December 19, 1998
... that may be asked. If she does not know the answer, she will guess, with conditional probability of ¼ of being correct. a. What is the probability that Linda gives the correct answer to a question? ...
... that may be asked. If she does not know the answer, she will guess, with conditional probability of ¼ of being correct. a. What is the probability that Linda gives the correct answer to a question? ...
Final 2010-B Past Papers Stat
... Q(41- 47)In a study to investigate the effect of Salvia extract on blood glucose level, one group of rats was treated with the extract and the other was used as control group (not treated). The average blood glucose level of the treated (n=6 rats) was 12.4 mM with standard deviation of 6.7 mM. The ...
... Q(41- 47)In a study to investigate the effect of Salvia extract on blood glucose level, one group of rats was treated with the extract and the other was used as control group (not treated). The average blood glucose level of the treated (n=6 rats) was 12.4 mM with standard deviation of 6.7 mM. The ...
AP Statistics - Test #11 (Makeup) - 2007-2008 - edventure
... (c) z requires that you can regard your data as an SRS from the population of interest. (d) z requires that your population be Normally distributed. (e) z requires that your observations be independent. 7. Looking online (for example, at espn.go.com) you find the salaries of all 22 players for the C ...
... (c) z requires that you can regard your data as an SRS from the population of interest. (d) z requires that your population be Normally distributed. (e) z requires that your observations be independent. 7. Looking online (for example, at espn.go.com) you find the salaries of all 22 players for the C ...
Probability and Sampling Distributions
... standard deviation (standard error) would be equal to n If we divide the standard deviation we calculated on our population (s = 2.236) and divide it by the square root of our sample size ( n= 2) we would obtain 2.236 / 1.4142 = 1.58; which is exactly what we calculated our standard deviation to ...
... standard deviation (standard error) would be equal to n If we divide the standard deviation we calculated on our population (s = 2.236) and divide it by the square root of our sample size ( n= 2) we would obtain 2.236 / 1.4142 = 1.58; which is exactly what we calculated our standard deviation to ...
