Lecture 7.3 1. Angular Momentum
... can be defined by means of the radius vector r directed from the origin of coordinate system. Then we shall define the angular momentum of this particle as ...
... can be defined by means of the radius vector r directed from the origin of coordinate system. Then we shall define the angular momentum of this particle as ...
Angular Momentum
... rotating body about a certain axis and is dependent upon the moment of inertia about that axis and the angular velocity about that axis. ...
... rotating body about a certain axis and is dependent upon the moment of inertia about that axis and the angular velocity about that axis. ...
Materialy/01/Applied Mechanics-Lectures/Applied Mechanics
... FUNDAMENTALS OF RIGID-BODY DYNAMICS Position vector ...
... FUNDAMENTALS OF RIGID-BODY DYNAMICS Position vector ...
New Phenomena: Recent Results and Prospects from the Fermilab
... A uniform rod of mass m, length l, and moment of inertia I = ml2/3 rotates around a pivot. It is held horizontally and released. Find the angular acceleration a and the linear acceleration a at the end. Where, along the rod, is a = g? ...
... A uniform rod of mass m, length l, and moment of inertia I = ml2/3 rotates around a pivot. It is held horizontally and released. Find the angular acceleration a and the linear acceleration a at the end. Where, along the rod, is a = g? ...
rotational motion and gravitation notes
... Torque is a vector quantity. The direction of the torque vector is at right angles to the plane containing both r and F and lies along the axis of rotation. (For interest only, in the example shown in the diagram torque, T, points out of the page). A force acting on the rim of an object will cause t ...
... Torque is a vector quantity. The direction of the torque vector is at right angles to the plane containing both r and F and lies along the axis of rotation. (For interest only, in the example shown in the diagram torque, T, points out of the page). A force acting on the rim of an object will cause t ...
Untitled
... Q9: Block A, with a mass of 4 kg, is moving with a speed of 2.0 m/s while block B, with a mass of 8 kg, is moving in the opposite direction with a speed of 3 m/s. The center of mass of the two block-system is moving with the velocity of: PCM = PA + PB = mAvA + mBvB = (4kg)(2m/s) + (8kg)(-3m/s) = -1 ...
... Q9: Block A, with a mass of 4 kg, is moving with a speed of 2.0 m/s while block B, with a mass of 8 kg, is moving in the opposite direction with a speed of 3 m/s. The center of mass of the two block-system is moving with the velocity of: PCM = PA + PB = mAvA + mBvB = (4kg)(2m/s) + (8kg)(-3m/s) = -1 ...
