear in print. Since the Fibonacci Association has adopted Fi = F2 = 1, Fn+i = F* + Fn-i, n > 2 and Li = 1, L2 = 3, Ln+i = L* + L«-i, n ^ 2 as the standard definitions for The Fibonacci and Lucas sequences, these definitions should not be a part of future p ...
... approximately twice the size they are to appear in print. Since the Fibonacci Association has adopted Fi = F2 = 1, Fn+i = F* + Fn-i, n > 2 and Li = 1, L2 = 3, Ln+i = L* + L«-i, n ^ 2 as the standard definitions for The Fibonacci and Lucas sequences, these definitions should not be a part of future p ...
Elementary mathematics
Elementary mathematics consists of mathematics topics frequently taught at the primary or secondary school levels. The most basic topics in elementary mathematics are arithmetic and geometry. Beginning in the last decades of the 20th century, there has been an increased emphasis on problem solving. Elementary mathematics is used in everyday life in such activities as making change, cooking, buying and selling stock, and gambling. It is also an essential first step on the path to understanding science.In secondary school, the main topics in elementary mathematics are algebra and trigonometry. Calculus, even though it is often taught to advanced secondary school students, is usually considered college level mathematics.