dyn-part3 - An
... i.e. the work done by all external forces and couple moments equals the change in body’s kinetic energy (translational and rotational). ...
... i.e. the work done by all external forces and couple moments equals the change in body’s kinetic energy (translational and rotational). ...
Rotational Kinematics (Part I from chapter 10)
... Point P will rotate about the origin in a circle of radius r Every particle on the disc undergoes circular motion about the origin, O Polar coordinates are convenient to use to represent the position of P (or any other point) P is located at (r, q) where r is the distance from the origin to P and q ...
... Point P will rotate about the origin in a circle of radius r Every particle on the disc undergoes circular motion about the origin, O Polar coordinates are convenient to use to represent the position of P (or any other point) P is located at (r, q) where r is the distance from the origin to P and q ...
Note that in the following three figures, which show
... depends on its mass and how far the mass is from the rotation axis. For an extended body (as opposed to a "point" object), different parts of the body are at different distances from the rotation axis, so how hard it is to rotate the body depends on both the total mass and how the mass is distribute ...
... depends on its mass and how far the mass is from the rotation axis. For an extended body (as opposed to a "point" object), different parts of the body are at different distances from the rotation axis, so how hard it is to rotate the body depends on both the total mass and how the mass is distribute ...
12 momentum impulse mc key File
... First of all, if the kinetic energies are the same, then when brought to rest, the non conservative work done on each would have to be the same based on work-energy principle. Also, since both have the same kinetic energies we have ½ m1v12 = ½ m2v22 … since the velocity is squared an increase in mas ...
... First of all, if the kinetic energies are the same, then when brought to rest, the non conservative work done on each would have to be the same based on work-energy principle. Also, since both have the same kinetic energies we have ½ m1v12 = ½ m2v22 … since the velocity is squared an increase in mas ...
Chapter 8: Rotational Motion of Solid Objects 1. An isolated object is
... 30. A body of rotational inertia 1.0 kg m2 is acted upon by a torque of 2.0 Nm. The angular acceleration of the body will be: A. 0.5 rad/s2. B. 0.5 rev/s2. C. 1.0 rad/s2. D. 2.0 rad/s2. E. 2.0 rev/s2. Answer: D 31. A merry-go-round, having a radius of 2.0 m, is set in motion by students applying a f ...
... 30. A body of rotational inertia 1.0 kg m2 is acted upon by a torque of 2.0 Nm. The angular acceleration of the body will be: A. 0.5 rad/s2. B. 0.5 rev/s2. C. 1.0 rad/s2. D. 2.0 rad/s2. E. 2.0 rev/s2. Answer: D 31. A merry-go-round, having a radius of 2.0 m, is set in motion by students applying a f ...
AP Physics I
... Conservation of Momentum in Collisions and Explosions 17. A 6.2 kg cannon ball is fired from a 280 kg cannon. The cannon recoils with a velocity of 4.9 m/s. What is the velocity of the cannon ball when it leaves the cannon? 18. A 0.410 kg billiard ball moving at 3.2 m/s strikes another billiard ball ...
... Conservation of Momentum in Collisions and Explosions 17. A 6.2 kg cannon ball is fired from a 280 kg cannon. The cannon recoils with a velocity of 4.9 m/s. What is the velocity of the cannon ball when it leaves the cannon? 18. A 0.410 kg billiard ball moving at 3.2 m/s strikes another billiard ball ...
Chapter 7 Linear Momentum
... Example: Head-on elastic collision of an isolated system. A softball of mass 0.200 kg that is moving with a speed 8.3 m/s collides head-on and elastically with another ball initially at rest. Afterward the incoming softball bounces backward with a speed of 3.2 m/s. a) Calculate the velocity of the ...
... Example: Head-on elastic collision of an isolated system. A softball of mass 0.200 kg that is moving with a speed 8.3 m/s collides head-on and elastically with another ball initially at rest. Afterward the incoming softball bounces backward with a speed of 3.2 m/s. a) Calculate the velocity of the ...
Conservation of Momentum Notes
... • Inelastic Collision: two or more objects collide and do not bounce off each other, but stick together. Or, an explosion where one object starts w/one momentum and then separates into two or more objects w/separate final momenta. ...
... • Inelastic Collision: two or more objects collide and do not bounce off each other, but stick together. Or, an explosion where one object starts w/one momentum and then separates into two or more objects w/separate final momenta. ...
