File
... 1. Calculate the momentum of a 0.15 kg ball that is moving toward home plate at a velocity of 40m/s. 2. Which has greater momentum, a 2.0kg hockey puck moving east at 2.5m/s or a 1.3kg hockey puck moving south at 3.0m/s? 3. A track athlete throws a 2kg discus into a field with a velocity of 21m/s. W ...
... 1. Calculate the momentum of a 0.15 kg ball that is moving toward home plate at a velocity of 40m/s. 2. Which has greater momentum, a 2.0kg hockey puck moving east at 2.5m/s or a 1.3kg hockey puck moving south at 3.0m/s? 3. A track athlete throws a 2kg discus into a field with a velocity of 21m/s. W ...
The Origin of the Milky Way
... where v is the body’s orbital speed • Set F = m2v2/r equal to F = GM1m2/r2 and solve for M1 ...
... where v is the body’s orbital speed • Set F = m2v2/r equal to F = GM1m2/r2 and solve for M1 ...
Homework # 2, due 17 Feb
... think the observable stars able in regions B and C would be more or less metal rich than what is actually in your model sky? 5. Consider hydrogen gas in the galactic plane. Assume the Sun is at a distance of R0 = 8 kpc from the Galactic center with the average Galactic rotational velocity at that di ...
... think the observable stars able in regions B and C would be more or less metal rich than what is actually in your model sky? 5. Consider hydrogen gas in the galactic plane. Assume the Sun is at a distance of R0 = 8 kpc from the Galactic center with the average Galactic rotational velocity at that di ...
Rigid Body Dynamics - UCSD Computer Graphics Lab
... We treat a rigid body as a system of particles, where the distance between any two particles is fixed We will assume that internal forces are generated to hold the relative positions fixed. These internal forces are all balanced out with Newton’s third law, so that they all cancel out and have no ef ...
... We treat a rigid body as a system of particles, where the distance between any two particles is fixed We will assume that internal forces are generated to hold the relative positions fixed. These internal forces are all balanced out with Newton’s third law, so that they all cancel out and have no ef ...
This worksheet uses the concepts of rotational
... Since v1 1.09v 2 , the sphere corresponding to “1” gets to the bottom first, namely the solid sphere. You can develop an argument for this which goes as follows: an amount of energy is divided (unequally) between rotational and translational terms. The less energy that goes into rotational motion, ...
... Since v1 1.09v 2 , the sphere corresponding to “1” gets to the bottom first, namely the solid sphere. You can develop an argument for this which goes as follows: an amount of energy is divided (unequally) between rotational and translational terms. The less energy that goes into rotational motion, ...
inaugural091112
... We need to create…….. Science is more creative than Art Stumble and then leap Work in the dark But all established laws must be obeyed Teach: making creators ...
... We need to create…….. Science is more creative than Art Stumble and then leap Work in the dark But all established laws must be obeyed Teach: making creators ...
40 N m
... Rolling Motion (Without Slipping) In (a), a wheel is rolling without slipping. The point P, touching the ground, is instantaneously at rest, and the center moves with velocity v. ...
... Rolling Motion (Without Slipping) In (a), a wheel is rolling without slipping. The point P, touching the ground, is instantaneously at rest, and the center moves with velocity v. ...
Rotation Torque, Rolling, & Angular Momentum
... …the basic point is that T equals the product of the PERPENDICULAR-COMPONENTS-of-r-and-F ...
... …the basic point is that T equals the product of the PERPENDICULAR-COMPONENTS-of-r-and-F ...
PROBLEM SET #9 SOLUTIONS AST142 1. Quasar luminosity
... This is only 22 AU. The X-ray variability suggests the accretion region is less than this size . If the central black hole is accreting and producing luminosity at the Eddington rate, its mass is 2e4 L = 2 × 1042 g = 109 M M= 3Gmp m2e c5 The Schwarzschild radius for a billion solar mass black hole ...
... This is only 22 AU. The X-ray variability suggests the accretion region is less than this size . If the central black hole is accreting and producing luminosity at the Eddington rate, its mass is 2e4 L = 2 × 1042 g = 109 M M= 3Gmp m2e c5 The Schwarzschild radius for a billion solar mass black hole ...
So, what`s the problem for high
... Why don’t we see a cluster of sources? Clump mass function looks like the Initial Mass Function--Maybe we see only the single brightest star. Fig. 2. The mass spectrum of IRAS 19410+2336. The clumpmass bins are [1.7(3),4], [4,6], [6,8], [8,10], and [10,25] M, and the axes are in logarithmic units. ...
... Why don’t we see a cluster of sources? Clump mass function looks like the Initial Mass Function--Maybe we see only the single brightest star. Fig. 2. The mass spectrum of IRAS 19410+2336. The clumpmass bins are [1.7(3),4], [4,6], [6,8], [8,10], and [10,25] M, and the axes are in logarithmic units. ...