AMS312.01 Lecture notes April 14, 2008 Prof. Wei Zhu
... of 36 randomly selected business days. And he found that the average daily sale for these days is $565 with a standard deviation of $150. (a) At the significance level =0.05, can Jerry conclude that the average daily sale is higher than $525? What is the p-value? (b) In order to estimate the averag ...
... of 36 randomly selected business days. And he found that the average daily sale for these days is $565 with a standard deviation of $150. (a) At the significance level =0.05, can Jerry conclude that the average daily sale is higher than $525? What is the p-value? (b) In order to estimate the averag ...
Section 7.2 Part 1 – Means and Variances of Random Variables
... Gain Communications sells aircraft communications units to both the military and the civilian markets. Next year’s sales depend on market conditions that cannot be predicted exactly. Gain follows the modern practice of using probability estimates of sales. The military division estimates its sales a ...
... Gain Communications sells aircraft communications units to both the military and the civilian markets. Next year’s sales depend on market conditions that cannot be predicted exactly. Gain follows the modern practice of using probability estimates of sales. The military division estimates its sales a ...
Estimate
... Another well known and popular estimator is the least-square estimator. If we have a sample and we think that (because of some knowledge we had before) all parameters of interest are inside the mean value of the population then least squares methods estimates by minimising the square of the differen ...
... Another well known and popular estimator is the least-square estimator. If we have a sample and we think that (because of some knowledge we had before) all parameters of interest are inside the mean value of the population then least squares methods estimates by minimising the square of the differen ...
Document
... When a sample is drawn from a normally distributed parent population, the quantity (n 1) ...
... When a sample is drawn from a normally distributed parent population, the quantity (n 1) ...
Chapter 8 Read Notes
... homework, on average. To investigate this claim, an AP Statistics class selected a random sample of 250 students from their school and asked them how long they spent doing homework during the last week. The sample mean was 10.2 hours and the sample standard deviation was 4.2 hours. Construct and int ...
... homework, on average. To investigate this claim, an AP Statistics class selected a random sample of 250 students from their school and asked them how long they spent doing homework during the last week. The sample mean was 10.2 hours and the sample standard deviation was 4.2 hours. Construct and int ...
Math 141
... Though not very exciting, we have shown that this function is concave up throughout its domain. ...
... Though not very exciting, we have shown that this function is concave up throughout its domain. ...
Section 9.1 Confidence Intervals: The Basics Point Estimator and
... AP Exam Common Error: Use these correctly! ...
... AP Exam Common Error: Use these correctly! ...
German tank problem
In the statistical theory of estimation, the problem of estimating the maximum of a discrete uniform distribution from sampling without replacement is known in English as the German tank problem, due to its application in World War II to the estimation of the number of German tanks.The analyses illustrate the difference between frequentist inference and Bayesian inference.Estimating the population maximum based on a single sample yields divergent results, while the estimation based on multiple samples is an instructive practical estimation question whose answer is simple but not obvious.