Rotational Dynamics SL and Honors 2016 2017
... • Gy = normal force from ground • WL = weight ladder = 355 N, at center of mass 4.00 m up • WF = weight firefighter = 875 N, stands 6.30 m up ladder • P = normal force of wall pushing back on ladder (no frictional force on smooth wall, so no y-component here) • Ground has friction, therefore Gx and ...
... • Gy = normal force from ground • WL = weight ladder = 355 N, at center of mass 4.00 m up • WF = weight firefighter = 875 N, stands 6.30 m up ladder • P = normal force of wall pushing back on ladder (no frictional force on smooth wall, so no y-component here) • Ground has friction, therefore Gx and ...
Rigid Body Dynamics
... is called the Coriolis force. Notice that it is greatest if the velocity is perpendicular to the axis of rotation. This corresponds to motion which, for positive vbody , moves the particle further from the axis of rotation. Since the velocity required to stay above a point on a rotating body increas ...
... is called the Coriolis force. Notice that it is greatest if the velocity is perpendicular to the axis of rotation. This corresponds to motion which, for positive vbody , moves the particle further from the axis of rotation. Since the velocity required to stay above a point on a rotating body increas ...
Equilibrium of Concurrent Forces (Force Table) Objectives
... Thus a vector written as components takes the form A=Axx̂ +Ayŷ (3), where x̂ Axx̂ and ŷ are unit vectors (magnitude 1 and direction along their respective axes). Figure 5hat Figure 5 is the graphical representation of equation 3; notice that it is the same as the parallelogram in figure 2 in the s ...
... Thus a vector written as components takes the form A=Axx̂ +Ayŷ (3), where x̂ Axx̂ and ŷ are unit vectors (magnitude 1 and direction along their respective axes). Figure 5hat Figure 5 is the graphical representation of equation 3; notice that it is the same as the parallelogram in figure 2 in the s ...