BSNL JTO (Telecom)
... The candidate’s comprehension and understanding of General English shall be tested through simple exercises. Questions on knowledge of current events and of such matter of everyday observation and experience in their scientific aspects as may be expected of an educated person. Questions will also be ...
... The candidate’s comprehension and understanding of General English shall be tested through simple exercises. Questions on knowledge of current events and of such matter of everyday observation and experience in their scientific aspects as may be expected of an educated person. Questions will also be ...
Electronics Glossary
... a circuit. This makes them useful in timing circuits where they are combined with resistors to introduce a delay in the flow of current round the circuit. They are also used to smooth out varying DC currents. There are two main types of capacitor: ...
... a circuit. This makes them useful in timing circuits where they are combined with resistors to introduce a delay in the flow of current round the circuit. They are also used to smooth out varying DC currents. There are two main types of capacitor: ...
Electronic glossary
... a circuit. This makes them useful in timing circuits where they are combined with resistors to introduce a delay in the flow of current round the circuit. They are also used to smooth out varying DC currents. There are two main types of capacitor: ...
... a circuit. This makes them useful in timing circuits where they are combined with resistors to introduce a delay in the flow of current round the circuit. They are also used to smooth out varying DC currents. There are two main types of capacitor: ...
This handbell design uses four circuit configurations to drive the
... same emitter. This current is not enough to do useful work. However, it can be amplified by using another 2N4401 transistor as shown in Figure 1. The 10kΩ prevents leakage flowing from tilt sensor. With this configuration, the current was amplified to approximately 14mA. Figure 2 shows the circuit c ...
... same emitter. This current is not enough to do useful work. However, it can be amplified by using another 2N4401 transistor as shown in Figure 1. The 10kΩ prevents leakage flowing from tilt sensor. With this configuration, the current was amplified to approximately 14mA. Figure 2 shows the circuit c ...
Section F5: Darlington Circuit
... Comparing the expressions above for input resistance and current gain with those of a single transistor EF (CC) amplifier (please refer to Section D4), we can see that both of these characteristics are much larger for circuits employing the Darlington pair than for single transistor circuits. Darlin ...
... Comparing the expressions above for input resistance and current gain with those of a single transistor EF (CC) amplifier (please refer to Section D4), we can see that both of these characteristics are much larger for circuits employing the Darlington pair than for single transistor circuits. Darlin ...
PHYS3610/6610 Electronics I – Final – Thursday December 10th
... 2) Consider the circuit in the figure with R=60 , C g=8 F and C f =0.22nF . Note: this exercise does not involve any complicated complex number calculation. a) [14 points] What is value of the gain at very low frequencies? At very low frequencies the impedances of the 4R capacitors is infinite so ...
... 2) Consider the circuit in the figure with R=60 , C g=8 F and C f =0.22nF . Note: this exercise does not involve any complicated complex number calculation. a) [14 points] What is value of the gain at very low frequencies? At very low frequencies the impedances of the 4R capacitors is infinite so ...
Example 17 Use current division to determine the current i through
... So we can use a single resistor to replace the two resistors. The two 10 kΩ resistors have the same pair of nodes, hence they are in parallel. To combine the parallel resistors, we can take the reciprocal of the first resistance and take the reciprocal of the second one and add together, and then ta ...
... So we can use a single resistor to replace the two resistors. The two 10 kΩ resistors have the same pair of nodes, hence they are in parallel. To combine the parallel resistors, we can take the reciprocal of the first resistance and take the reciprocal of the second one and add together, and then ta ...
May 2002 Efficient DC/DC Converter Provides Two 15A Outputs
... The LTC1876 uses three techniques to efficiently power low voltage DSPs, ASICs and FPGAs from a low input voltage. The first technique uses an internal boost regulator to provide a separate 5V for the MOSFET gate drive. Secondly, its Burst Mode operation achieves high efficiency at light loads. Last ...
... The LTC1876 uses three techniques to efficiently power low voltage DSPs, ASICs and FPGAs from a low input voltage. The first technique uses an internal boost regulator to provide a separate 5V for the MOSFET gate drive. Secondly, its Burst Mode operation achieves high efficiency at light loads. Last ...
SMD Network Thick Film - Type MCN Series
... N.B. Take care when using these resistors close to the specified power ratings at the heat generated by a network is greater than that of equivalent individual chip resistors separately placed. ...
... N.B. Take care when using these resistors close to the specified power ratings at the heat generated by a network is greater than that of equivalent individual chip resistors separately placed. ...
DN308 - 100MHz Op Amp Features Low Noise Rail-to-Rail Performance While Consuming Only 2.5mA
... were measured to be 2.4nV/√Hz and 100MHz, respectively, with only 3.8mA supply current. This is unparalleled in the monolithic world where 5 to 6 times the supply current would be expected for similar performance. The 100MHz gain-bandwidth product of the LT6202 is maintained in this circuit because ...
... were measured to be 2.4nV/√Hz and 100MHz, respectively, with only 3.8mA supply current. This is unparalleled in the monolithic world where 5 to 6 times the supply current would be expected for similar performance. The 100MHz gain-bandwidth product of the LT6202 is maintained in this circuit because ...
Sheet (3) Transformers
... across the secondary, what is the resistance referred to the primary? If the same resistor is instead connected across the primary, what is its resistance referred to the secondary? 2) The parameters of the equivalent of a transformer, having a turns ratio of 5, are R1=0.5Ω, R2=0.021Ω, X1=3.2Ω, X2=0 ...
... across the secondary, what is the resistance referred to the primary? If the same resistor is instead connected across the primary, what is its resistance referred to the secondary? 2) The parameters of the equivalent of a transformer, having a turns ratio of 5, are R1=0.5Ω, R2=0.021Ω, X1=3.2Ω, X2=0 ...
Sheet (2) Transformers 1) A transformer has a turns ratio of 5. if a
... connected across the secondary, what is the resistance referred to the primary? If the same resistor is instead connected across the primary, what is its resistance referred to the secondary? 2) The parameters of the equivalent of a transformer, having a turns ratio of 5, are R1=0.5Ω, R2=0.021Ω, X1= ...
... connected across the secondary, what is the resistance referred to the primary? If the same resistor is instead connected across the primary, what is its resistance referred to the secondary? 2) The parameters of the equivalent of a transformer, having a turns ratio of 5, are R1=0.5Ω, R2=0.021Ω, X1= ...